How to return a value of a variable from shell script to perl script

[babp]

HI ,
Is there any way to return a value of variable from shell to perl script.

Code:
===

Perl file 
my $diff1=system("sh diff.sh");
my $diff2=system("sh diff1.sh");

I need exit status of below commands

i.e 0 and 1 respectively.

Since in both the cases diff is working so system command will return 0 .

diff1.sh
-------
a=diff aaa ccc
diff.sh
--------
b=diff aaa bbb



122 $> cat aaa 
1hi hello
123 $> cat bbb
hi hello
125 $ cat ccc
1hi hello

120 $ diff aaa ccc
echo $?
0


diff aaa bbb
1c1
< 1hi hello
---
> hi hello
Exit 1

 echo $?
1

[numberwhun]

You are corrent, the system() command does return the return code (1 or 0) or the command it ran. My suggestion would be to use backtics in place of the system command. Its another way to execute system level commands, but you can get the output instead.

my $diff1 = `sh diff.sh`;
my $diff2 = `sh diff2.sh`;

Regards,

Jeff

[babp]

Hi Jeff ,
Thanks for the response since i jhave explained already I need exit status as 1 or 0.

If i'll use backtick it'll return the diff output like below:
1c1
< 1hi hello
---
> hi hello

But I need script to return a value like 1 if it finds any diffrence between two files and 0 if it doesnot find any diffrence between two files .

[numberwhun]

Ok, I guess I can say that I am now confused. The system() function does just that. If the script/command that was run exits normally, then it returns zero. Otherwise it returns a 1.

If the script you are running returns a value, then you would use backtics. Otherwise, I highly suggest you re-write your shell scripts in Perl to do what you need to do. It will preempt any and all confusion on what you are really wanting.

Regards,

Jeff

[babp]

Hi jeff ,
Thanks for the reply i got the solution :

ACE25C1: ...Monday/package 154 $ cat diff.pl
my $a=system("sh diff.sh");
print $a;


ACE25C1: ...Monday/package 155 $ cat diff.sh
diff aaa bbb
if [ `diff aaa bbb | grep -c "^1c1$"` -eq 0 ]
then
exit 0
else
exit 1
fi