I keep getting this error in in_array. Any ideas why?

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  • rich
    #1

    I keep getting this error in in_array. Any ideas why?

    I keep getting the error:
    Warning: in_array(): Wrong datatype for second argument on line 679
    here is the code.
    I declare and fill the array
    $specprimA = array();
    $specprimA= getspecprim($dr esstypeid);
    $primsecA=getpr imsec();

    Then I do a compare using in Array. I even put in the extra step of
    making sure I have something in the array with the is sizeof statement.

    $numcl= count($primsecA );
    for ($i=0; $i<$numcl; $i++){
    $primsec = $primsecA[$i]['primsec'];
    if (sizeof($specpr imA) >0){
    if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
    <input type="checkbox" checked tabindex="2" name="primsecid[]"
    value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
    $primsec;
    } else { ?>
    <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
    echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
    }
    } else { ?>
    <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
    echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
    }
    }?>

    This is line 679
    if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>

    Any ideas why?

    Tags: None
    • rich
      #2
      Re: I keep getting this error in in_array. Any ideas why?

      Oh here is the getspecprim() function

      function getspecprim($dr esstypeid) {
      $getQ="SELECT primsecid FROM li_dresstypepsp
      WHERE
      dresstypeid= '$dresstypeid'" ;
      $getR = pg_query($getQ) ;
      $getA= pg_fetch_all($g etR);
      return($getA);
      }

      rich wrote:
      I keep getting the error:
      Warning: in_array(): Wrong datatype for second argument on line 679
      here is the code.
      I declare and fill the array
      $specprimA = array();
      $specprimA= getspecprim($dr esstypeid);
      $primsecA=getpr imsec();
      >
      Then I do a compare using in Array. I even put in the extra step of
      making sure I have something in the array with the is sizeof statement.
      >
      $numcl= count($primsecA );
      for ($i=0; $i<$numcl; $i++){
      $primsec = $primsecA[$i]['primsec'];
      if (sizeof($specpr imA) >0){
      if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
      <input type="checkbox" checked tabindex="2" name="primsecid[]"
      value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
      $primsec;
      } else { ?>
      <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
      echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
      }
      } else { ?>
      <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
      echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
      }
      }?>
      >
      This is line 679
      if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
      >
      Any ideas why?

        Comment

        • Juliette
          #3
          Re: I keep getting this error in in_array. Any ideas why?

          rich wrote:
          Oh here is the getspecprim() function
          >
          function getspecprim($dr esstypeid) {
          $getQ="SELECT primsecid FROM li_dresstypepsp
          WHERE
          dresstypeid= '$dresstypeid'" ;
          $getR = pg_query($getQ) ;
          $getA= pg_fetch_all($g etR);
          return($getA);
          }
          >
          rich wrote:
          >I keep getting the error:
          >Warning: in_array(): Wrong datatype for second argument on line 679
          >here is the code.
          >I declare and fill the array
          >$specprimA = array();
          >$specprimA= getspecprim($dr esstypeid);
          >$primsecA=getp rimsec();
          >>
          >Then I do a compare using in Array. I even put in the extra step of
          >making sure I have something in the array with the is sizeof statement.
          >>
          >$numcl= count($primsecA );
          >for ($i=0; $i<$numcl; $i++){
          >$primsec = $primsecA[$i]['primsec'];
          >if (sizeof($specpr imA) >0){
          >if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
          ><input type="checkbox" checked tabindex="2" name="primsecid[]"
          >value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
          >$primsec;
          >} else { ?>
          ><input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
          >echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
          >}
          >} else { ?>
          > <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
          >echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
          >}
          >}?>
          >>
          >This is line 679
          >if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
          >>
          >Any ideas why?
          >

          count / sizeof on a boolean or string will return 1, so try changing the
          line above the problem line to:
          if( is_array( $specprimA ) && count( $specprimA ) 0 ) {

          Alternatively, IMHO a better solution, would be to do the checking /
          typecasting in the function.

          replace:
          return($getA);

          with something along the lines of:
          if( !is_array( $getA ) {
          return array();
          }
          else {
          return $getA;
          }

            Comment

            • rich
              #4
              Re: I keep getting this error in in_array. Any ideas why?

              Juliette that was a good idea. Thanks.

              Juliette wrote:
              rich wrote:
              Oh here is the getspecprim() function

              function getspecprim($dr esstypeid) {
              $getQ="SELECT primsecid FROM li_dresstypepsp
              WHERE
              dresstypeid= '$dresstypeid'" ;
              $getR = pg_query($getQ) ;
              $getA= pg_fetch_all($g etR);
              return($getA);
              }

              rich wrote:
              I keep getting the error:
              Warning: in_array(): Wrong datatype for second argument on line 679
              here is the code.
              I declare and fill the array
              $specprimA = array();
              $specprimA= getspecprim($dr esstypeid);
              $primsecA=getpr imsec();
              >
              Then I do a compare using in Array. I even put in the extra step of
              making sure I have something in the array with the is sizeof statement.
              >
              $numcl= count($primsecA );
              for ($i=0; $i<$numcl; $i++){
              $primsec = $primsecA[$i]['primsec'];
              if (sizeof($specpr imA) >0){
              if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
              <input type="checkbox" checked tabindex="2" name="primsecid[]"
              value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
              $primsec;
              } else { ?>
              <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
              echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
              }
              } else { ?>
              <input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
              echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
              }
              }?>
              >
              This is line 679
              if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
              >
              Any ideas why?
              >
              >
              count / sizeof on a boolean or string will return 1, so try changing the
              line above the problem line to:
              if( is_array( $specprimA ) && count( $specprimA ) 0 ) {
              >
              Alternatively, IMHO a better solution, would be to do the checking /
              typecasting in the function.
              >
              replace:
              return($getA);
              >
              with something along the lines of:
              if( !is_array( $getA ) {
              return array();
              }
              else {
              return $getA;
              }

                Comment

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