why doesn't this work? - using && with an IF statement

[NotGiven]

session_start() ;
if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '')
echo "hello";

It doesn't throw an error it just doesn't display anything

However, this works:

session_start() ;
if (isset($HTTP_SE SSION_VARS[un']))
echo "hello";

Thanks.

[Pedro Graca]

Re: why doesn't this work? - using && with an IF statement

NotGiven wrote:[color=blue]
> session_start() ;
> if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '') echo "hello";[/color]
(-----(============== =========))
The &&'s are outside the if () !!!
[color=blue]
> It doesn't throw an error it just doesn't display anything[/color]

I think you should have received a "parse error"
[color=blue]
> However, this works:[/color]

PHP can be nice sometimes, can't it? :)
[color=blue]
> session_start() ;
> if (isset($HTTP_SE SSION_VARS[un']))[/color]
_______________ _______________ ^^^^^
I assume this is a typing mistake
[color=blue]
> echo "hello";[/color]


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[Gary L. Burnore]

Re: why doesn't this work? - using && with an IF statement

On Thu, 8 Jul 2004 20:39:39 -0400, "NotGiven" <noname@nonegiv en.net>
wrote:
[color=blue]
>session_start( );
>if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '')[/color]

Could it be that you missed the single quote before un' that you
missed here?



[color=blue]
>echo "hello";
>
>It doesn't throw an error it just doesn't display anything
>
>However, this works:
>
>session_start( );
>if (isset($HTTP_SE SSION_VARS[un']))
>echo "hello";
>
>Thanks.
>[/color]

--
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[Zurab Davitiani]

Re: why doesn't this work? - using &amp;&amp; with an IF statement

NotGiven wrote:
[color=blue]
> if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '')[/color]

Watch your parentheses and a missing single quote.

On a side note, unless you are writing this for older versions of PHP, you
should use $_SESSION array instead.

[Michael Austin]

Re: why doesn't this work? - using &amp;&amp; with an IF statement

NotGiven wrote:
[color=blue]
> session_start() ;
> if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '')
> echo "hello";
>
> It doesn't throw an error it just doesn't display anything
>
> However, this works:
>
> session_start() ;
> if (isset($HTTP_SE SSION_VARS[un']))
> echo "hello";[/color]

because the echo statment is not a part of the if statement. you need

if (isset($HTTP_SE SSION_VARS['un'])) {
echo "hello";
}[color=blue]
>
> Thanks.
>
>[/color]
you're welcome...

Michael Austin.

[Alvaro G Vicario]

Re: why doesn't this work? - using &amp;&amp; with an IF statement

*** NotGiven wrote/escribió (Thu, 8 Jul 2004 20:39:39 -0400):[color=blue]
> However, this works:
>
> session_start() ;
> if (isset($HTTP_SE SSION_VARS[un']))
> echo "hello";[/color]

It doesn't:

Parse error: parse error, expecting `']''



--
--
-- Álvaro G. Vicario - Burgos, Spain
--

[michel]

Re: why doesn't this work? - using &amp;&amp; with an IF statement


"Michael Austin" <maustin@firstd basource.com> wrote in message
news:V2nHc.7296 $p%6.6360@newss vr23.news.prodi gy.com...[color=blue]
> NotGiven wrote:
>[color=green]
> > session_start() ;
> > if (isset($HTTP_SE SSION_VARS[un']))&&($HTTP_SESS ION_VARS['un'] != '')
> > echo "hello";
> >
> > It doesn't throw an error it just doesn't display anything
> >
> > However, this works:
> >
> > session_start() ;
> > if (isset($HTTP_SE SSION_VARS[un']))
> > echo "hello";[/color]
>
> because the echo statment is not a part of the if statement. you need
>
> if (isset($HTTP_SE SSION_VARS['un'])) {
> echo "hello";
> }[color=green]
> >[/color][/color]
That's not true. You only need these parenthesis when wanting to execute
more than one line.
in this case, where only the echo is done, he don't need those