Empty form data with POST

[iReachable]

Hi!

We are seeeing many users with XP experiencing empty form data issue.

Browwer = Explorer 7.0, OS = Windows Vista
Browser = Firefox 2.0.0, OS = Windows XP
Browser = Explorer 6.0, OS = Windows XP
Browser = Firefox 1.0.7, OS = Windows XP
Broswer = Opera 9.25, OS = Windows XP

The form is submitted using POST. For testing we are using XP/Explorer 6.0 client and we don't see issue at all. It is only some users who are experiencing this issue.

Any help would be appreciated. URL

http://www.ireachable. com/vote

[MarkoKlacar]

Hi,

could you please post some code that produces the output?

Cheers

Hi!

We are seeeing many users with XP experiencing empty form data issue.

Browwer = Explorer 7.0, OS = Windows Vista
Browser = Firefox 2.0.0, OS = Windows XP
Browser = Explorer 6.0, OS = Windows XP
Browser = Firefox 1.0.7, OS = Windows XP
Broswer = Opera 9.25, OS = Windows XP

The form is submitted using POST. For testing we are using XP/Explorer 6.0 client and we don't see issue at all. It is only some users who are experiencing this issue.

Any help would be appreciated. URL

http://www.ireachable. com/vote

[amanjsingh]

Hi!

We are seeeing many users with XP experiencing empty form data issue.

Browwer = Explorer 7.0, OS = Windows Vista
Browser = Firefox 2.0.0, OS = Windows XP
Browser = Explorer 6.0, OS = Windows XP
Browser = Firefox 1.0.7, OS = Windows XP
Broswer = Opera 9.25, OS = Windows XP

The form is submitted using POST. For testing we are using XP/Explorer 6.0 client and we don't see issue at all. It is only some users who are experiencing this issue.

Any help would be appreciated. URL

http://www.ireachable.com/vote

I have a similar issue...when using IE 6 variable is displayed but it sends a "" when using Firefox. Both under Windows 2000/XP

Any solutions to this problem would be highly appreciated.

Thanks
AJ

[amanjsingh]

Hi,

could you please post some code that produces the output?

Cheers

<?php

if ($_POST['methodUI'] == "1") {
$link = mysql_connect('DB details);
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
mysql_select_db('app_pw_container');
$query="SELECT pkey_app_name FROM main_up";
$result=mysql_query($query);

echo '<form method="post" action="update.php" name="form2">';
echo "<table>";
echo '<tr><td>App Name:';
echo '<select name="appName"><option>Select Application Name</option>';

while($row=mysql_fetch_array($result)) {
echo '<option value>';
echo $row["pkey_app_name"];
echo "</option>";
}
echo '</select></td></tr>';
echo '<tr><td><label>Username: <input type="text" name="username" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Password: <input type="password" name="pass" maxlength="40"></label></td></tr>';
echo '<tr><td><input type="submit" name="update" value="Submit"></td></tr>';
echo "</table>";
echo "</form>";

}


elseif ($_POST['methodUI'] == "2") {
echo '<form method="post" action="update.php" name="form2">';
echo "<table>";
echo '<tr><td><label>App Name: <input type="text" name="appName" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Username: <input type="text" name="username" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Password: <input type="password" name="pass" maxlength="40"></label></td></tr>';
echo '<tr><td><input type="submit" name="submit" value="Submit"></td></tr>';
echo "</table>";
echo "<br>";
echo "</form>";

}

?>

I have put in the text. Basically, I am trying to populate the combobox with values from database. The other two normal text fields pass the variable value to the next page but only the combobox value isn't passed and this happens only in Firefox.

Thanks
AJ

[ronverdonk]

There is no field with the name 'methodUI' in your form. So what is it you are testing in the $_POST array? If the code shown is not all of it, show it.

Btw: statement

$link = mysql_connect('DB details);

needas a closing single quote in the connect.

Ronald

[amanjsingh]

There is no field with the name 'methodUI' in your form. So what is it you are testing in the $_POST array? If the code shown is not all of it, show it.

Btw: statement

$link = mysql_connect('DB details);

needas a closing single quote in the connect.

Ronald

Thanks for the response ronverdonk

DB details are correct.

This form is displayed on the basis of a value (methodUI) from a previous form which either sends a "1" or a "2". It is basically a dropdown list where user selects on of the two choices. Based on that, on the next page, respective form is showed.

This is working fine in IE but not in FF.

<form method="post" action="inputform.php" name="forminput">
<table>
<tr>
<td>Select Method: </td>

<td>
<select name="methodUI">
	<option value="1">Update Current Application Details</option>
	<option value="2">Insert New Application Details</option>
</select>
</td>
</tr>

<tr>
<td>
<input type="submit" name"submitip" value="Submit">
</td>
</tr>
</table>
</form>

Much appreciate your help.

Best,
AJ

[ronverdonk]

Thius application runs fine in both IE and FF, except for a minor error in statement

<input type="submit" name"submitip" value="Submit">

where you forgot the '=' .
I'll show you what I did: took your code and changed the action to b.php.
So here is your code[php]<form method="post" action="b.php" name="forminput ">
<table>
<tr>
<td>Select Method: </td>

<td>
<select name="methodUI" >
<option value="1">Updat e Current Application Details</option>
<option value="2">Inser t New Application Details</option>
</select>
</td>
</tr>

<tr>
<td>
<input type="submit" name="submitip" value="Submit">
</td>
</tr>
</table>
</form>[/php]
and here is the code for b.php:[php]<?php
echo '<pre>'; print_r($_POST) ;
?>[/php]
Running the program in IE and FF, selection the 2nd option and submitting results in b.php being executed and the results are:

Array
(
    [methodUI] => 2
    [submitip] => Submit
)

Ronald

[amanjsingh]

Thius application runs fine in both IE and FF, except for a minor error in statement

<input type="submit" name"submitip" value="Submit">

where you forgot the '=' .
I'll show you what I did: took your code and changed the action to b.php.
So here is your code[php]<form method="post" action="b.php" name="forminput ">
<table>
<tr>
<td>Select Method: </td>

<td>
<select name="methodUI" >
<option value="1">Updat e Current Application Details</option>
<option value="2">Inser t New Application Details</option>
</select>
</td>
</tr>

<tr>
<td>
<input type="submit" name="submitip" value="Submit">
</td>
</tr>
</table>
</form>[/php]
and here is the code for b.php:[php]<?php
echo '<pre>'; print_r($_POST) ;
?>[/php]
Running the program in IE and FF, selection the 2nd option and submitting results in b.php being executed and the results are:

Array
(
    [methodUI] => 2
    [submitip] => Submit
)

Ronald

Ronald, wow. you take a lot of effort. I am really amazed. :)

I can very well get the output of methodUI to the next page where using methodUI value I will create a form depending on the value of methodUI. I can very well get to the part where methodUI is being passed successfully and the appropriate form is being generated on the next level. But for

methodUI=="1"

I have a dropdown list from database. If you see the code below, there is a dropdown list in the if section where methodUI=="1". the second section works fine but in the first section when i select the dropdown value and hit Submit, it does not output the value from the dropdown list. So, this is not about methodUI 's value being passed or not, it is being passed. Problem is with the <select> I think.

<?php

if ($_POST['methodUI'] == "1") {
echo '<form method="post" action="update.php" name="form2">';

$link = mysql_connect('DB Details');
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
mysql_select_db('app_pw_container');
$query="SELECT pkey_app_name FROM main_up";
$result=mysql_query($query);

echo "<table>";
echo '<tr><td>App Name:';
echo '<select name="appName" id="appNameID"><option>Select Application Name</option>';

while($row=mysql_fetch_array($result)) {
echo '<option value>';
echo $row["pkey_app_name"];
echo "</option>";
}
echo '</select></td></tr>';
echo '<tr><td><label>Username: <input type="text" name="username" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Password: <input type="password" name="pass" maxlength="40"></label></td></tr>';
echo '<tr><td><input type="submit" name="update" value="Submit"></td></tr>';
echo "</table>";
echo "</form>";

}


elseif ($_POST['methodUI'] == "2") {
echo '<form method="post" action="update.php" name="form2">';
echo "<table>";
echo '<tr><td><label>App Name: <input type="text" name="appName" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Username: <input type="text" name="username" maxlength="40"></label></td></tr>';
echo '<tr><td><label>Password: <input type="password" name="pass" maxlength="40"></label></td></tr>';
echo '<tr><td><input type="submit" name="submit" value="Submit"></td></tr>';
echo "</table>";
echo "<br>";
echo "</form>";

}

?>

Also pasting the last update.php

<?php

$appname = $_POST['appName'];
$uname = $_POST['username'];
$passw = $_POST['pass'];

echo var_dump($appname);
echo var_dump($uname);
echo var_dump($passw);
 ?>

I don't know if I am clear yet or not. Feel free to curse or shout if I am not. :)

Best,
AJ

[amanjsingh]

Thius application runs fine in both IE and FF, except for a minor error in statement

<input type="submit" name"submitip" value="Submit">

where you forgot the '=' .
I'll show you what I did: took your code and changed the action to b.php.
So here is your code[php]<form method="post" action="b.php" name="forminput ">
<table>
<tr>
<td>Select Method: </td>

<td>
<select name="methodUI" >
<option value="1">Updat e Current Application Details</option>
<option value="2">Inser t New Application Details</option>
</select>
</td>
</tr>

<tr>
<td>
<input type="submit" name="submitip" value="Submit">
</td>
</tr>
</table>
</form>[/php]
and here is the code for b.php:[php]<?php
echo '<pre>'; print_r($_POST) ;
?>[/php]
Running the program in IE and FF, selection the 2nd option and submitting results in b.php being executed and the results are:

Array
(
    [methodUI] => 2
    [submitip] => Submit
)

Ronald

I just tried your way on the second form which has appName...
Please note that the appName is not being passed at all in FF.

Array
(
    [appName] => 
    [username] => fdghdhd
    [pass] => dgdgh
    [update] => Submit
)

Whereas in IE, the output was -

Array
(
    [appName] => testing_gendb
    [username] => fgfdgf
    [pass] => cvcv
    [update] => Submit
)

[ronverdonk]

Try this one for row 19:
[php]
echo '<option value="'.$row['pkey_app_name'].'">'.$row["pkey_app_n ame"].'</option>';[/php]
Ronald

[amanjsingh]

Try this one for row 19:
[php]
echo '<option value="'.$row['pkey_app_name'].'">'.$row["pkey_app_n ame"].'</option>';[/php]
Ronald

Works like a charm. :)

Why was I missing this?

Thanks a lot Ronald.

Best,
AJ

[ronverdonk]

Works like a charm. :)

Why was I missing this?

Thanks a lot Ronald.

Best,
AJ

Being awake (possibly)?
Anyway, great it works. See you again.

Ronald