array_join

[Shmuel]

Hi,
I'm trying to do this:

$array1 = array("a" => 1, "b" => 2);
$array2 = array("a" => 2, "b" => 4);
$array3 = array_join($arr ay1, $arra2);

Output should be:
$array3 = (
[a] => 3
[b] => 6
)

with this:
function array_join($arr ay1, $array2) {
foreach($array2 as $key => $value) {
if(array_key_ex ists($key, $array1)) {
$array1[$key] .= $array2[$key];
}
else {
$array[$key] = $array2[$key];
}
}
return $array1;
}


But it doesn't quite work. Can somebody help a bit?
It gives a warning like this:

Warning: Invalid argument supplied for foreach() in
C:\Programs\wor k\jobs\index.ph p on line 63

Shmuel.

[kingofkolt]

Re: array_join

"Shmuel" <sdg@nic.fi> wrote in message
news:R7pyc.2284 $7F6.568@reader 1.news.jippii.n et...[color=blue]
> Hi,
> I'm trying to do this:
>
> $array1 = array("a" => 1, "b" => 2);
> $array2 = array("a" => 2, "b" => 4);
> $array3 = array_join($arr ay1, $arra2);
>
> Output should be:
> $array3 = (
> [a] => 3
> [b] => 6
> )
>
> with this:
> function array_join($arr ay1, $array2) {
> foreach($array2 as $key => $value) {
> if(array_key_ex ists($key, $array1)) {
> $array1[$key] .= $array2[$key];
> }
> else {
> $array[$key] = $array2[$key];
> }
> }
> return $array1;
> }
>
>
> But it doesn't quite work. Can somebody help a bit?
> It gives a warning like this:
>
> Warning: Invalid argument supplied for foreach() in
> C:\Programs\wor k\jobs\index.ph p on line 63
>
> Shmuel.[/color]

you misspelled the variable name $array2 when you called the array_join
function ("$array2 = array_join($arr ay1,$arra2);") you spelled $array2 like
$arra2

[Chung Leong]

Re: array_join


"kingofkolt " <jessepNOSPAM@c omcast.net> wrote in message
news:dzpyc.77$H g2.19@attbi_s04 ...[color=blue]
> "Shmuel" <sdg@nic.fi> wrote in message
> news:R7pyc.2284 $7F6.568@reader 1.news.jippii.n et...[color=green]
> > Hi,
> > I'm trying to do this:
> >
> > $array1 = array("a" => 1, "b" => 2);
> > $array2 = array("a" => 2, "b" => 4);
> > $array3 = array_join($arr ay1, $arra2);
> >
> > Output should be:
> > $array3 = (
> > [a] => 3
> > [b] => 6
> > )
> >
> > with this:
> > function array_join($arr ay1, $array2) {
> > foreach($array2 as $key => $value) {
> > if(array_key_ex ists($key, $array1)) {
> > $array1[$key] .= $array2[$key];
> > }
> > else {
> > $array[$key] = $array2[$key];
> > }
> > }
> > return $array1;
> > }
> >
> >
> > But it doesn't quite work. Can somebody help a bit?
> > It gives a warning like this:
> >
> > Warning: Invalid argument supplied for foreach() in
> > C:\Programs\wor k\jobs\index.ph p on line 63
> >
> > Shmuel.[/color]
>
> you misspelled the variable name $array2 when you called the array_join
> function ("$array2 = array_join($arr ay1,$arra2);") you spelled $array2[/color]
like[color=blue]
> $arra2[/color]

Moreover, .= is string concatenation, not addition. The result would be

$array3 = (
[a] => 12
[b] => 24
)

+= is needed in this case.

function array_join($arr ay1, $array2) {
foreach($array2 as $key => $value) {
@$array1[$key] += $value;
}
return $array1;
}