sending variable to include file

**Andrew Poelstra** · Aug 18 '06, 04:35 AM

Re: sending variable to include file

"vetchling" <vetchling@gmai l.comwrites:

Hi, I'm pretty new to php but I've been working on a site and have a
problem I can't fix, though it's probably pretty simple.
>
Basically I have an index.php file that includes a header.php file. I
attempt to pass a variable to it as follows:
<?include("head er.php?page=Hom e");?>
>
Then the header.php file contains this code:
<?php
$page = $_GET['page'];
?>
<html><head><ti tle><?$page?></title>
>
I want $page to contain the string "Home" of course, but it ends up
being nothing but an empty string.
>
Thanks in advance for your help.

You can't add ?args to an include; PHP doesn't evalutate that when
including files. (In fact, it usually never evaluates URL arguments:
that's the HTTP daemon's job.) It merely copies the contents of
header.php directly into your document (or parses equivilantly).

To do this, you need to do:

#In mypage.php you need to access $mypage_page directly.
mypage_page = "Home";
include ("mypage.php ");

I've prefixed the variable $page to avoid naming conflicts.

--
Andrew Poelstra <http://www.wpsoftware. net/projects>
To reach me by email, use `apoelstra' at the above domain.
"Do BOTH ends of the cable need to be plugged in?" -Anon.

**Geoff Muldoon** · Aug 18 '06, 05:35 AM

Re: sending variable to include file

In article <1155873472.662 698.276320@i42g 2000cwa.googleg roups.com>,
vetchling@gmail .com says...

Hi, I'm pretty new to php but I've been working on a site and have a
problem I can't fix, though it's probably pretty simple.
>
Basically I have an index.php file that includes a header.php file. I
attempt to pass a variable to it as follows:
<?include("head er.php?page=Hom e");?>

Write your header (and footer if so warranted, example included) as a
function which returns the header text with the variable embedded in it,
and pass the variable to the function.

# header_footer_f unctions.php
<?php
function print_header($t his_page) {
$text = '<html><head><t itle>'.$this_pa ge.'</title></head>';
return $text;
}
function print_footer($a uthor, $dept) {
$text = '<div>Author: .'$author.'<br />Dept: '.$dept.'</div></html>';
return $text;
}
?>

# home_page.php
<?php
include_once('h eader_footer_fu nctions.php')
echo print_header('h ome');
?>
... rest of home page
<?php
echo print_footer('S lave Driver', 'Head Office');
?>

# some_other_page .php
<?php
include_once('h eader_footer_fu nctions.php')
echo print_header('s ome other page');
?>
... rest of some other page
<?php
echo print_footer('U nderpaid', 'Underlings');
?>

Geoff M

**Chung Leong** · Aug 18 '06, 05:45 AM

Re: sending variable to include file

vetchling wrote:

Hi, I'm pretty new to php but I've been working on a site and have a
problem I can't fix, though it's probably pretty simple.
>
Basically I have an index.php file that includes a header.php file. I
attempt to pass a variable to it as follows:
<?include("head er.php?page=Hom e");?>
>
Then the header.php file contains this code:
<?php
$page = $_GET['page'];
?>
<html><head><ti tle><?$page?></title>
>
I want $page to contain the string "Home" of course, but it ends up
being nothing but an empty string.

[rant against using includes as functions]

Just wrap a function around the HTML then call it. Later on you'll find
that it gives you a lot of flexibility. So instead of a header.php and
footer.php, you have one file, interface.php:

<?php function printHeader($pa ge) { ?>
<html><head><ti tle><? echo htmlspecialchar s($page); ?></title>
<? } ?>

<?php function printFooter() { ?>
</body></html>
<? } ?>

In the different pages, you'd include this file then call the functions
at the right places:

<?php

require_once("i nterface.php");

printHeader('We lcome');

/* ... */

printFooter();

?>

**m2m tech** · Aug 18 '06, 06:55 AM

Re: sending variable to include file

Dear Matt, your Script should work, you just forgot add 'echo' which
prints your variable ...

<?php
$page = $_GET['page'];
?>
<html><head><ti tle><?php echo $page; ?></title>

vetchling wrote:

Hi, I'm pretty new to php but I've been working on a site and have a
problem I can't fix, though it's probably pretty simple.
>
Basically I have an index.php file that includes a header.php file. I
attempt to pass a variable to it as follows:
<?include("head er.php?page=Hom e");?>
>
Then the header.php file contains this code:
<?php
$page = $_GET['page'];
?>
<html><head><ti tle><?$page?></title>
>
I want $page to contain the string "Home" of course, but it ends up
being nothing but an empty string.
>
Thanks in advance for your help.
>
Matt
>

--
--------------------------------------------
m2m server software gmbh - http://www.m2m.at

**Chuck Anderson** · Aug 18 '06, 06:35 PM

Re: sending variable to include file

vetchling wrote:

Hi, I'm pretty new to php but I've been working on a site and have a
problem I can't fix, though it's probably pretty simple.
>
Basically I have an index.php file that includes a header.php file. I
attempt to pass a variable to it as follows:
<?include("head er.php?page=Hom e");?>
>
Then the header.php file contains this code:
<?php
$page = $_GET['page'];
?>
<html><head><ti tle><?$page?></title>
>
I want $page to contain the string "Home" of course, but it ends up
being nothing but an empty string.
>
Thanks in advance for your help.
>
Matt
>
>

You don't need to pass a variable to an included file, it already has
access to all variables in the includING script. It becomes part of the
script that is including it.

$page = 'Home';
include 'header.php';

Now header.php will see that $page contains 'Home'.

--
*************** **************
Chuck Anderson • Boulder, CO

http://www.CycleTourist.com

*************** **************

sending variable to include file

sending variable to include file

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