Array to simple variables assignment

[Bob Stearns]

Am I conflating PHP with another language (PERL maybe?) or can you do an
assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
to believe in the conflation theory. If there is a syntax for this,
could you please send me a manual reference for it?

[Andy Hassall]

Re: Array to simple variables assignment

On Tue, 25 Jul 2006 18:29:52 -0400, Bob Stearns <rstearns1241@c harter.net>
wrote:

>Am I conflating PHP with another language (PERL maybe?) or can you do an
>assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
>given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
>to believe in the conflation theory. If there is a syntax for this,
>could you please send me a manual reference for it?

Yes, you're closer to Perl with the first example, which is almost valid in
that language, except it'd be @array not $array.

PHP requires an extra word to do the same thing; see http://uk2.php.net/list


--
Andy Hassall :: andy@andyh.co.u k :: http://www.andyh.co.uk
http://www.andyhsoftware.co.uk/space :: disk and FTP usage analysis tool

[Noodle]

Re: Array to simple variables assignment


Bob Stearns wrote:

Am I conflating PHP with another language (PERL maybe?) or can you do an
assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
to believe in the conflation theory. If there is a syntax for this,
could you please send me a manual reference for it?

$array = array($a, $b, $c);

http://www.php.net/manual/en/function.array.php

[Bob Stearns]

Re: Array to simple variables assignment

Andy Hassall wrote:

On Tue, 25 Jul 2006 18:29:52 -0400, Bob Stearns <rstearns1241@c harter.net>
wrote:
>
>

>>Am I conflating PHP with another language (PERL maybe?) or can you do an
>>assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
>>given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
>>to believe in the conflation theory. If there is a syntax for this,
>>could you please send me a manual reference for it?

>
>
Yes, you're closer to Perl with the first example, which is almost valid in
that language, except it'd be @array not $array.
>
PHP requires an extra word to do the same thing; see http://uk2.php.net/list
>
>

Thank you.

[Bob Stearns]

Re: Array to simple variables assignment

Noodle wrote:

Bob Stearns wrote:
>

>>Am I conflating PHP with another language (PERL maybe?) or can you do an
>>assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
>>given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
>>to believe in the conflation theory. If there is a syntax for this,
>>could you please send me a manual reference for it?

>
>
$array = array($a, $b, $c);
>

http://www.php.net/manual/en/function.array.php

>

That is the opposite of what I wanted. The correct syntax, as pointed
out by Andy Hassal is:

list($a, $b, $c) = $array;

[Noodle]

Re: Array to simple variables assignment


Bob Stearns wrote:

Noodle wrote:
>

Bob Stearns wrote:

>Am I conflating PHP with another language (PERL maybe?) or can you do an
>assignment to $a, $b and $c something like ($a, $b, $c) = $array? The
>given sytax doesn't work nor does [$a, $b, $c] = $array. This leads me
>to believe in the conflation theory. If there is a syntax for this,
>could you please send me a manual reference for it?

$array = array($a, $b, $c);

http://www.php.net/manual/en/function.array.php

That is the opposite of what I wanted. The correct syntax, as pointed
out by Andy Hassal is:
>
list($a, $b, $c) = $array;

Fair Enough. I don't think I read your question correctly.