Reg. exp. question

[Roy]

Hi all,

I need to check a string for valid characters. The regular expression that I
am working is long and I try to make it short. There are many 'or' condition
in the expression, so if I can find answer to the following question then I
can make the reg exp shorter and nicer.
Now example: There is a word that could be 2 or 3 characters. First
characters should be "a" and the last character should be "d". The middle
character is either "n" or nothing. My regular expression looks like:
[a][n][d]|[a][d]
Is there a way to make the "d" optional as character d or nothing and not
use (|).
Thanks in advance,

Roy

[Jacques Leclerc]

RE: Reg. exp. question

Don't know if this will make it any shorter.
an{0,1}d

{0,1} specifies that the expression will accept 0 or 1 occurances of the
preceding character or expression.

Hope this helps

Jacques

"Roy" wrote:
[color=blue]
> Hi all,
>
> I need to check a string for valid characters. The regular expression that I
> am working is long and I try to make it short. There are many 'or' condition
> in the expression, so if I can find answer to the following question then I
> can make the reg exp shorter and nicer.
> Now example: There is a word that could be 2 or 3 characters. First
> characters should be "a" and the last character should be "d". The middle
> character is either "n" or nothing. My regular expression looks like:
> [a][n][d]|[a][d]
> Is there a way to make the "d" optional as character d or nothing and not
> use (|).
> Thanks in advance,
>
> Roy[/color]