Appending the required string between the variable(concatenation) ?

[vijayarl]

Hi Everyone,

i need to add a string in between the filename.so that new file will have the
required filename.

what am doing is reading the files from the directory & extract only the filename and then pass this failename to create new file.

now what i need is instead of just passing filename, i need to add some string to this filename & then pass the filename to create a new file.

sub loadavg_file(){
my $dir = 'C:\Performance_svap\INPUT_FILES\*.xls'; 
my @file=glob("$dir"); 
my @output;
my $loadavg;
my $str;
my $str1;
my @data;
my $date;
foreach my $f (@file){
 $str = substr($f,32,39);
 $str1 = substr($str,0,9);
 $loadavg ="c:\\Performance_svap\\OUTPUT_FILES\\$str";

blaah blaah...
....
....
}
open(EX,">$loadavg") or die "Can't open open $loadavg:$!";
print EX "$output[0]\t$output[1]\t$output[2]\t$output[3]\t$output[4]\n"; 
close EX;
}

so, in the above script, $str variable holds the filename. now to this variable i need to append the required string in between ie,

$str will have = prstat-Ls-20080118-1800.xls value.

now i need to append the string to this variable & it should look like

$str = prstat-Ls-LAVG-20080118-1800.xls

i tried changing with first instance ie,

$str = substr($f,32,39);
$str1 = substr($str,0,9);
$str = "LAVG".$str;
$loadavg ="c:\\Performance_svap\\OUTPUT_FILES\\$str";

am not getting how append the string in between the file name.

any help or suggestions will great full for me.

Thanks,
Vijayarl

[scruff6119]

You can use the period operator like this:

$str = $str1 . "LAVG" . $str;

[vijayarl]

hey thanks for reply !!! i try it right away !!!

but what i feel is what you have suggested will give this i guess :

$str1 = substr($str,0,9); # holds the value =prstat-Ls

so i guess i will get this ouput from your logic

$str=prstat-Ls-LAVG-prstat-Ls-20080118-1800.xls

anyway i will cm back !!!

Regards,
Vijayarl

[vijayarl]

hi scruff6119,

my guess was right... am getting output like this

prstat-Ls-LAVG-prstat-Ls-20080118-1800.xls

i instead want the file name to look like this:

prstat-Ls-LAVG-20080118-1800.xls

thanks for your reply

any help or idea ???

Regards,
Vijayarl

[vijayarl]

hi there,

i got it...it was simply..

foreach my $f (@file){
$str = substr($f,32,39);
$str1 = substr($str,0,9);
$str2 = substr($str,10,27);
$str = $str1 . "-LAVG-" . $str2;
$loadavg ="c:\\Performance_svap\\OUTPUT_FILES\\$str";
}

Thanks you...

Regards,
Vijayarl

[scruff6119]

Could do it by regex too:

$str =~ s/(.*?Ls-)(\d{8}.*?\.xls )/$1LANG-$2/

[vijayarl]

hey thanks scruff6119 !!!!

Even this worked...As am not so good at regex.. i didn't thought of this idea..

anyway's thanks for you help :-)

Regards,
Vijayarl