XPath query difficulty...

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  • oopsatwork
    #1

    XPath query difficulty...

    I'm trying to construct an XPath and it is giving me trouble. I have
    an XML that contains a "Routine". The routine contains "Steps". The
    steps have different types. Some types of steps have more steps
    contained within them (substeps). I want to get a list of all of the
    steps in a routine, including any substeps...but excluding substeps
    that occur in a particular type of step ("Subroutine ").

    Below is a simplified example XML. The query I envision would return
    all of the steps in the routine, including substeps found in the
    "Loop" step type and "Condition" step type...but NOT including any
    steps that are anywhere within a "Subroutine " step.

    Any thoughts? My sincerest thanks in advance!

    -----

    <Routine>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Loop</Type>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Loop</Type>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    </Steps>
    </Step>
    </Steps>
    </Step>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Condition </Type>
    <TrueSteps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Loop</Type>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    </Steps>
    </Step>
    </TrueSteps>
    <FalseSteps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    </FalseSteps>
    </Step>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Subroutin e</Type>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    <Step>
    <Type>Loop</Type>
    <Steps>
    <Step>
    <Type>Calculati on</Type>
    <Other>stuff</Other>
    </Step>
    </Steps>
    </Step>
    </Steps>
    </Step>
    </Steps>
    </Routine>
    Tags: None
    • Dimitre Novatchev
      #2
      Re: XPath query difficulty...

      I'm trying to construct an XPath and it is giving me trouble. I have
      an XML that contains a "Routine". The routine contains "Steps". The
      steps have different types. Some types of steps have more steps
      contained within them (substeps). I want to get a list of all of the
      steps in a routine, including any substeps...but excluding substeps
      that occur in a particular type of step ("Subroutine ").


      //Step[not(ancestor::T ype[. = ' Subroutine '])]



      Cheers,

      Dimitre Novatchev





      "oopsatwork " <mkimberlin@gma il.comwrote in message
      news:e5de478f-0f92-43e1-b5d2-893d6414703b@d7 7g2000hsb.googl egroups.com...
      I'm trying to construct an XPath and it is giving me trouble. I have
      an XML that contains a "Routine". The routine contains "Steps". The
      steps have different types. Some types of steps have more steps
      contained within them (substeps). I want to get a list of all of the
      steps in a routine, including any substeps...but excluding substeps
      that occur in a particular type of step ("Subroutine ").
      >
      Below is a simplified example XML. The query I envision would return
      all of the steps in the routine, including substeps found in the
      "Loop" step type and "Condition" step type...but NOT including any
      steps that are anywhere within a "Subroutine " step.
      >
      Any thoughts? My sincerest thanks in advance!
      >
      -----
      >
      <Routine>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Loop</Type>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Loop</Type>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      </Steps>
      </Step>
      </Steps>
      </Step>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Condition </Type>
      <TrueSteps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Loop</Type>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      </Steps>
      </Step>
      </TrueSteps>
      <FalseSteps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      </FalseSteps>
      </Step>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Subroutin e</Type>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      <Step>
      <Type>Loop</Type>
      <Steps>
      <Step>
      <Type>Calculati on</Type>
      <Other>stuff</Other>
      </Step>
      </Steps>
      </Step>
      </Steps>
      </Step>
      </Steps>
      </Routine>

        Comment

        • Mukul Gandhi
          #3
          Re: XPath query difficulty...

          On Sep 27, 12:55 am, oopsatwork <mkimber...@gma il.comwrote:
          I'm trying to construct an XPath and it is giving me trouble.  I have
          an XML that contains a "Routine".  The routine contains "Steps".  The
          steps have different types.  Some types of steps have more steps
          contained within them (substeps).  I want to get a list of all of the
          steps in a routine, including any substeps...but excluding substeps
          that occur in a particular type of step ("Subroutine ").
          I would think, this should work (not tested, though)

          //Step[not(ancestor::S tep[Type = 'Subroutine'])]

          Regards,
          Mukul

            Comment

            • oopsatwork
              #4
              Re: XPath query difficulty...

              //Step[not(ancestor::S tep[Type = 'Subroutine'])]
              You guys are pimps...thanks for the help!

                Comment

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