variable problem...

[os2]

hi

in bd.php i do:

<?php

$serveur = "localhost" ;
$utilisateur = "root";
$motDePasse = "";
$base = "laboiteapr og";
$link = "";

function connectionbd()
{
//ouvre une connection
$link = mysql_connect($ serveur, $utilisateur, $motDePasse);
mysql_select_db ($base) or die("Connexion ratée");
}
?>

don't get error


in news.php i do:

<?php

include("bd.php ");
....
?>
in news.php i get this error:

Undefined variable: serveur
Undefined variable: utilisateur
Undefined variable: motDePasse
Undefined variable: base
....

any idea to resolve that?

[Chris Hope]

Re: variable problem...

os2 wrote:
[color=blue]
> in bd.php i do:
>
> <?php
>
> $serveur = "localhost" ;
> $utilisateur = "root";
> $motDePasse = "";
> $base = "laboiteapr og";
> $link = "";
>
> function connectionbd()
> {
> //ouvre une connection
> $link = mysql_connect($ serveur, $utilisateur, $motDePasse);
> mysql_select_db ($base) or die("Connexion ratée");
> }
> ?>
>
> don't get error
>
>
> in news.php i do:
>
> <?php
>
> include("bd.php ");
> ...
> ?>
> in news.php i get this error:
>
> Undefined variable: serveur
> Undefined variable: utilisateur
> Undefined variable: motDePasse
> Undefined variable: base
> ...
>
> any idea to resolve that?[/color]

Are you calling the connectionbd() from news.php? If so, then the problem is
you are calling the function but the function has a whole load of undefined
variables in it. Although you defined $serveur, $utilisateur, $motDePasse
and $base outside the function they are not actually available inside the
function unless you pass them as parameters, eg:

function connectionbd($s erveur, $utilisateur, $motDePasse, $base)
{
//ouvre une connection
$link = mysql_connect($ serveur, $utilisateur, $motDePasse);
mysql_select_db ($base) or die("Connexion ratée");
}

In news.php these are actually already defined as you've called bd.php and
the variables are set at the beginning of the script, so you could easily
call connectiondb from any other page like so:

include('bd.php ');
connectionbd($s erveur, $utilisateur, $motDePasse, $base);

HTH

--
Chris Hope
The Electric Toolbox - http://www.electrictoolbox.com/

[Kelly Thompson]

Re: variable problem...

On Tue, 27 Apr 2004 14:45:37 +1200
Chris Hope <chris@electric toolbox.com> wrote:
[color=blue]
> os2 wrote:
> [color=green]
> > in bd.php i do:
> >
> > <?php
> >
> > $serveur = "localhost" ;
> > $utilisateur = "root";
> > $motDePasse = "";
> > $base = "laboiteapr og";
> > $link = "";
> >
> > function connectionbd()
> > {
> > //ouvre une connection
> > $link = mysql_connect($ serveur, $utilisateur, $motDePasse);
> > mysql_select_db ($base) or die("Connexion ratée");
> > }
> > ?>
> >
> > don't get error
> >
> >
> > in news.php i do:
> >
> > <?php
> >
> > include("bd.php ");
> > ...
> > ?>
> > in news.php i get this error:
> >
> > Undefined variable: serveur
> > Undefined variable: utilisateur
> > Undefined variable: motDePasse
> > Undefined variable: base
> > ...
> >
> > any idea to resolve that?[/color]
>
> Are you calling the connectionbd() from news.php? If so, then the
> problem is you are calling the function but the function has a whole
> load of undefined variables in it. Although you defined $serveur,
> $utilisateur, $motDePasse and $base outside the function they are
> not actually available inside the function unless you pass them as
> parameters, eg:
>
> function connectionbd($s erveur, $utilisateur, $motDePasse, $base)
> {
> //ouvre une connection
> $link = mysql_connect($ serveur, $utilisateur, $motDePasse);
> mysql_select_db ($base) or die("Connexion ratée");
> }[/color]

Or tell the function to work with global variables

function func() {
global $x, $y, $z;
do_something($x ,$y,$z);
}