XSL Umformung

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  • Sascha Kerschhofer
    #1

    XSL Umformung

    Hi,
    ich suche eine Idee, wie man folgendes mit XSL erreichen kann: folgendes XML
    Dokument:
    <body>
    Erster Text<br/>
    Zweiter Text<br/>
    <em>Dritter</em> Text<br/>
    Vierter <u>Text</u><br clear-previous="true"/>

    Fünfter Text<br/>

    Sechster Text
    </body>

    Ich will das nun in einzelne Absätze teilen, aber so, dass der Text im
    Absatz es immer "kumulativ" wird außer clear-previous ist true (die übrigen
    Formatierungen müssen aber erhalten bleiben). Das würde liefern:

    <body>
    <p>Erster Text</p>
    <p>Erster TextZweiterText </p>
    <p>Erster TextZweiterText <em>Dritter</em> Text</p>
    <p>Vierter <u>Text</u></p>
    <p>Vierter <u>Text</u>Fünfter Text</p>
    <p>Vierter <u>Text</u>Fünfter TextSechster Text</p>
    </body>

    Hat jemand eine Idee oder Lösung?

    Sascha Kerschhofer


    Tags: None
    • Sascha Kerschhofer
      #2
      Re: XSL Umformung

      Sorry, wrong Newsgroup selected...


      "Sascha Kerschhofer" <skerschhofer@y ahoo.antispam.d e> schrieb im Newsbeitrag
      news:d9h49h$d25 $1@news.mch.sbs .de...[color=blue]
      > Hi,
      > ich suche eine Idee, wie man folgendes mit XSL erreichen kann: folgendes[/color]
      XML[color=blue]
      > Dokument:
      > <body>
      > Erster Text<br/>
      > Zweiter Text<br/>
      > <em>Dritter</em> Text<br/>
      > Vierter <u>Text</u><br clear-previous="true"/>
      >
      > Fünfter Text<br/>
      >
      > Sechster Text
      > </body>
      >
      > Ich will das nun in einzelne Absätze teilen, aber so, dass der Text im
      > Absatz es immer "kumulativ" wird außer clear-previous ist true (die[/color]
      übrigen[color=blue]
      > Formatierungen müssen aber erhalten bleiben). Das würde liefern:
      >
      > <body>
      > <p>Erster Text</p>
      > <p>Erster TextZweiterText </p>
      > <p>Erster TextZweiterText <em>Dritter</em> Text</p>
      > <p>Vierter <u>Text</u></p>
      > <p>Vierter <u>Text</u>Fünfter Text</p>
      > <p>Vierter <u>Text</u>Fünfter TextSechster Text</p>
      > </body>
      >
      > Hat jemand eine Idee oder Lösung?
      >
      > Sascha Kerschhofer
      >
      >[/color]


        Comment

        • Joris Gillis
          #3
          Re: XSL Umformung

          On Fri, 24 Jun 2005 16:10:57 +0200, Sascha Kerschhofer
          <skerschhofer@y ahoo.antispam.d e> wrote:
          [color=blue]
          > Ich will das nun in einzelne Absätze teilen, aber so, dass der Text im
          > Absatz es immer "kumulativ" wird außer clear-previous ist true (die
          > übrigen
          > Formatierungen müssen aber erhalten bleiben). Das würde liefern:[/color]

          Hi,

          Here you find a working solution.
          It uses a combination of a key method and a recursivly called template.

          <xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
          version="1.0">

          <xsl:output method="xml" indent="yes"/>

          <xsl:key name="before_br " match="node()[not(self::br)]"
          use="generate-id(following-sibling::br[1])"/>

          <xsl:template match="body">
          <xsl:copy>
          <xsl:apply-templates select="br"/>
          <xsl:if test="br[last()]/following-sibling::node() ">
          <p>
          <xsl:apply-templates select="br[last()]" mode="copy_tail "/>
          <xsl:copy-of select="br[last()]/following-sibling::node() "/>
          </p>
          </xsl:if>
          </xsl:copy>
          </xsl:template>

          <xsl:template match="br">
          <p>
          <xsl:if test="not(@clea r-previous='true' )">
          <xsl:apply-templates select="precedi ng-sibling::br[1]"
          mode="copy_tail "/>
          </xsl:if>
          <xsl:copy-of select="key('be fore_br',genera te-id())"/>
          </p>
          </xsl:template>

          <xsl:template match="br" mode="copy_tail ">
          <xsl:apply-templates select="precedi ng-sibling::br[1]" mode="copy_tail "/>
          <xsl:copy-of select="key('be fore_br',genera te-id())"/>
          </xsl:template>

          <xsl:template match="br[@clear-previous='true']" mode="copy_tail ">
          <xsl:copy-of select="key('be fore_br',genera te-id())"/>
          </xsl:template>

          </xsl:stylesheet>

          regards,
          --
          Joris Gillis (http://users.telenet.be/root-jg/me.html)
          Vincit omnia simplicitas
          Keep it simple

            Comment

            • Sascha Kerschhofer
              #4
              Re: XSL Umformung

              Thank you Joris,
              this works pretty well. Honestly this is a quite interesting but however a
              guru-stylesheet and I don't understand exactly how it works. What is the
              recursion-rule? Maybe there is a chance to get it explained :).
              Unfortunately I had made a mistake in my example since the "new" text group
              must be started after a br[@clear-previous="true"]. The example below is
              corrected now. So what need to be modified?

              For all not-german speaking people here is the actual question:

              I need to transform some text that is divided by empty br-elements into
              separate paragraphs. Further all separated text fragments must be
              progressively collected. Example:

              <body>
              First Text<br/>
              Second Text<br/>
              <em>Thrird</em> Text<br/>
              Fourth <u>Text</u><br clear-previous="true"/>
              Fifth Text<br/>
              Sixt Text
              </body>

              becomes

              <body>
              <p>First Text</p>
              <p>First TextZweiter Text</p>
              <p>First TextSecond Text<em>Third</em> Text</p>
              <p>First TextSecond Text<em>Third</em> TextFourth <u>Text</u></p>
              <p>Fitht Text</p>
              <p>Fith TextSixt Text</p>
              </body>


              Sascha Kerschhofer


                Comment

                • Joris Gillis
                  #5
                  Re: XSL Umformung

                  Hi,

                  On Tue, 28 Jun 2005 14:28:54 +0200, Kerschhofer Alexander
                  <alexander.kers chhofer@siemens .com> wrote:

                  Honestly this is a quite interesting but however a guru-stylesheet
                  It would take a guru to code a guru-stylesheet:D Mine was probably
                  unintelligable. ..
                  and I don't understand exactly how it works. What is the recursion-rule?
                  The recursion is done via the 'copy_tail' template
                  Maybe there is a chance to get it explained :).
                  see the comments below
                  Unfortunately I had made a mistake in my example since the "new" text group
                  must be started after a br[@clear-previous="true"]. The example below is
                  corrected now. So what need to be modified?

                  In that case it becomes much easier, it was actually the error in your
                  sample data that made the job challenging.
                  Here you have a new stylesheet with comments included:

                  <xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
                  version="1.0">

                  <xsl:output method="xml" indent="yes"/>

                  <xsl:key name="before_br " match="node()[not(self::br)]"
                  use="generate-id(following-sibling::br[1])"/>
                  <!-- the key connects all nodes to their first 'br' element
                  following-sibling -->

                  <xsl:template match="body">
                  <xsl:copy>
                  <xsl:apply-templates select="br"/>
                  <xsl:if test="br[last()]/following-sibling::node() ">
                  <!-- handle left-over nodes at the body's end-->
                  <p>
                  <xsl:apply-templates select="br[last()]" mode="copy_tail "/>
                  <xsl:copy-of select="br[last()]/following-sibling::node() "/>
                  </p>
                  </xsl:if>
                  </xsl:copy>
                  </xsl:template>

                  <xsl:template match="br">
                  <p>
                  <xsl:apply-templates select="." mode="copy_tail "/>
                  <!-- copy the tail of this 'br' node inside a 'p' element-->
                  </p>
                  </xsl:template>

                  <xsl:template match="br" mode="copy_tail ">
                  <!-- continue copying the tail backwards and only stop when the
                  'clear-previous' attribute is 'true'-->
                  <xsl:apply-templates
                  select="precedi ng-sibling::br[1][not(@clear-previous='true' )]"
                  mode="copy_tail "/>
                  <xsl:copy-of select="key('be fore_br',genera te-id())"/>
                  </xsl:template>

                  </xsl:stylesheet>


                  regards,
                  --
                  Joris Gillis (http://users.telenet.be/root-jg/me.html)
                  Vincit omnia simplicitas
                  Keep it simple

                    Comment

                    • Sascha Kerschhofer
                      #6
                      Re: XSL Umformung

                      Wow, so you are indeed a guru xsl-transformer...
                      Sascha
                      [color=blue]
                      > In that case it becomes much easier, it was actually the error in your
                      > sample data that made the job challenging.
                      > Here you have a new stylesheet with comments included:
                      >
                      > <xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
                      > version="1.0">
                      >
                      > <xsl:output method="xml" indent="yes"/>
                      >
                      > <xsl:key name="before_br " match="node()[not(self::br)]"
                      > use="generate-id(following-sibling::br[1])"/>
                      > <!-- the key connects all nodes to their first 'br' element
                      > following-sibling -->
                      >
                      > <xsl:template match="body">
                      > <xsl:copy>
                      > <xsl:apply-templates select="br"/>
                      > <xsl:if test="br[last()]/following-sibling::node() ">
                      > <!-- handle left-over nodes at the body's end-->
                      > <p>
                      > <xsl:apply-templates select="br[last()]" mode="copy_tail "/>
                      > <xsl:copy-of select="br[last()]/following-sibling::node() "/>
                      > </p>
                      > </xsl:if>
                      > </xsl:copy>
                      > </xsl:template>
                      >
                      > <xsl:template match="br">
                      > <p>
                      > <xsl:apply-templates select="." mode="copy_tail "/>
                      > <!-- copy the tail of this 'br' node inside a 'p' element-->
                      > </p>
                      > </xsl:template>
                      >
                      > <xsl:template match="br" mode="copy_tail ">
                      > <!-- continue copying the tail backwards and only stop when the
                      > 'clear-previous' attribute is 'true'-->
                      > <xsl:apply-templates
                      > select="precedi ng-sibling::br[1][not(@clear-previous='true' )]"
                      > mode="copy_tail "/>
                      > <xsl:copy-of select="key('be fore_br',genera te-id())"/>
                      > </xsl:template>
                      >
                      > </xsl:stylesheet>
                      >
                      >
                      > regards,
                      > --
                      > Joris Gillis (http://users.telenet.be/root-jg/me.html)
                      > Vincit omnia simplicitas
                      > Keep it simple[/color]


                        Comment

                        • Joris Gillis
                          #7
                          Re: XSL Umformung

                          > Wow, so you are indeed a guru xsl-transformer...
                          I actually meant to say that I do not consider myself a guru at all.

                            Comment

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