If Statement Problem

[bokke]

Hi,

I have a page that has several stories that run on it from a mysql
database. Right now I use this code:
<img src="Images/NewsPics/<?php echo $row["id"];?>.jpg" border="1"to
display the image.

BUT I have added a column to the database with 1 or 2 (1=has pic, 2=no
pic). I would like to use an IF STATEMENT - so that:
<?php
if (<?php echo $row["PicNumber"];?== "2") {
echo "";
} else {
echo "<img src="Images/NewsPics/<?php echo $row["id"];?>.jpg"
border="1">";
}
?>

But I can't seem to embed the <?php echo $row["PicNumber"];?within
the PHP statement.

What am I doing wrong here? Any help would be much appreciated


Thanks

[Andy Hassall]

Re: If Statement Problem

On 30 Oct 2006 10:06:04 -0800, "bokke" <micrest@gmail. comwrote:

><?php
>if (<?php echo $row["PicNumber"];?== "2") {
>echo "";
>} else {
>echo "<img src="Images/NewsPics/<?php echo $row["id"];?>.jpg"
>border="1">" ;
>}
>?>
>
>But I can't seem to embed the <?php echo $row["PicNumber"];?within
>the PHP statement.
>
>What am I doing wrong here? Any help would be much appreciated

You're already in PHP, so you don't need another <?php tag; you don't want to
be trying to print PHP code into other PHP code, it really just does not work
like that.

Surely you mean:

<?php
if ($row['PicNumber'] == '2')
{
echo '';
}
else
{
echo '<img src="Images/NewsPics/' . $row['id'] . '.jpg" border="1">';
}
?>

--
Andy Hassall :: andy@andyh.co.u k :: http://www.andyh.co.uk
http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[bokke]

Re: If Statement Problem

Hi Andy,

I had tried that before without success - but it gave me another idea -
and it worked ...

<?php
if ($row['picture'] == '1')
{
echo '<img src="Images/NewsPics/' . $row['id'] . '.jpg"
border="1">';
}

else
{
echo '';

}

?>

for some reason the other way round fails ...

thanks a lot for the help

[Michael Fesser]

Re: If Statement Problem

..oO(bokke)

>else
>{
echo '';
>
>}

You can remove this.

Micha

[Pedro Graca]

Re: If Statement Problem

["Followup-To:" header set to comp.lang.php.]
bokke wrote:

I have a page that has several stories that run on it from a mysql
database. Right now I use this code:
<img src="Images/NewsPics/<?php echo $row["id"];?>.jpg" border="1">

|-------- HTML --------||------- PHP --------||--- HTML ----|

to display the image.
>
BUT I have added a column to the database with 1 or 2 (1=has pic, 2=no
pic). I would like to use an IF STATEMENT

The only part of your code above that is PHP if the bit with the
filename. You need to make the PHP bigger.

<?php
echo '<img src="Images/NewsPics/'; // previous HTML
echo $row["id"]; // previous PHP
echo '.jpg" border="1">'; // previous HTML
?>

<?php
if (<?php echo $row["PicNumber"];?== "2") {
echo "";
} else {
echo "<img src="Images/NewsPics/<?php echo $row["id"];?>.jpg"
border="1">";
}
?>

and make your IF STATEMENT encompass all of the image

<?php // This snippet is incomplete. It does not 'work'

if ( /* something here */ ) {

echo '<img src="Images/NewsPics/';
echo $row["id"];
echo '.jpg" border="1">';

}
?>

But I can't seem to embed the <?php echo $row["PicNumber"];?within
the PHP statement.

You can't embed PHP within PHP. All the code above is PHP right now.
There is no need to "reenter" PHP mode.

<?php

if ($row["PicNumber"] == 1) {

echo '<img src="Images/NewsPics/';
echo $row["id"];
echo '.jpg" border="1">';

} else {
// no <img ...written to the browser
}
?>

Thanks

You're very welcome. Hope this helps.

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