Dereferencing variable name

[Owen Funkhouser]

Maybe someone can help me out here:

$name1 = "Owen";
$name2 = "Funkhouser ";

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = $name$i -->\n";
}

I'd like to see:

<!-- name1 = Owen -->
<!-- name2 = Funkhouser -->

Instead, I get:

<!-- name1 = 1 -->
<!-- name2 = 2 -->

What am I doing wrong?

[Phlarmf]

Re: Dereferencing variable name


"Owen Funkhouser" <funk@highwaay. net> wrote in message
news:3F710B3C.3 3A56CC3@highwaa y.net...[color=blue]
> Maybe someone can help me out here:
>
> $name1 = "Owen";
> $name2 = "Funkhouser ";
>
> for ($i = 1; $i < 3; $i++ ) {
> echo "<!-- name$i = $name$i -->\n";
> }
>
> I'd like to see:
>
> <!-- name1 = Owen -->
> <!-- name2 = Funkhouser -->
>
> Instead, I get:
>
> <!-- name1 = 1 -->
> <!-- name2 = 2 -->
>
> What am I doing wrong?[/color]


Dynamic variable names are done with the double dollar sign. Try this:

$name1 = "Owen";
$name2 = "Funkhouser ";

for ($i = 1; $i < 3; $i++ ) {
$varName = "name{$i}";
echo "<!-- $varName = $$varName -->\n";
}

[Owen Funkhouser]

Re: Dereferencing variable name

Phlarmf wrote:[color=blue]
>
> "Owen Funkhouser" <funk@highwaay. net> wrote in message
> news:3F710B3C.3 3A56CC3@highwaa y.net...[color=green]
> > Maybe someone can help me out here:
> >
> > $name1 = "Owen";
> > $name2 = "Funkhouser ";
> >
> > for ($i = 1; $i < 3; $i++ ) {
> > echo "<!-- name$i = $name$i -->\n";
> > }
> >
> > I'd like to see:
> >
> > <!-- name1 = Owen -->
> > <!-- name2 = Funkhouser -->
> >
> > Instead, I get:
> >
> > <!-- name1 = 1 -->
> > <!-- name2 = 2 -->
> >
> > What am I doing wrong?[/color]
>
> Dynamic variable names are done with the double dollar sign. Try this:
>
> $name1 = "Owen";
> $name2 = "Funkhouser ";
>
> for ($i = 1; $i < 3; $i++ ) {
> $varName = "name{$i}";
> echo "<!-- $varName = $$varName -->\n";
> }[/color]

I really want to avoid having another variable around. But you got me going in the right
direction. The following seems to work well:

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = ${"name$i"} -->\n";
}

[Jochen Daum]

Re: Dereferencing variable name

Hi Owen![color=blue]
>I really want to avoid having another variable around. But you got me going in the right
>direction. The following seems to work well:
>
>for ($i = 1; $i < 3; $i++ ) {
> echo "<!-- name$i = ${"name$i"} -->\n";
>}[/color]

If you want to avoid unnecessary variables you might want to look into
arrays. See www.php.net

HTH,Jochen

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database editing interfaces.

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[Owen Funkhouser]

Re: Dereferencing variable name

Jochen Daum wrote:[color=blue]
>
> Hi Owen![color=green]
> >I really want to avoid having another variable around. But you got me going in the right
> >direction. The following seems to work well:
> >
> >for ($i = 1; $i < 3; $i++ ) {
> > echo "<!-- name$i = ${"name$i"} -->\n";
> >}[/color]
>
> If you want to avoid unnecessary variables you might want to look into
> arrays. See www.php.net[/color]

The data actually ends up in an array; I elided that information. In a nutshell, I'm
converting input from a form's POST into an array.

[Zurab Davitiani]

Re: Dereferencing variable name

Owen Funkhouser wrote on Wednesday 24 September 2003 09:29:
[color=blue]
> The data actually ends up in an array; I elided that information. In a
> nutshell, I'm converting input from a form's POST into an array.[/color]

If you have control over the form being submitted, use an array when
assigning form element names, such as:

<input type="text" name="arr[0]" />
<input type="text" name="arr[1]" />
etc.

After the form is submitted, the resulting variable $_POST["arr"] will be an
array also.

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[Owen Funkhouser]

Re: Dereferencing variable name

Zurab Davitiani wrote:[color=blue]
>
> Owen Funkhouser wrote on Wednesday 24 September 2003 09:29:
>[color=green]
> > The data actually ends up in an array; I elided that information. In a
> > nutshell, I'm converting input from a form's POST into an array.[/color]
>
> If you have control over the form being submitted, use an array when
> assigning form element names, such as:
>
> <input type="text" name="arr[0]" />
> <input type="text" name="arr[1]" />
> etc.
>
> After the form is submitted, the resulting variable $_POST["arr"] will be an
> array also.[/color]

Thank you! This will remove many large chunks of code and reduce the size of the SDD
greatly.

[Geoff Berrow]

Re: Dereferencing variable name

I noticed that Message-ID:
<skmcb.9176$GO4 .8301@newssvr25 .news.prodigy.c om> from Zurab Davitiani
contained the following:
[color=blue]
><input type="text" name="arr[0]" />
><input type="text" name="arr[1]" />
>etc.
>
>After the form is submitted, the resulting variable $_POST["arr"] will be an
>array also.[/color]

So the values will be in $_POST["arr[0]"],$_POST["arr[1]"] and so on?

--
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[Pedro]

Re: Dereferencing variable name

On Thu, 25 Sep 2003 00:09:52 +0100, Geoff Berrow wrote:[color=blue]
> So the values will be in $_POST["arr[0]"],$_POST["arr[1]"] and so on?[/color]

Not quite, but very near :-)

The values will be in $_POST['arr'][0], $_POST['arr'][1], etc


and you can treat the array with the foreach construct:

<?php
echo '<table>';
foreach ($_POST['arr'] as $k=>$v) {
echo '<tr><td>', $k, '</td><td>', $v, '</td></tr>';
}
echo '</table>';
?>

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