Executing PHP in a variable?

[brett]

I'm doing a file include as

<?php $content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
echo $content; ?>

In somefile.php, there is PHP code. How can I execute the code once
$content is displayed as above?

Thanks,
Brett

[Andy Hassall]

Re: Executing PHP in a variable?

On 11 Nov 2006 12:00:17 -0800, "brett" <account@cygen. comwrote:

>I'm doing a file include as
>
><?php $content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
>echo $content; ?>
>
>In somefile.php, there is PHP code. How can I execute the code once
>$content is displayed as above?

http://groups.google.co.uk/groups?q=Executing%20PHP%20in%20a%20variable

--
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http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[larry@portcommodore.com]

Re: Executing PHP in a variable?


brett wrote:

I'm doing a file include as
>
<?php $content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
echo $content; ?>
>
In somefile.php, there is PHP code. How can I execute the code once
$content is displayed as above?
>
Thanks,
Brett

You want to use eval(), here is the entry on the on-line PHP manual (a
great reference for PHP coding):

http://us3.php.net/eval

Larry

[brett]

Re: Executing PHP in a variable?

http://groups.google.co.uk/groups?q=Executing%20PHP%20in%20a%20variable

Your link doesn't seem to work.

[Andy Hassall]

Re: Executing PHP in a variable?

On 11 Nov 2006 12:28:03 -0800, "brett" <account@cygen. comwrote:

> http://groups.google.co.uk/groups?q=...20a%20variable

>
>Your link doesn't seem to work.

Works fine from here. In what way does it not seem to work?

--
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http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[brett]

Re: Executing PHP in a variable?

You want to use eval(), here is the entry on the on-line PHP manual (a

great reference for PHP coding):

I still can't get this to work. There are three files involved. The
chain starts here:

LinkGuide.php --
<a href="www.abc.c om/page1">Some Link</a(abc)

somefile.php --
Here's the link from LinkGuide:
<?php $content = file_get_conten ts(TEMPLATEPATH . '/LinkGuide.php') ;
echo $content; }
?>

header.php --
Finally, here's the two files from above:
<?php
$content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
echo eval("$content" );
?>

I get this error:
Parse error: syntax error, unexpected T_STRING in
d:\home\blog\wp-content\themes\ default\header. php(111) : eval()'d code
on line 1

Any suggestions?

Thanks again,
Brett

[Pedro Graca]

Re: Executing PHP in a variable?

brett wrote:

<?php
$content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
echo eval("$content" );

echo eval('?>' . $content);

?>

I like to think of it as if eval() evaluates its parameter /starting/ in
PHP mode. So, if your data (from somefile.php) starts with "<?php" you
need to get out of PHP mode first, then, when eval() sees "<?php" it
will enter PHP mode and execute the rest.


<?php
unset($x);
$data = '$x = 42;';
eval($data);
echo $x, "\n";

unset($x);
$data = '<?php $x = 42; ?>';
eval('?>' . $data);
echo $x, "\n";
?>

The more balanced "eval('?>' . $data . '<?php');" gives a stupid parse
error!

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If you *really* need to mail me, use the address in the Reply-To
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[brett]

Re: Executing PHP in a variable?

I like to think of it as if eval() evaluates its parameter /starting/ in

PHP mode. So, if your data (from somefile.php) starts with "<?php" you
need to get out of PHP mode first, then, when eval() sees "<?php" it
will enter PHP mode and execute the rest.

The PHP is mixed with regular content. The file actually looks like
this:

somefile.php --
Here's the link from LinkGuide:
<?php $content = file_get_conten ts(TEMPLATEPATH . '/LinkGuide.php') ;
echo $content; }
?>
Then more text here.

How can I get out of PHP mode when its mixed this way?

Thanks,
Brett

[Rudi Menter]

Re: Executing PHP in a variable?

brett:

How can I get out of PHP mode when its mixed this way?

You /are/ out immediately after the " ?" qualifier... no "mix"...

Rgds
--

[puzz]

Re: Executing PHP in a variable?

brett wrote:

I'm doing a file include as
>
<?php $content = file_get_conten ts(TEMPLATEPATH . '/somefile.php');
echo $content; ?>
>
In somefile.php, there is PHP code. How can I execute the code once
$content is displayed as above?

Why don't you just:

include( TEMPLATEPATH . '/somefile.php' );

--

http://www.phpwebdir.com

[Peter Fox]

Re: Executing PHP in a variable?

Following on from puzz's message. . .

>
>Why don't you just:
>
>include( TEMPLATEPATH . '/somefile.php' );

Is the Right Answer - (At last)

BTW the OP might also want to search the manual for "include path".
Either run time or php.ini setting options.

--
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peterfox@eminen t.demon.co.uk.n ot.this.bit.no. html
2 Tees Close, Witham, Essex.
Gravity beer in Essex <http://www.eminent.dem on.co.uk>