exec("ls *.*") gives unexpected output

[kurt.krueckeberg@gmail.com]

The second line of this script
<?php
// current directory
echo getcwd() . "<br />";
print ( exec("ls *.*") );
?>
should display the names of the four files (it does in an ssh session)
which are located in public_html, but instead it displays just one
filename, that of this script.

I don't understand why?

[Chris Hope]

Re: exec(&quot;ls *.*&quot;) gives unexpected output

kurt.krueckeber g@gmail.com wrote:
[color=blue]
> The second line of this script
> <?php
> // current directory
> echo getcwd() . "<br />";
> print ( exec("ls *.*") );
> ?>
> should display the names of the four files (it does in an ssh session)
> which are located in public_html, but instead it displays just one
> filename, that of this script.
>
> I don't understand why?[/color]

It would be a good idea to refer to the manual:

http://www.php.net/manual/en/function.exec.php

Note in particular:
"Return Values
The last line from the result of the command. If you need to execute a
command and have all the data from the command passed directly back
without any interference, use the passthru() function."

--
Chris Hope | www.electrictoolbox.com | www.linuxcdmall.com