Conditionally define a function in php

[Quinten Carlson]

Is there a way to conditionally define a function in php?

I'm trying to run a php page 10 times using the include statement, but I get
an error because my function is already defined. The docs state that a
function cannot be undefined and adding "exit" to the included page doesn't
free it up either.

Any suggestions?

B44CCD21

[CC Zona]

Re: Conditionally define a function in php

In article <9i1Qa.44068$OZ 2.8100@rwcrnsc5 4>, "Quinten Carlson" <no@no.com>
wrote:
[color=blue]
> Is there a way to conditionally define a function in php?
>
> I'm trying to run a php page 10 times using the include statement, but I get
> an error because my function is already defined.[/color]

http://php.net/require-once

--
CC

[sam]

Re: Conditionally define a function in php

if(!function_ex ists("my_functi on"))
{
//define your fumction my_function here
}
else
{
// do other stuff here
}


"Quinten Carlson" <no@no.com> wrote in message
news:9i1Qa.4406 8$OZ2.8100@rwcr nsc54...[color=blue]
> Is there a way to conditionally define a function in php?
>
> I'm trying to run a php page 10 times using the include statement, but I[/color]
get[color=blue]
> an error because my function is already defined. The docs state that a
> function cannot be undefined and adding "exit" to the included page[/color]
doesn't[color=blue]
> free it up either.
>
> Any suggestions?
>
> B44CCD21
>
>[/color]

[Quinten Carlson]

Re: Conditionally define a function in php

Thanks CC, I dropped the function into an include and require_once'd it.
Works like a charm!

B44CCD21
[color=blue]
> http://php.net/require-once
>
> --
> CC[/color]