PHP Notice: Undefined variable: array_var

[dmain1971]

I have a class with an empty array like so:

private $detail = array();


Then I have a function later on in the class:

function get_array_value ()
{
$detail_info = ' ';
foreach($detail as $key=>$value)
{
$detail_info .= CreateDetailEnt ry($value);
}
}

when I create an instance of my class and try to use the function get_array_value , I get this:

PHP Notice: Undefined variable: detail in blah blah file line ??

Is there a problem with creating an empty array that gets filled in later?

[dmain1971]

I have a class with an empty array like so:

private $detail = array();


Then I have a function later on in the class:

function get_array_value ()
{
$detail_info = ' ';
foreach($detail as $key=>$value)
{
$detail_info .= CreateDetailEnt ry($value);
}
}

when I create an instance of my class and try to use the function get_array_value , I get this:

PHP Notice: Undefined variable: detail in blah blah file line ??

Is there a problem with creating an empty array that gets filled in later?

--------------------------------------
I have tried declaring it public with the same result.
I tried creating it as private $detail = array(3); with the same result

What am I missing?

[dmain1971]

--------------------------------------
I have tried declaring it public with the same result.
I tried creating it as private $detail = array(3); with the same result

What am I missing?

changed it again: public $detail = array(1 => 'A');

same result. I have other arrays that work fine.

[dmain1971]

changed it again: public $detail = array(1 => 'A');

same result. I have other arrays that work fine.

Here is the rest of the error: "PHP Warning: Invalid argument supplied for foreach()", meaning the array I created.

[code green]

The $detail you are using in your function is local only to that function. To use a class variable you need to tell the class you are using the variable.
[PHP]$this->detail;[/PHP]