Hi...guys! I have a form which consists of drop down menu and radio button..I would like to output the selected value in next page by using $_POST.How can capture them?It is urgent for me,thanks for generious help
[PHP]
<?
if (isset($_SESSIO N['gmemberid'])) {
$tbl_name = "movie";
$result = mysql_query(spr intf('SELECT name,classifica tion,screeningT ime FROM %s
LIMIT 7', $tbl_name)) or die('Cannot execute query.');
//$numrow = mysql_num_rows( $result);
while ($rows = mysql_fetch_ass oc($result)) {
echo '<table width="100%" border="0"><tr> <td height="68">
<table width="100%" height="47" border="0">
-----------------------------------------<br>';
echo '<strong>' . $rows['name'] . ' (' . $rows['classification '] . ')
<br></strong>';
foreach (explode(',', $rows['screeningTime']) as $time) { ?>
<label>
<input type="radio" name="time[<?php echo $rows['name']; ?>]"
title ="screening time" value="<?php echo $time; ?>">
<?php echo $time; ?> & nbsp;
</label>
<?php } ?>
<?
}
}
?>
[/PHP]
Code:
<select name="rNumber" title="number of ticket"> <option selected>Select</option> <option>01</option> <option>02</option> <option>03</option> <option>04</option> <option>05</option> <option>06</option> </select>
[PHP]
<?
if (isset($_SESSIO N['gmemberid'])) {
$tbl_name = "movie";
$result = mysql_query(spr intf('SELECT name,classifica tion,screeningT ime FROM %s
LIMIT 7', $tbl_name)) or die('Cannot execute query.');
//$numrow = mysql_num_rows( $result);
while ($rows = mysql_fetch_ass oc($result)) {
echo '<table width="100%" border="0"><tr> <td height="68">
<table width="100%" height="47" border="0">
-----------------------------------------<br>';
echo '<strong>' . $rows['name'] . ' (' . $rows['classification '] . ')
<br></strong>';
foreach (explode(',', $rows['screeningTime']) as $time) { ?>
<label>
<input type="radio" name="time[<?php echo $rows['name']; ?>]"
title ="screening time" value="<?php echo $time; ?>">
<?php echo $time; ?> & nbsp;
</label>
<?php } ?>
<?
}
}
?>
[/PHP]
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