Displaying numbers with 2 digits

[Michael]

Hi,

I have something like :
$c=$a+$b;
echo $c,

The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
How 2 ?

Thanks in advance.

Michael

[Kevin Thorpe]

Re: Displaying numbers with 2 digits

Michael wrote:[color=blue]
> Hi,
>
> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> How 2 ?[/color]

$c = $a+$b;
printf('%2u',$c );

...or..

$c = sprintf('%2u',$ a+$b);
echo $c;

[Michael Fuhr]

Re: Displaying numbers with 2 digits

"Michael" <michaperso@eas ynet.fr> writes:
[color=blue]
> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).[/color]

See the documentation for printf() and sprintf() in the PHP manual.

http://www.php.net/manual/en/ref.strings.php

http://www.php.net/manual/fr/ref.strings.php

--
Michael Fuhr

http://www.fuhr.org/~mfuhr/

[Pedro Graca]

Re: Displaying numbers with 2 digits

Michael wrote:[color=blue]
> Hi,
>
> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> How 2 ?[/color]

+ is an arithmetic operator

http://www.php.net/manual/en/language.operators.arithmetic.php

I think you want the

.. string operator

http://www.php.net/manual/en/language.operators.string.php

<?php
$as = "0";
$bs = "5";
$cs = "0";

$an = 0;
$bn = 5;
$cn = 0;

echo $as + $bs; ### 5
echo $as . $bs; ### 05
echo $bs + $cs; ### 5
echo $bs . $cs; ### 50

echo $an + $bn; ### 5
echo $an . $bn; ### 05
echo $bn + $cn; ### 5
echo $bn . $cn; ### 50
?>


Or, if I misunderstood you, use the number_format() or printf()
functions

http://www.php.net/number_format

http://www.php.net/printf

HTH

--
..sig

[Michael Fuhr]

Re: Displaying numbers with 2 digits

Kevin Thorpe <kevin@pricetra k.com> writes:
[color=blue]
> Michael wrote:[color=green]
> >
> > I have something like :
> > $c=$a+$b;
> > echo $c,
> >
> > The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> > How 2 ?[/color]
>
> $c = $a+$b;
> printf('%2u',$c );
>
> ..or..
>
> $c = sprintf('%2u',$ a+$b);
> echo $c;[/color]

Using %2u results in a leading space, not a leading zero as stated
in the requirement. See the documentation for sprintf() to find
out how to get leading zeros.

--
Michael Fuhr

http://www.fuhr.org/~mfuhr/

[Michael]

Re: Displaying numbers with 2 digits

> Using %2u results in a leading space, not a leading zero as stated in
[color=blue]
> the requirement. See the documentation for sprintf() to find out how[/color]
[color=blue]
> to get leading zeros.[/color]

It's "%02d"

Thanx folks !

[Ian.H]

Re: Displaying numbers with 2 digits

On Mon, 24 Nov 2003 18:21:50 +0100, Michael wrote:
[color=blue][color=green]
>> Using %2u results in a leading space, not a leading zero as stated in[/color]
>[color=green]
>> the requirement. See the documentation for sprintf() to find out how[/color]
>[color=green]
>> to get leading zeros.[/color]
>
> It's "%02d"
>
> Thanx folks ![/color]


The 'u' IIRC, is a symbol for 'UNSIGNED' INTs.



Regards,

Ian

--
Ian.H [Design & Development]
digiServ Network - Web solutions
www.digiserv.net | irc.digiserv.ne t | forum.digiserv. net
Programming, Web design, development & hosting.