regular expression

[Peter Parker]

preg_match("/<some_tag >([^']*?)<\/some_tag>/", $data, $matches)
preg_match_all( "/<p>(.*?)<\/p>/", $matches[1], $paragraphs);

foreach ($paragraphs[0] as $paragraph) {
$content=$conte nt.$paragraph;
}

The above code only works if <pis the first tag under <some_tag>. i.e,
works with

<some_tag >
<p>blah</p>
</some_tag>

but not with

<some_tag >
<some_other_tag >blah</some_other_tag>
<p>blah</p>
</some_tag>


How could I make the code works regardless of the position of <punder
<some_tag>? Thank you.

[Jerry Stuckle]

Re: regular expression

Peter Parker wrote:

preg_match("/<some_tag >([^']*?)<\/some_tag>/", $data, $matches)
preg_match_all( "/<p>(.*?)<\/p>/", $matches[1], $paragraphs);
>
foreach ($paragraphs[0] as $paragraph) {
$content=$conte nt.$paragraph;
}
>
The above code only works if <pis the first tag under <some_tag>. i.e,
works with
>
<some_tag >
<p>blah</p>
</some_tag>
>
but not with
>
<some_tag >
<some_other_tag >blah</some_other_tag>
<p>blah</p>
</some_tag>
>
>
How could I make the code works regardless of the position of <punder
<some_tag>? Thank you.
>
>

Try alt.html. This isn't a PHP problem.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===

[Curtis]

Re: regular expression

Jerry Stuckle wrote:

Peter Parker wrote:

>preg_match("/<some_tag >([^']*?)<\/some_tag>/", $data, $matches)
>preg_match_all ("/<p>(.*?)<\/p>/", $matches[1], $paragraphs);
>>
>foreach ($paragraphs[0] as $paragraph) {
> $content=$conte nt.$paragraph;
> }
>>
>The above code only works if <pis the first tag under <some_tag>.
>i.e, works with
>>
><some_tag >
> <p>blah</p>
> </some_tag>
>>
>but not with
>>
><some_tag >
> <some_other_tag >blah</some_other_tag>
> <p>blah</p>
></some_tag>
>>
>>
>How could I make the code works regardless of the position of <p>
>under <some_tag>? Thank you.
>>
>>

>
Try alt.html. This isn't a PHP problem.
>

How is it not a PHP problem? The OP is asking about using regex in PHP.

Anyway, @OP: You might be able to get what you're after with one
regex. Check out the print_r output to figure out what you need, and
if it works:

$data = '<div>Foo bar <p><em>baz</em></pIshmael</div>';

// use a different delimiter when / occurs, to avoid
// unnecessary escaping
$re = '%<([\w.:-]+)[^<>]*>(.*?<p[^<>]*>(.*?)</p>.*?)</\1>%i';

preg_match_all( $re, $data, $matches);

print_r($matche s);

--
Curtis, http://dyersweb.com

[Jerry Stuckle]

Re: regular expression

Curtis wrote:

Jerry Stuckle wrote:

>Peter Parker wrote:

>>preg_match( "/<some_tag >([^']*?)<\/some_tag>/", $data, $matches)
>>preg_match_al l("/<p>(.*?)<\/p>/", $matches[1], $paragraphs);
>>>
>>foreach ($paragraphs[0] as $paragraph) {
>> $content=$conte nt.$paragraph;
>> }
>>>
>>The above code only works if <pis the first tag under <some_tag>.
>>i.e, works with
>>>
>><some_tag >
>> <p>blah</p>
>> </some_tag>
>>>
>>but not with
>>>
>><some_tag >
>> <some_other_tag >blah</some_other_tag>
>> <p>blah</p>
>></some_tag>
>>>
>>>
>>How could I make the code works regardless of the position of <p>
>>under <some_tag>? Thank you.
>>>
>>>

>>
>Try alt.html. This isn't a PHP problem.
>>

>
How is it not a PHP problem? The OP is asking about using regex in PHP.
>
Anyway, @OP: You might be able to get what you're after with one regex.
Check out the print_r output to figure out what you need, and if it works:
>
$data = '<div>Foo bar <p><em>baz</em></pIshmael</div>';
>
// use a different delimiter when / occurs, to avoid
// unnecessary escaping
$re = '%<([\w.:-]+)[^<>]*>(.*?<p[^<>]*>(.*?)</p>.*?)</\1>%i';
>
preg_match_all( $re, $data, $matches);
>
print_r($matche s);
>
--
Curtis, http://dyersweb.com

Yep, you're right - I misread the question. Sorry.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===