Trying to get constant from array but get literal string instead

[comp.lang.php]

[PHP]
var $filterArray = array('reverse' =IMG_FILTER_NEG ATE,
'edge highlight' =IMG_FILTER_EDG EDETECT,
'emboss' =IMG_FILTER_EMB OSS,
'gaussian blur' =IMG_FILTER_GAU SSIAN_BLUR,
'blur' =IMG_FILTER_SEL ECTIVE_BLUR,
'sketchy' =IMG_FILTER_MEA N_REMOVAL);

[/PHP]

I am trying to generate an HTML dropdown from this array, however, when
I do, the value that should go in the OPTION tag literally becomes
this:

<option value="IMG_FILT ER_EMBOSS">embo ss</OPTION>

Which is completely wrong; I want the actual constant IMG_FILTER_EMBO SS
instead, which should display as an integer within the OPTION tag.

How do I do this?

Code:

[PHP]
/**
* Generate a filter technique dropdown HTML with any additional
features to the array before display
*
* *NOTE* This method will be called outside of the $this->image
property having existence and thus will have to be used as a
placeholder to self-instantiate using $this->self
*
* @access public
* @param array $newFilterArray (optional)
* @return mixed HTML
*/
function &generateFilter Dropdown($newFi lterArray = '') { // STATIC
HTML STRING METHOD
if (!is_object($th is) || @!is_a($this,
'ImageFilterTec hniqueGenerator ')) {
$self =& new ImageFilterTech niqueGenerator( 'placeholder');
} else {
$self =& $this; // MAKE A LOCAL REFERENCE POINTER TO KEEP
CODE CONSISTENT
}
if (is_array($newF ilterArray) && @sizeof($newFil terArray) 0)
$self->setFilterArray ($newFilterArra y);
$filterArray = $self->getFilterArray ();
if (is_array($filt erArray) && @sizeof($filter Array) 0) {
$html = "<select multiple name=\"filter_t ech[]\" size=\"";
$html .= (sizeof($filter Array) 5) ? 5 : sizeof($filterA rray);
$html .= "\">\n";
foreach ($filterArray as $display =$filter) {
print_r("filter = $filter = ${$filter}<P>") ; // THIS PRODUCES
"filter = IMG_FILTER_EMBO SS =
$html .= " <option value=\"${$filt er}\"" .
$self->disp->preSelect(${$f ilter},
@array_search(a rray_values($fi lterArray), ${$filter})) . '>' .
str_replace('<' , '&lt;', str_replace('\\ ', '',
$display)) . "</option>\n";
}
$html .= "</select>\n";
}

return $html;
}
[/PHP]

Thanx
Phil

[bobzimuta]

Re: Trying to get constant from array but get literal string instead

comp.lang.php wrote:

[PHP]
var $filterArray = array('reverse' =IMG_FILTER_NEG ATE,
'edge highlight' =IMG_FILTER_EDG EDETECT,
'emboss' =IMG_FILTER_EMB OSS,
'gaussian blur' =IMG_FILTER_GAU SSIAN_BLUR,
'blur' =IMG_FILTER_SEL ECTIVE_BLUR,
'sketchy' =IMG_FILTER_MEA N_REMOVAL);
>
[/PHP]
>
I am trying to generate an HTML dropdown from this array, however, when
I do, the value that should go in the OPTION tag literally becomes
this:
>

<option value="IMG_FILT ER_EMBOSS">embo ss</OPTION>

Are you using PHP 5? Those are PHP 5 constants, and if they don't exist
the constant will be converted to that string. Just try var_dump(
IMG_FILTER_NEGA TE ); via command line or in a script to see if the
numeric value is returned. Otherwise, I'd try wrapping the constants
like the following
'reverse' =intval( IMG_FILTER_NEGA TE ),

[comp.lang.php]

Re: Trying to get constant from array but get literal string instead


bobzimuta wrote:

comp.lang.php wrote:

[PHP]
var $filterArray = array('reverse' =IMG_FILTER_NEG ATE,
'edge highlight' =IMG_FILTER_EDG EDETECT,
'emboss' =IMG_FILTER_EMB OSS,
'gaussian blur' =IMG_FILTER_GAU SSIAN_BLUR,
'blur' =IMG_FILTER_SEL ECTIVE_BLUR,
'sketchy' =IMG_FILTER_MEA N_REMOVAL);

[/PHP]

I am trying to generate an HTML dropdown from this array, however, when
I do, the value that should go in the OPTION tag literally becomes
this:

<option value="IMG_FILT ER_EMBOSS">embo ss</OPTION>

>
Are you using PHP 5? Those are PHP 5 constants, and if they don't exist
the constant will be converted to that string. Just try var_dump(
IMG_FILTER_NEGA TE ); via command line or in a script to see if the
numeric value is returned. Otherwise, I'd try wrapping the constants
like the following
'reverse' =intval( IMG_FILTER_NEGA TE ),

Thanx but I am using PHP 4.1.2 on one machine, PHP 4.3.2 on another
machine, PHP 4.3.9 on another machine and PHP 5.0.4 on another machine,
all test machines for building a portable web application product. So
I can't have anything specific to PHP 5.0+ without having to come up
with a PHP 4+ version, and I can't imagine a version for that, so I'm
scrapping the whole filter thing.

Thanx though
Phil