copy of object is a reference in PHP5

[groups2@reenie.org]

Can someone please explain the results below
We switched to PHP 5
if I make a copy of an object, and then change the variable inside the
object the change is reflected in the copy.

Either the copy is a reference to the object or the variable inside
the object is a static variable, I'm not sure what is going on, but It
doesn't seem like it should be doing that. Is that because of a
setting on the server or something ?

<?


$label=new myObj();
$label->settext('the text');

$copy=$label;
print_r($copy);
$label->settext('diffe rent text');
print_r($copy);




class myObj{
var $text;
function settext($text){
$this->text=$text;
}

}

?>
results:
myObj Object
(
[text] =the text
)
myObj Object
(
[text] =different text
)

[JustinCarmony]

Re: copy of object is a reference in PHP5

On Oct 25, 11:50 am, grou...@reenie. org wrote:

Can someone please explain the results below
We switched to PHP 5
if I make a copy of an object, and then change the variable inside the
object the change is reflected in the copy.
>
Either the copy is a reference to the object or the variable inside
the object is a static variable, I'm not sure what is going on, but It
doesn't seem like it should be doing that. Is that because of a
setting on the server or something ?
>
<?
>
$label=new myObj();
$label->settext('the text');
>
$copy=$label;
print_r($copy);
$label->settext('diffe rent text');
print_r($copy);
>
class myObj{
var $text;
function settext($text){
$this->text=$text;
}
>
}
>
?>
results:
myObj Object
(
[text] =the text
)
myObj Object
(
[text] =different text
)

All objects in PHP 5, if I'm not mistaken, are always passed by
reference. Example:
<?php

class MyClass
{
public $myVar;

function __construct()
{
$this->myVar = 1;
}
}

$class1 = new MyClass();

$class2 = $class1;

$class1->myVar = 2;

echo $class2->myVar; // Outputs 2

?>

If you want to make a copy of an object, so its a new object and not a
reference is to use the clone keyword like this:

<?

class MyClass
{
public $myVar;

function __construct()
{
$this->myVar = 1;
}
}

$class1 = new MyClass();

$class2 = clone $class1;

$class1->myVar = 2;

echo $class2->myVar;

?>

You can also explicitly code what is to happen when an object is
cloned by using the __clone() class function. You can read more here:

http://us3.php.net/manual/en/language.oop5.cloning.php

Carmony

[Thomas Hamacher]

Re: copy of object is a reference in PHP5

groups2@reenie. org schrieb:

On Oct 25, 2:05 pm, JustinCarmony <carm...@gmail. comwrote:

>You can also explicitly code what is to happen when an object is
>cloned by using the __clone() class function.

$label=new geocellobj();
$label->setalign('righ t');

array($label->settext('uniqu e test'), $label->settext('diffe rent
text));

I don't think cloning will help me.

Well, just clone the objects before storing them into the array:

array(clone $label->settext(...) , ...)

[groups2@reenie.org]

Re: copy of object is a reference in PHP5

On Oct 25, 6:17 pm, Thomas Hamacher <da...@nurfuers pam.dewrote:

grou...@reenie. org schrieb:
>

On Oct 25, 2:05 pm, JustinCarmony <carm...@gmail. comwrote:

You can also explicitly code what is to happen when an object is
cloned by using the __clone() class function.

$label=new geocellobj();
$label->setalign('righ t');
array($label->settext('uniqu e test'), $label->settext('diffe rent
text));
I don't think cloning will help me.

>
Well, just clone the objects before storing them into the array:
>
array(clone $label->settext(...) , ...)

Ok thanks that works great.