paging like google

[khalidbaloch]

can any one help me creating a dynamic pagination script for non-sql entries
i made this simple paging script

<?php
//Show Result Per Page
$ResultPerPage=10;
//Total Result Availaible
$TotalResults =1000;
//calculate how many pages will be created
$TotalPages = $TotalResults / $ResultPerPage;
$TotalPages = round($TotalPages,0);
$c = 0;
echo "<br>";

while($c<$TotalPages){

$page = $c + 1;
if($_REQUEST['page']==$page){
echo "[$page]";
}
else{
echo "<a href=?page=$page>[$page] </a>";
}
$c = $c+1;
}
echo "<br>".$TotalResults." Pages in total".$TotalPages."<br>";
?>

it displays all the following:

[1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15] [16] [17] [18] [19] [20] [21] [22] [23] [24] [25] [26] [27] [28] [29] [30] [31] [32] [33] [34] [35] [36] [37] [38] [39] [40] [41] [42] [43] [44] [45] [46] [47] [48] [49] [50] [51] [52] [53] [54] [55] [56] [57] [58] [59] [60] [61] [62] [63] [64] [65] [66] [67] [68] [69] [70] [71] [72] [73] [74] [75] [76] [77] [78] [79] [80] [81] [82] [83] [84] [85] [86] [87] [88] [89] [90] [91] [92] [93] [94] [95] [96] [97] [98] [99] [100]
1000 Pages in total100

Can anyone help me to shorten the list of displaying page links? I want to do some like this:

[1 ][2] [3] [4][ 5] [6 ][7 ][8][ 9] [10]

and if the vistor is looking the page no 9 it should look like this

[10][11][12][13][14][15][16][17][18][19]

in short only last ten page links should be displayed instead all of 100 pages

i have searched the web and found many paging script but all of theme was for mysql

[b1randon]

can any one help me creating a dynamic pagination script for non-sql entries
i made this simple paging script

<?php
//Show Result Per Page
$ResultPerPage=10;
//Total Result Availaible
$TotalResults =1000;
//calculate how many pages will be created
$TotalPages = $TotalResults / $ResultPerPage;
$TotalPages = round($TotalPages,0);
$c = 0;
echo "<br>";

while($c<$TotalPages){

$page = $c + 1;
if($_REQUEST['page']==$page){
echo "[$page]";
}
else{
echo "<a href=?page=$page>[$page] </a>";
}
$c = $c+1;
}
echo "<br>".$TotalResults." Pages in total".$TotalPages."<br>";
?>

it displays all the following:

[1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13] [14] [15] [16] [17] [18] [19] [20] [21] [22] [23] [24] [25] [26] [27] [28] [29] [30] [31] [32] [33] [34] [35] [36] [37] [38] [39] [40] [41] [42] [43] [44] [45] [46] [47] [48] [49] [50] [51] [52] [53] [54] [55] [56] [57] [58] [59] [60] [61] [62] [63] [64] [65] [66] [67] [68] [69] [70] [71] [72] [73] [74] [75] [76] [77] [78] [79] [80] [81] [82] [83] [84] [85] [86] [87] [88] [89] [90] [91] [92] [93] [94] [95] [96] [97] [98] [99] [100]
1000 Pages in total100

Can anyone help me to shorten the list of displaying page links? I want to do some like this:

[1 ][2] [3] [4][ 5] [6 ][7 ][8][ 9] [10]

and if the vistor is looking the page no 9 it should look like this

[10][11][12][13][14][15][16][17][18][19]

in short only last ten page links should be displayed instead all of 100 pages

i have searched the web and found many paging script but all of theme was for mysql

[PHP]
$start = $c;
while($c<$Total Pages && $c<($start+10)) {
$page = $c + 1;
if($_REQUEST['page']==$page){
echo "[$page]";
}
else{
echo "<a href=?page=$pag e>[$page] </a>";
}
$c = $c+1;
}
[/PHP]
That should do ya.

[tejasonduty]

what if I want to have output like [1][2][3][4][5] [6] [7][8][9][10][11] Where current page is 6 and I want page to show 5 page back and 5 page forward/

[smdf]

Can you please telll me what $c stands for. Is that representing the current page number? Also, I more or less have this same code belong but I definately have the same problem. Its paginating 82 pages and I only want to show 10 at a time. I'm using a for loop. I see you have $start but I dont see where and how you are using it effectively in the code you provided. Can you explain how you are using the $start variable in a little bit more detial or re-write the entire script. I need this to code write for my job and I'm pulling my hair out over here.

[PHP]
$start = $c;
while($c<$Total Pages && $c<($start+10)) {
$page = $c + 1;
if($_REQUEST['page']==$page){
echo "[$page]";
}
else{
echo "<a href=?page=$pag e>[$page] </a>";
}
$c = $c+1;
}
[/PHP]
That should do ya.

[ronverdonk]

smdf: you are not seriously 'suggesting' that b1randon re-writes his code for you!

Can you explain how you are using the $start variable in a little bit more detial or re-write the entire script. I need this to code write for my job and I'm pulling my hair out over here.

This is not a coding factory but a forum where programmers help programmers.

And if you are a PHP programmer you can work out how the variables $c and $start are used. It is not that difficult to see.

moderator

[smdf]

I can figure out how $c is being used. I'm just trying to figure out how to offset my paginating links without using PEAR. If he doesnt want to retype , cool, but I still don't see how $start is being used although I understand what its for. If he didn't need to explain $start then this forum wouldn't need to exist. If everyone knew how to use $start then then would have already knew the problem to offsetting paginating links.

smdf: you are not seriously 'suggesting' that b1randon re-writes his code for you!
This is not a coding factory but a forum where programmers help programmers.

And if you are a PHP programmer you can work out how the variables $c and $start are used. It is not that difficult to see.

moderator

[smdf]

what if I want to have output like [1][2][3][4][5] [6] [7][8][9][10][11] Where current page is 6 and I want page to show 5 page back and 5 page forward/

Hey, I just figured out my own problem and did exactly what you are looking for. You have to change the variable you are passing in the URL from the ones I am dealing with but here is how I went about it with a switch statement.



<?php
switch(TRUE){
case ($c <= 10):
if ($num_pages > 10 ) {
$stop = $i + 10;}
else {
$stop = $num_pages; }

for ($i=1; $i <= $stop; $i++)
{
if($i == $c)
{echo ($i." ");}
else
{
$urlquery = "q=".urlencode( $q)."&ist=".url encode($ist)."& pt=".urlencode( $pt)."&b=".urle ncode($b)."&d=" .urlencode($d). "&k=".urlencode ($k)."&pr=".url encode($pr)."&o =".urlencode($o )."&s=".urlenco de($s)."&c=".ur lencode($i) ."&u=".urlencod e($u);

echo("<a href=\"$PHP_SEL F?$urlquery\"> [$i] </a> ");
}
}
break;
case ( ($c >= 11) && ($c < ($num_pages - 5) ) ): //condition is met when the current pages is between page 10 and 5 pages prior to end of data
$stop = $c + 5;

for ($i= ($c - 4); $i <= $stop; $i++)
{
if($i == $c)
{echo ($i." ");}
else
{
$urlquery = "q=".urlencode( $q)."&ist=".url encode($ist)."& pt=".urlencode( $pt)."&b=".urle ncode($b)."&d=" .urlencode($d). "&k=".urlencode ($k)."&pr=".url encode($pr)."&o =".urlencode($o )."&s=".urlenco de($s)."&c=".ur lencode($i) ."&u=".urlencod e($u);

echo("<a href=\"$PHP_SEL F?$urlquery\"> [$i] </a> ");
}
}
break;
case ( ($c >= 11) && ($c >= ($num_pages - 5) ) ): //condition is met when the current page is less than 5 pages away from end of data
$stop = ($num_pages - c);

for ($i= ($c - 5); $i <= $stop; $i++)
{
if($i == $c)
{echo ($i." ");}
else
{
$urlquery = "q=".urlencode( $q)."&ist=".url encode($ist)."& pt=".urlencode( $pt)."&b=".urle ncode($b)."&d=" .urlencode($d). "&k=".urlencode ($k)."&pr=".url encode($pr)."&o =".urlencode($o )."&s=".urlenco de($s)."&c=".ur lencode($i) ."&u=".urlencod e($u);

echo("<a href=\"$PHP_SEL F?$urlquery\"> [$i] </a> ");
}
}
break;
}

. If you have any questions about my script don't be shy with the questions. I don't mind helping other's out. I hope this helps.