returning references

[Justin Koivisto]

I was wondering if there was a way to return a reference of an object
that lies within another object...

<?php
class my_class_1{
var $_db=NULL;

function my_class_1(){
$this->_db=new my_class_2(TRUE );
return TRUE;
}

function get_db(&$db){
$db=&$this->db;
return TRUE;
}
}

class my_class_2{
var $var1=NULL;

function my_class_2($var ){
$this->var1=$var;
return TRUE;
}
}

$object=new my_class_1();
$object->get_db($db);
var_dump($db);
?>

This gives:
NULL

I was hoping for:
object(my_class _2)(1) {
["var1"]=>
bool(true)
}

Anyone know of a way to do this, or can you only return a copy instead
of the reference?

[Garp]

Re: returning references


"Justin Koivisto" <spam@koivi.com > wrote in message
news:ikjdc.432$ m3.16865@news7. onvoy.net...[color=blue]
> I was wondering if there was a way to return a reference of an object
> that lies within another object...
>[/color]
<sample snipped>[color=blue]
>
> Anyone know of a way to do this, or can you only return a copy instead
> of the reference?[/color]

http://uk.php.net/manual/en/language.references.return.php

Returning References
Returning by-reference is useful when you want to use a function to find
which variable a reference should be bound to. When returning references,
use this syntax:


<?php
function &find_var ($param)
{
/* ...code... */
return $found_var;
}

$foo =& find_var ($bar);
$foo->x = 2;
?>

HTH
Garp

[Justin Koivisto]

Re: returning references

Garp wrote:
[color=blue]
> "Justin Koivisto" <spam@koivi.com > wrote in message
> news:ikjdc.432$ m3.16865@news7. onvoy.net...
>[color=green]
>>I was wondering if there was a way to return a reference of an object
>>that lies within another object...[/color]
>
> <sample snipped>
>[color=green]
>>Anyone know of a way to do this, or can you only return a copy instead
>>of the reference?[/color]
>
> http://uk.php.net/manual/en/language...ces.return.php
>
> Returning References
> Returning by-reference is useful when you want to use a function to find
> which variable a reference should be bound to. When returning references,
> use this syntax:
>
> <?php
> function &find_var ($param)
> {
> /* ...code... */
> return $found_var;
> }
>
> $foo =& find_var ($bar);
> $foo->x = 2;
> ?>[/color]

Now isn't that just hallarious! I had read that page 5 times and missed
the & before the function name... (no wonder I kept getting warnings,
errors and notices)

Damn long days.... I'm goin' to the pub now. ;) Enjoy!

THANKS!

[Garp]

Re: returning references


"Justin Koivisto" <spam@koivi.com > wrote in message
news:sXjdc.435$ m3.16903@news7. onvoy.net...[color=blue]
> Garp wrote:
>[color=green]
> > "Justin Koivisto" <spam@koivi.com > wrote in message
> > news:ikjdc.432$ m3.16865@news7. onvoy.net...
> >[color=darkred]
> >>I was wondering if there was a way to return a reference of an object
> >>that lies within another object...[/color]
> >
> > <sample snipped>
> >[color=darkred]
> >>Anyone know of a way to do this, or can you only return a copy instead
> >>of the reference?[/color]
> >
> > http://uk.php.net/manual/en/language...ces.return.php
> >
> > Returning References
> > Returning by-reference is useful when you want to use a function to find
> > which variable a reference should be bound to. When returning[/color][/color]
references,[color=blue][color=green]
> > use this syntax:
> >
> > <?php
> > function &find_var ($param)
> > {
> > /* ...code... */
> > return $found_var;
> > }
> >
> > $foo =& find_var ($bar);
> > $foo->x = 2;
> > ?>[/color]
>
> Now isn't that just hallarious! I had read that page 5 times and missed
> the & before the function name... (no wonder I kept getting warnings,
> errors and notices)
>
> Damn long days.... I'm goin' to the pub now. ;) Enjoy!
>
> THANKS![/color]

It's not the world's greatest bit of syntax. 8) Glad to help.

Garp