Forms in Php

[onefastmustang]

Is it possible to use the GET method with checkboxes in php?? I have a
form that does a get but I get the following error.

Warning: Invalid argument supplied for foreach() in


If I change the method to a POST it works fine..

Thanks

[scott Johnson]

Re: Forms in Php

What snippet of code are you using for the foreach?
foreach($_GET as $key=>$value){} should work.

Is there a particular reason you are using GET and not POST for the form?

onefastmustang wrote:[color=blue]
> Is it possible to use the GET method with checkboxes in php?? I have a
> form that does a get but I get the following error.
>
> Warning: Invalid argument supplied for foreach() in
>
>
> If I change the method to a POST it works fine..
>
> Thanks
>[/color]

--
Scott Johnson

http://www.seaforthsailingclub.com

[onefastmustang]

Re: Forms in Php

I am using that exact syntax.. I misspoke before.. POST does not work
either.. The reason I was using GET is that the client wants to be
able to use the back button on the browser without getting the PAGE
EXPIRED page..

my form looks like this..
<input type="checkbox" value= "1" name="roles[]" >
<input type="checkbox" value= "2" name="roles[]" >

The reciveing code looks like this..


$roles = $_GET[roles]. $_POST[roles];


if ($roles) {
$sqls = $sqls. " and profiles.role IN (";
foreach ($roles as $key => $value){
$sqls = $sqls. "$value,";
}
$sqls = substr("$sqls", 0 , -1);
$sqls .= ")";
}

[Oli Filth]

Re: Forms in Php

onefastmustang said the following on 17/10/2005 18:22:[color=blue]
> I am using that exact syntax.. I misspoke before.. POST does not work
> either.. The reason I was using GET is that the client wants to be
> able to use the back button on the browser without getting the PAGE
> EXPIRED page..
>
> my form looks like this..
> <input type="checkbox" value= "1" name="roles[]" >
> <input type="checkbox" value= "2" name="roles[]" >
>
> The reciveing code looks like this..
>
>
> $roles = $_GET[roles]. $_POST[roles];[/color]
^ ^
^ ^
Missing quotes here?
Also, you can't concatenate arrays like this. Try array_merge() instead.
[color=blue]
>
>
> if ($roles) {
> $sqls = $sqls. " and profiles.role IN (";
> foreach ($roles as $key => $value){
> $sqls = $sqls. "$value,";
> }
> $sqls = substr("$sqls", 0 , -1);
> $sqls .= ")";
> }
>[/color]


--
Oli

[Siv Hansen]

Re: Forms in Php

onefastmustang wrote:[color=blue]
> I am using that exact syntax.. I misspoke before.. POST does not work
> either.. The reason I was using GET is that the client wants to be
> able to use the back button on the browser without getting the PAGE
> EXPIRED page..
>
> my form looks like this..
> <input type="checkbox" value= "1" name="roles[]" >
> <input type="checkbox" value= "2" name="roles[]" >
>
> The reciveing code looks like this..
>
>
> $roles = $_GET[roles]. $_POST[roles];[/color]

Do you use both get and post at the same time? If you want to use a
method that doesn't care wether the post or get method is used try request..

$roles = $_REQUEST['roles'];

[color=blue]
>
>
> if ($roles) {
> $sqls = $sqls. " and profiles.role IN (";
> foreach ($roles as $key => $value){
> $sqls = $sqls. "$value,";
> }
> $sqls = substr("$sqls", 0 , -1);
> $sqls .= ")";
> }
>[/color]

Your error message is for the loop that goes through the query to the
database. I can't see why you try to loop the way you do. Could you try
to explain what you're trying to retreive in that query?

[Jerry Stuckle]

Re: Forms in Php

onefastmustang wrote:[color=blue]
> I am using that exact syntax.. I misspoke before.. POST does not work
> either.. The reason I was using GET is that the client wants to be
> able to use the back button on the browser without getting the PAGE
> EXPIRED page..
>
> my form looks like this..
> <input type="checkbox" value= "1" name="roles[]" >
> <input type="checkbox" value= "2" name="roles[]" >
>
> The reciveing code looks like this..
>
>
> $roles = $_GET[roles]. $_POST[roles];
>
>
> if ($roles) {
> $sqls = $sqls. " and profiles.role IN (";
> foreach ($roles as $key => $value){
> $sqls = $sqls. "$value,";
> }
> $sqls = substr("$sqls", 0 , -1);
> $sqls .= ")";
> }
>[/color]

Well, $roles won't be an array at this time - you did a string
concatenation on it.

If you're using GET method, use $_GET. If you're using $_POST, use
$_POST. You can also use $_REQUEST to handle either - but personally I
don't like that as well. But that's just my personal preference.

Also, if neither checkbox is checked, $roles will be empty.

A couple of changes:

$roles = isset($_GET['roles']) ? $_GET($roles) : null; // Note quotes!

if (isset($roles) { // Has one been set?
if (isarray($roles ) { // Ensure it's an array
$sqls = $sqls. " and profiles.role IN (";
foreach ($roles as $key => $value){
$sqls = $sqls. "$value,";
}
$sqls = substr("$sqls", 0 , -1);
$sqls .= ")";
}
else { // Set but not an array
$sqls = $sqls . " and profiles.role = " . $roles . ")"
}
}

(note - not checked for syntax)
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attgl obal.net
=============== ===