Replacing Space character

[homesick123]

From the following pattern:

$x = f+ remove/4occurances/of spaces/immediately/after plus

There are 4 space characters after f+ which are to be removed .So
How can I get the following :

$x = remove/4occurances/of spaces/immediately/after plus

[miller]

Say you have the string: my $string = "foo f+ bar";

To remove the 4 space characters after the substring "f+", all you need to do is:

$string =~ s/f\+ {4}/f+/;

The new value will be "foo f+bar";

<Note>
I'm not sure if that is what you wanted though. To more clearly ask how to make a regular expression, simply give the exact string you have before and what you want after. Alternatively, you could actually write out what you want using english, instead of this/wierd/slashing type/question. :)
</Note>