REGEXP problem

[frizzle]

Hi there,

I'm not really experienced with regexpes etc. so that's why i come
here.
My script needs to parse the requested filename:

Imagine the filename is index_en.html
My output needs to be an array with the following:
language =en (no underscore)
file =index (no "_en")
extension =html

i created the following, but i don't know how to move on:
preg_split( '/^[a-z0-9]*(_(en|_ru))?\.[a-z0-9]{2,4}$/', $filename );

As you can see, the _en part can be left out (index.html) wich would
have to return
language =default

I hope it's clear, cause i really need to get this going!

Thanks.

Frizzle.

[Erwin Moller]

Re: REGEXP problem

frizzle wrote:

Hi there,
>
I'm not really experienced with regexpes etc. so that's why i come
here.
My script needs to parse the requested filename:
>
Imagine the filename is index_en.html
My output needs to be an array with the following:
language =en (no underscore)
file =index (no "_en")
extension =html
>
i created the following, but i don't know how to move on:
preg_split( '/^[a-z0-9]*(_(en|_ru))?\.[a-z0-9]{2,4}$/', $filename );
>
As you can see, the _en part can be left out (index.html) wich would
have to return
language =default
>
I hope it's clear, cause i really need to get this going!
>
Thanks.
>
Frizzle.

Hi,

This part
(_(en|_ru))?
matches
_en or __ru or nothing (note the double _)

I doubt that is what you want.
I expect you mean:
(_(en|ru))?
which will match
_en
_ru
nothing

Unless you want to learn regexpr (which is fun), I think it is easier to use
explode:
$filename = "blabla_en.html ";
$parts = explode(".",$fi lename);
$otherparts = explode("_",par ts[0]);

$extension = $parts[1];
$file = $otherparts[0];
if (count($otherpa rts) == 1){
$language = "Default";
} else {
$language = $otherparts[1];
}

It is more code, but easier to understand. :-)

Regards,
Erwin Moller

[John Dunlop]

Re: REGEXP problem

frizzle:

Imagine the filename is index_en.html
My output needs to be an array with the following:
language =en (no underscore)
file =index (no "_en")
extension =html

Making some assumptions (untested):

<^([^_.]*)(_([^.]*))?\.(.*)$>i

Applied to "index_en.html" :

0 = "index_en.h tml"
1 = "index"
2 = "_en"
3 = "en"
4 = "html"

Applied to "index.html ":

0 = "index.html "
1 = "index"
2 = ""
3 = ""
4 = "html"

--
Jock

[Pedro Graca]

Re: REGEXP problem

frizzle wrote:

Imagine the filename is index_en.html
My output needs to be an array with the following:
language =en (no underscore)
file =index (no "_en")
extension =html
>
i created the following, but i don't know how to move on:
preg_split( '/^[a-z0-9]*(_(en|_ru))?\.[a-z0-9]{2,4}$/', $filename );

preg_match() is your friend.

if (preg_match('/^([a-z0-9]*)(?:_(en|ru))? \.([a-z0-9]{2,4})$/', $filename, $matches)) {
$output['language'] = $matches[2];
$output['file'] = $matches[1];
$output['extension'] = $matches[3];
}


Reference: http://www.php.net/preg_match

--
File not found: (R)esume, (R)etry, (R)erun, (R)eturn, (R)eboot

[frizzle]

Re: REGEXP problem


Pedro Graca wrote:

frizzle wrote:

Imagine the filename is index_en.html
My output needs to be an array with the following:
language =en (no underscore)
file =index (no "_en")
extension =html

i created the following, but i don't know how to move on:
preg_split( '/^[a-z0-9]*(_(en|_ru))?\.[a-z0-9]{2,4}$/', $filename );

>
preg_match() is your friend.
>
if (preg_match('/^([a-z0-9]*)(?:_(en|ru))? \.([a-z0-9]{2,4})$/', $filename, $matches)) {
$output['language'] = $matches[2];
$output['file'] = $matches[1];
$output['extension'] = $matches[3];
}
>
>
Reference: http://www.php.net/preg_match
>
--
File not found: (R)esume, (R)etry, (R)erun, (R)eturn, (R)eboot

Thanks all.

I'll use John's or Pedro's way.
I am a little bit familiar with regex, but it's stuffed away somewhere
down there, and i can't reach it. Yet!!
Anyway, thanks a lot for your help!!

Frizzle.