managing date

[nyso]

Hi,

I've got a string that contains a date with the following format :
yyyy-mm-dd hh:mm:ss
ex :
2003-10-10 11:37:47

I'd like to get 4 variables :
- 1 for the year number,
- 1 for the month,
- 1 for the day,
- 1 for the time.

How is it possible ?
Must I use the explode function or is there another way ?

many thanks in advance,
cheers,
--
nyso

[The Biscuit Eater]

Re: managing date


"nyso" <nyso@no-spam.org> wrote in message
news:3fa0cf12$0 $27566$626a54ce @news.free.fr.. .[color=blue]
> Hi,
>
> I've got a string that contains a date with the following format :
> yyyy-mm-dd hh:mm:ss
> ex :
> 2003-10-10 11:37:47
>
> I'd like to get 4 variables :
> - 1 for the year number,
> - 1 for the month,
> - 1 for the day,
> - 1 for the time.
>
> How is it possible ?
> Must I use the explode function or is there another way ?[/color]


I did something like this (but not with the time) and posted an example
recently. I am new to this, but you could explode on the space and you would
have date and time, then explode on the date and get the year, month and
day.

Bill

[nyso]

Re: managing date

> I did something like this (but not with the time) and posted an example[color=blue]
> recently. I am new to this, but you could explode on the space and you[/color]
would[color=blue]
> have date and time, then explode on the date and get the year, month and
> day.
>
> Bill[/color]

That's what I'm doing at the moment... but it doesn't seem "clean" to me.
I'm searching for a better solution.

--
nyso

[Clubberboy]

Re: managing date

Op Thu, 30 Oct 2003 09:43:15 +0100 schreef "nyso" <nyso@no-spam.org>:
[color=blue]
>I've got a string that contains a date with the following format :
>yyyy-mm-dd hh:mm:ss
>ex :
>2003-10-10 11:37:47
>
>I'd like to get 4 variables :
>- 1 for the year number,
>- 1 for the month,
>- 1 for the day,
>- 1 for the time.
>
>How is it possible ?
>Must I use the explode function or is there another way ?[/color]

Try this:

$date_time="200 3-10-15 11:37:47";

$year=strftime( "%Y",strtotime( $date_time));
$month=strftime ("%m",strtotime ($date_time));
$day=strftime(" %d",strtotime($ date_time));
$time=strftime( "%H:%M:%S",strt otime($date_tim e));


--

http://www.techtronix.be

[Alvaro G Vicario]

Re: managing date

*** nyso wrote/escribió (Thu, 30 Oct 2003 09:43:15 +0100):[color=blue]
> 2003-10-10 11:37:47
>
> I'd like to get 4 variables :
> - 1 for the year number,
> - 1 for the month,
> - 1 for the day,
> - 1 for the time.[/color]

<?php
if (ereg ("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})", $date, $regs)) {
echo "$regs[3].$regs[2].$regs[1]";
} else {
echo "Invalid date format: $date";
}
?>

I hope this helps. It's taken from ereg() reference.


--
--
-- Álvaro G. Vicario - Burgos, Spain
--

[R. Rajesh Jeba Anbiah]

Re: managing date

"nyso" <nyso@no-spam.org> wrote in message news:<3fa0cf12$ 0$27566$626a54c e@news.free.fr> ...[color=blue]
> Hi,
>
> I've got a string that contains a date with the following format :
> yyyy-mm-dd hh:mm:ss
> ex :
> 2003-10-10 11:37:47
>
> I'd like to get 4 variables :
> - 1 for the year number,
> - 1 for the month,
> - 1 for the day,
> - 1 for the time.
>
> How is it possible ?
> Must I use the explode function or is there another way ?[/color]

You may use:

$date_str = "2003-10-10 11:37:47";
list($y, $m, $d, $hh, $mm, $ss) = sscanf($date_st r,"%4d-%2d-%2d
%2d:%2d:%2d");
echo $y;
echo $m;
.....

---
"He who created the god was a fool; he who spreads his name is a
scoundrel and he who worships him is a barbarian."---Periyar, Famous
Tamil Rationalist
Email: rrjanbiah-at-Y!com

[Pat Scott]

Re: managing date

$datearr = split("[- ]",$bigfield );

$datearr[0] will contain the year
$datearr[1] will contain the month
$datearr[2] will contain the day
$datearr[3] will contain the time

"R. Rajesh Jeba Anbiah" <ng4rrjanbiah@r ediffmail.com> wrote in message
news:abc4d8b8.0 311010458.44652 889@posting.goo gle.com...[color=blue]
> "nyso" <nyso@no-spam.org> wrote in message[/color]
news:<3fa0cf12$ 0$27566$626a54c e@news.free.fr> ...[color=blue][color=green]
> > Hi,
> >
> > I've got a string that contains a date with the following format :
> > yyyy-mm-dd hh:mm:ss
> > ex :
> > 2003-10-10 11:37:47
> >
> > I'd like to get 4 variables :
> > - 1 for the year number,
> > - 1 for the month,
> > - 1 for the day,
> > - 1 for the time.
> >
> > How is it possible ?
> > Must I use the explode function or is there another way ?[/color]
>
> You may use:
>
> $date_str = "2003-10-10 11:37:47";
> list($y, $m, $d, $hh, $mm, $ss) = sscanf($date_st r,"%4d-%2d-%2d
> %2d:%2d:%2d");
> echo $y;
> echo $m;
> .....
>
> ---
> "He who created the god was a fool; he who spreads his name is a
> scoundrel and he who worships him is a barbarian."---Periyar, Famous
> Tamil Rationalist
> Email: rrjanbiah-at-Y!com[/color]

[nyso]

Re: managing date

"Pat Scott" <jscott4272@com cast.net> a écrit dans le message de news:
EKKdnSitnZjTLD6 iRVn-hg@comcast.com...[color=blue]
> $datearr = split("[- ]",$bigfield );
>
> $datearr[0] will contain the year
> $datearr[1] will contain the month
> $datearr[2] will contain the day
> $datearr[3] will contain the time
>
> "R. Rajesh Jeba Anbiah" <ng4rrjanbiah@r ediffmail.com> wrote in message
> news:abc4d8b8.0 311010458.44652 889@posting.goo gle.com...[/color]

thank you very much for your help.
this was very useful for me.

thanks again,
--
nyso