Executing another PHP page

[adriann]

Hi,
I have a section of code, whereby after satisfying certain conditions of variables,
I would like PHP to leave it's current page, and launch a different PHP page.

Sort of like if a user had clicked on a Link or a submit button.

thank you.

[ronverdonk]

As in:

[PHP]
if (condition == 'met')
header('Locatio n: new_page.php');
else {
// do whatever you need to do here
}
[/PHP]

Ronald :cool:

[adriann]

Hi Ronald,

I tried yr code suggestion but I got the old "headers already sent " error message.

Warning: Cannot modify header information - headers already sent by... blah blah blah.

Are there any other ways to perform this task?

thank you.

[phpmaet]

Hi,

This is another way for skip the current page.

[PHP]if($_POST($cond ))
{
echo '<meta http-equiv=refresh content=0;url=h ome.php>';
}[/PHP]

[Banfa]

or alternitively

[php]
if (condition == 'met')
require_once('n ew_page.php');
else {
// do whatever you need to do here
}

[/php]

[mtcyber]

For uses

header('Locatio n: new_page.php');

You can uses ob_start(); and ob_end_flush();

Example::

<?
ob_start();

.....
.....
if ($condition1)
{
header('Locatio n: new_page1.php') ;
}
.....
.....
.....
if ($condition1)
{
header('Locatio n: new_page1.php') ;
}

ob_end_flush();

?>


=============== ======

Hi Ronald,

I tried yr code suggestion but I got the old "headers already sent " error message.

Warning: Cannot modify header information - headers already sent by... blah blah blah.

Are there any other ways to perform this task?

thank you.

[skim]

using JS. This is the easiest way.

<?php
whatever your code...
if( whatever condition){
?>
<SCRIPT LANGUAGE ="JavaScript ">
window.location = "./your/file.php"
</SCRIPT>
<?php
}

Whatever yourcode....
?>
Done.