update database entries

[backups2007]

Say for example, I want to add 50 more books to a database of 100 books. How could I do it using the Update method? It is for the inventory module of the system that I'm working on.

Please help. Thanks.

[t0m66]

If you prefer using the UPDATE ... SET style method, MySQL has an answer, the INSERT ... SET method.

INSERT INTO tablename
SET colname = value, colname = value, ...

http://dev.mysql.com/doc/refman/5.0/en/insert.html

[backups2007]

If you prefer using the UPDATE ... SET style method, MySQL has an answer, the INSERT ... SET method.

INSERT INTO tablename
SET colname = value, colname = value, ...

http://dev.mysql.com/doc/refman/5.0/en/insert.html

Thanks for this but I was asking how to add values to an existing value in the database.

for example, can i do this?

UPDATE tablename SET quantity = quantity+'$qty'

[webandwe]

Hi,

I am assuming your are not working with images and only letters and your book has a ID Example Book_ID just to keep track of them:

We can do this with 3 pages.

1. form.html
2. update.php
3 updated.php

1. form.html

First make a html form so bring up the book we want to update:

[HTML]
<form id="form1" name="form1" method="post" action="http://www.location.co m/update.php">
<label>
<input name="book" type="text" id="book" />
</label>
<p>
<label>
<input type="submit" name="Submit" value="Submit" />
</label>
</p>
</form>
[/HMTL]


2. Update.php

[PHP]
<?

$book=$_POST['book']; ////////Get id number or book name from the html form

#Connect to Database ( Change all the stuff that has _ Example; Your_DB.

$con = mysql_connect(" localhost","you rDBusername","y ourDBpassword") ;

if (!$con)

{

die('Could not connect: ' . mysql_error());

}mysql_select_d b("Your_databas e_name", $con); #database name

$query="SELECT * FROM Your_Table WHERE Book_ID_no='$bo ok'"; #database name and book to update

$result=mysql_q uery($query);

$num=mysql_numr ows($result);

mysql_close();


# Get all the details from the Database for the book you want to up date. PLease note you must write every row you have for the particular table otherwise the update will not work

$i=0;

while ($i < $num) {

$book_id_no=mys ql_result($resu lt,$i,"book_id_ no");
$title=mysql_re sult($result,$i ,"title");
$writer=mysql_r esult($result,$ i,"writer");
$info=mysql_res ult($result,$i, "info");

?>


<form action="http://www.location.co m.to/updated.php" method="post">
<input name="book" type="hidden" id="book" value="<? echo"$book_ID_N o "?>" /> <!-- Hide this cause we don't want anyone updating the book name or id that we work with to update otherwise if someone change the id/book name it will no longer be updateble-->
<input type="text" name="ud_title" value="<? echo "$title"?>" />
<input type="text" name="ud_writer " value="<? echo "$writer"?> " />
<input type="text" name="ud_info" value="<? echo "$info"?>" />

<input name="submit" type="submit" value="Update" />
</form>
[/PHP]

3. Updated.php

[PHP]

<?

$$book_ID_No=$_ POST['$book_ID_No'];


$con = mysql_connect(" localhost","you rDBusername","y ourDBpassword") ;


$query="UPDATE Your_table SET title='$ud_titl e', writer='$ud_wri ter', info='$ud_info' WHERE book_id_no='$bo ok_ID_No'";
#once again make sure your write all your rows otherwise your stuff will not update. Make sure you put no spaces where there are not suppose to be and as well as for the commas:

@mysql_select_d b("divereg") or die( "Unable to select database");

mysql_query($qu ery);

mysql_close();

?>
[/PHP]

If you have any trouble feel free to post again

[webandwe]

Hi,

I am assuming your are not working with images and only letters and your book has a ID Example Book_ID just to keep track of them:

We can do this with 3 pages.

1. form.html
2. update.php
3 updated.php

1. form.html

First make a html form so bring up the book we want to update:

<form id="form1" name="form1" method="post" action="http://www.location.co m/update.php">
<label>
<input name="book" type="text" id="book" />
</label>
<p>
<label>
<input type="submit" name="Submit" value="Submit" />
</label>
</p>
</form>



2. Update.php

[PHP]
<?

$book=$_POST['book']; ////////Get id number or book name from the html form

#Connect to Database ( Change all the stuff that has _ Example; Your_DB.

$con = mysql_connect(" localhost","you rDBusername","y ourDBpassword") ;

if (!$con)

{

die('Could not connect: ' . mysql_error());

}mysql_select_d b("Your_databas e_name", $con); #database name

$query="SELECT * FROM Your_Table WHERE Book_ID_no='$bo ok'"; #database name and book to update

$result=mysql_q uery($query);

$num=mysql_numr ows($result);

mysql_close();


# Get all the details from the Database for the book you want to up date. PLease note you must write every row you have for the particular table otherwise the update will not work

$i=0;

while ($i < $num) {

$book_id_no=mys ql_result($resu lt,$i,"book_id_ no");
$title=mysql_re sult($result,$i ,"title");
$writer=mysql_r esult($result,$ i,"writer");
$info=mysql_res ult($result,$i, "info");

?>


<form action="http://www.location.co m.to/updated.php" method="post">
<input name="book" type="hidden" id="book" value="<? echo"$book_ID_N o "?>" /> <!-- Hide this cause we don't want anyone updating the book name or id that we work with to update otherwise if someone change the id/book name it will no longer be updateble-->
<input type="text" name="ud_title" value="<? echo "$title"?>" />
<input type="text" name="ud_writer " value="<? echo "$writer"?> " />
<input type="text" name="ud_info" value="<? echo "$info"?>" />

<input name="submit" type="submit" value="Update" />
</form>
[/PHP]

3. Updated.php

[PHP]

<?

$$book_ID_No=$_ POST['$book_ID_No'];


$con = mysql_connect(" localhost","you rDBusername","y ourDBpassword") ;


$query="UPDATE Your_table SET title='$ud_titl e', writer='$ud_wri ter', info='$ud_info' WHERE book_id_no='$bo ok_ID_No'";
#once again make sure your write all your rows otherwise your stuff will not update. Make sure you put no spaces where there are not suppose to be and as well as for the commas:

@mysql_select_d b("divereg") or die( "Unable to select database");

mysql_query($qu ery);

mysql_close();

?>
[/PHP]

If you have any trouble feel free to post again

[webandwe]

just let me know if this works for you, I use it for all of my stuff........

Regards
Webandwe

[backups2007]

just let me know if this works for you, I use it for all of my stuff........

Regards
Webandwe

well, i'm pretty sure that your code will work because I've used that kind of code before. but it really didn't solve my problem. I wanted to know how to add additional values in a databse.

for example, I have 100 boxes of oranges in my inventory database and I want to add 100 more. how should I do it?

could I do something like this:

$quantity=$_POST["quantity"];

$query=mysql_query(SELECT fruit_id,description,quantity FROM tblFruits WHERE description = "oranges");

if($query)
{
     $fruit_id = $row['fruit_id'];
     $description = $row['description'];
     $qty = $row['quantity'];

     $qtyplus = $qty + $quantity;

     $query2 = mysql_query("UPDATE tblFruits SET quantity = '$qtyplus'");

     if($query2)
     {
          echo "update success!!!!"
     }
}
}

[webandwe]

sorry for the miss understanding.. ....


Yes, that will work.

[backups2007]

sorry for the miss understanding.. ....


Yes, that will work.

do you any other solution aside from what I posted? If so, please post it. It would help me a lot.