problem integration php with html

[deepakNagpal]

hi
this is deepak, just beggner of learning php, facing some problem, if anyone could help me out, i will be thankful to him. when i run this code it will so me undefined variable as : calc , val1, and val2, which i have already declared in my html file.

my html code:


<html>
<head>
<title>Calculat ion form</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>
<form method="post" ACTION="calcula te.php">
<P>Value 1: <INPUT TYPE="text" NAME="val1" SIZE=10></P>
<P>Value 2: <INPUT TYPE="text" NAME="val2" SIZE=10></P>
<P>Calculation: <br><br>

<INPUT TYPE="radio" NAME='calc' VALUE="add">add <br>
<INPUT TYPE="radio" NAME="calc" VALUE="subtract ">subtract< br>
<INPUT TYPE="radio" NAME="calc" VALUE="multiply ">multiply< br>
<INPUT TYPE="radio" NAME="calc" VALUE="divide"> divide</P>


<P><INPUT TYPE="submit" NAME="Submit" VALUE="Calulate "></P>
</form>


</body>
</html>

my php code:


<?php

if(($val1 == "") || ($val2 == "") || ($calc == "")){
header("Locatio n: http://localhost/mySite/calculate_form. html");
exit;
}

if ($calc == "add"){
$result = $val1 + $val2;

} else if ($calc == "substruct" ){
$result = $val1 - $val2;

} else if ($calc == "multiply") {
$result = $val1 * $val2;

} else if ($calc == "divide"){
$result = $val1 / $val2;
}
?>

<html>
<head>
<title>Untitl ed Document</title>
</head>

<body>
<P> The result of the claculation is: <? echo "$result"; ?> </P>
</body>
</html>

[code green]

Assuming your php code is calculate.php then you need it to read the $_POST array as set when creating your form.

<form method="post" ACTION="calculate.php">

Before this [PHP]if(($val1 == "") || ($val2 == "") || ($calc == "")){[/PHP] you need [PHP]$val1 = $_POST['var1']; $val2 = $_POST['val2']; $calc = $_POST['calc'];[/PHP]

[deepakNagpal]

HI, code green

Thanx for helping me.but i don't know why the script is not running properly, as i did as per guidence by you the php file still showing me error which i am pasting exect keywords.

Error : PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 6 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 9 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 12 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 15


I think now you r more comfortable with my problem.

thanks;

[deepakNagpal]

HI, code green

Thanx for helping me.but i don't know why the script is not running properly, as i did as per guidence by you the php file still showing me error which i am pasting exect keywords.

Error : PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 6 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 9 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 12 PHP Notice: Undefined variable: calc in C:\Inetpub\wwwr oot\mySite\calc ulate.php on line 15


I think now you r more comfortable with my problem.

thanks;

[code green]

I think you have not selected a radio button.
If a radio button is not set, it's $_POST element is not created.
Then the line

$calc = $_POST['calc'};

is pointing $calc to NULL (I think) so $calc is not defined.
Set a radio button to checked by default and it is better to test your $_POST variables first before using them.