Using SPLIT( ) to parse HTTP_REFERER

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  • John A. Irwin
    #1

    Using SPLIT( ) to parse HTTP_REFERER

    I'm very new to PHP and am trying to figure out how to parse out a
    variable "HTTP_REFER ER". My reason for this is my site was recently
    "FEATURED" (sic) on a website called FARK.COM. Because of this I
    received over 100,000 Hits in less then one hour and it caused my host's
    server farm to crash. While I understand that I could move to a more
    robust Web Host, I would rather trap any further links from FARK and
    redirect them to a rejection page at the following URL.

    Angelfire - error 403
    http://www.angelfire.com/crazy/actualclient/farkreject.htm
    Angelfire on Lycos, established in 1995, is one of the leading personal publishing communities on the Web. Angelfire makes it easy for members to create their own blogs, web sites, get a web address (domain) and start publishing online.


    In doing this I should be able to avoid another crash and save myself
    some phenomenal bandwidth charges.

    I tried the following code to attempt to isolate the word FARK from
    HTTP_REFERER thinking that the 2nd element of the array would be FARK
    (assuming that the HTTP_REFERER = "http://www.fark.com")

    My expected output would be
    $refer_array(1) = http://www
    $refer_array(2) = fark
    $refer_array(3) = com

    However what I get is the following message
    Parse error: parse error in /refer_test.php on line 11

    Here is the Code I'm using to display the results
    -------------------------------------------------------------------------------------------
    <html>
    <head>
    <title>Untitl ed Document</title>
    <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
    </head>

    <body>
    <?php //PHP ADODB document - made with PHAkt 2.2.0
    PRINT HTTP_REFERER

    $refer_array = split(".",HTTP_ REFERER);
    foreach ( $refer_array as $item )
    print "$item<BR>" ;
    ?>
    </body>
    </html>
    ---------------------------------------------------------------------------------------------

    Any help anyone could offer would be greatly appreciated by this
    bumbling n00bie

    Thanks
    John

    Tags: None
    • Jeffrey Silverman
      #2
      Re: Using SPLIT( ) to parse HTTP_REFERER

      On Mon, 21 Jul 2003 11:45:32 -0700, John A. Irwin wrote:
      [color=blue]
      > I'm very new to PHP and am trying to figure out how to parse out a
      > variable "HTTP_REFER ER". My reason for this is my site was recently[/color]
      <snip!>[color=blue]
      > Here is the Code I'm using to display the results
      > -------------------------------------------------------------------------------------------
      > <html>
      > <head>
      > <title>Untitl ed Document</title>
      > <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
      > </head>
      >
      > <body>
      > <?php //PHP ADODB document - made with PHAkt 2.2.0 PRINT HTTP_REFERER
      >
      > $refer_array = split(".",HTTP_ REFERER); foreach ( $refer_array as $item )
      > print "$item<BR>" ;
      > ?>
      > </body>
      > </html>
      > ---------------------------------------------------------------------------------------------
      >
      > Any help anyone could offer would be greatly appreciated by this bumbling
      > n00bie
      >
      > Thanks
      > John[/color]

      First of all, HTTP_REFERER is not a reliable variable to use. However,
      ignoring that aspect, try the following code:
      <?php

      $refer_array = split("\.",$_SE RVER['HTTP_HOST']); foreach ( $refer_array as $item )
      print "$item<BR>" ;
      ?>

      You need to escape the dot "." with a backslash "\." and you also forgot
      the dollar sign "$" indicating that HTTP_REFERER is a variable --
      $HTTP_REFERER.


      later...

      --
      Jeffrey D. Silverman | jeffrey AT jhu DOT edu
      Johns Hopkins University | Baltimore, MD
      Website | http://www.wse.jhu.edu/newtnotes/

        Comment

        • Actual Client
          #3
          Re: Using SPLIT( ) to parse HTTP_REFERER

          Jeff that seemed to work just fine, Thanks for taking the time to respond.


          Jeffrey Silverman wrote:[color=blue]
          > On Mon, 21 Jul 2003 11:45:32 -0700, John A. Irwin wrote:
          >
          >[color=green]
          >>I'm very new to PHP and am trying to figure out how to parse out a
          >>variable "HTTP_REFER ER". My reason for this is my site was recently[/color]
          >
          > <snip!>
          >[color=green]
          >>Here is the Code I'm using to display the results
          >>-------------------------------------------------------------------------------------------
          >><html>
          >><head>
          >><title>Untitl ed Document</title>
          >><meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
          >></head>
          >>
          >><body>
          >><?php //PHP ADODB document - made with PHAkt 2.2.0 PRINT HTTP_REFERER
          >>
          >>$refer_arra y = split(".",HTTP_ REFERER); foreach ( $refer_array as $item )
          >> print "$item<BR>" ;
          >>?>
          >></body>
          >></html>
          >>---------------------------------------------------------------------------------------------
          >>
          >>Any help anyone could offer would be greatly appreciated by this bumbling
          >>n00bie
          >>
          >>Thanks
          >>John[/color]
          >
          >
          > First of all, HTTP_REFERER is not a reliable variable to use. However,
          > ignoring that aspect, try the following code:
          > <?php
          >
          > $refer_array = split("\.",$_SE RVER['HTTP_HOST']); foreach ( $refer_array as $item )
          > print "$item<BR>" ;
          > ?>
          >
          > You need to escape the dot "." with a backslash "\." and you also forgot
          > the dollar sign "$" indicating that HTTP_REFERER is a variable --
          > $HTTP_REFERER.
          >
          >
          > later...
          >[/color]

            Comment

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