PHPSELF when used with file function

[Murali]

Hi,

I have a php file, where i am using an include from a URL

detail.php:

$html = "";
$contentFile = "http://www.mysite.com/link.php";
if ( $contentFile ) {
$fileBuffer = file($contentFi le);
foreach ($fileBuffer as $tmp) {
$html .= $tmp;
}
}

------------------------
link.php contains a script which echos $PHP_SELF

when i echo it, it displays "link.php" but i want the output as
"detail.php " basically i need to echo where the link is called from..

any solution ??

thanks
murali

[Martin Meredith]

Re: PHPSELF when used with file function

Why can't you use $PHP_SELF in detail.php ?

Murali wrote:
[color=blue]
> Hi,
>
> I have a php file, where i am using an include from a URL
>
> detail.php:
>
> $html = "";
> $contentFile = "http://www.mysite.com/link.php";
> if ( $contentFile ) {
> $fileBuffer = file($contentFi le);
> foreach ($fileBuffer as $tmp) {
> $html .= $tmp;
> }
> }
>
> ------------------------
> link.php contains a script which echos $PHP_SELF
>
> when i echo it, it displays "link.php" but i want the output as
> "detail.php " basically i need to echo where the link is called from..
>
> any solution ??
>
> thanks
> murali[/color]

[Pedro Graca]

Re: PHPSELF when used with file function

Murali wrote:
[...][color=blue]
> when i echo it, it displays "link.php" but i want the output as
> "detail.php " basically i need to echo where the link is called from..
>
> any solution ??[/color]

Don't read the file with file(). That way you are processing it as
another page; instead simply include it

<?php include 'link.php'; ?>

--
..sig

[Murali]

Re: PHPSELF when used with file function

Yah, but actually i need to add this html output of link.php to $html
string and print it later...

other thing which i thought is, i might pass a query string(file name)
to link.php and read that in link.php

like
file("http://www.mysite.com/link.php?pg=/mypage.php")

and in link.php i would refer to mypage.php.

i actually tried this, but for some reason, my logic which was working
is not working now.. :(

i am actually expanding a menu and collapsing a menu by passing
arguments.. something like menu=0 and menu=1.



Pedro Graca <hexkid@hotpop. com> wrote in message news:<bonmlg$1f ni77$1@ID-203069.news.uni-berlin.de>...[color=blue]
> Murali wrote:
> [...][color=green]
> > when i echo it, it displays "link.php" but i want the output as
> > "detail.php " basically i need to echo where the link is called from..
> >
> > any solution ??[/color]
>
> Don't read the file with file(). That way you are processing it as
> another page; instead simply include it
>
> <?php include 'link.php'; ?>[/color]

[Pedro Graca]

Re: PHPSELF when used with file function

Murali wrote:[color=blue]
> Yah, but actually i need to add this html output of link.php to $html
> string and print it later...[/color]

Make a function in link.php that returns what you need.

[color=blue]
> other thing which i thought is, i might pass a query string(file name)
> to link.php and read that in link.php[/color]

That should be a parameter to the function.

[color=blue]
> like
> file("http://www.mysite.com/link.php?pg=/mypage.php")
>
> and in link.php i would refer to mypage.php.[/color]

like
<?php
// ...
require_once 'link.php';
$html .= link_function(' mypage.php');
// ...
?>

[color=blue]
> i actually tried this, but for some reason, my logic which was working
> is not working now.. :(
>
> i am actually expanding a menu and collapsing a menu by passing
> arguments.. something like menu=0 and menu=1.[/color]

in link.php you can define the function with those parameters too:
<?php
function link_function($ page, $collapse=false ) {
$retval = 'menu';
if (!$collapse) $retval .= '<br/>submenu';
return $retval;
}
?>

--
..sig