How to display all the ancestors and their attributes of a selected element?

[ai2003lian@yahoo.com]

Assuming I have the following two xml file:


source.xml:

<AllFields>
<Group name="G1">
<Field fieldName="f1"> Value1</Field>
<Field fieldName="f2"> Value2</Field>
<Field fieldName="f3"> Value3</Field>
</Group>
<Group name="G2">
<Field fieldName="f4"> Value4</Field>
<Field fieldName="f5"> Value5</Field>
<Field fieldName="f6"> Value6</Field>
</Group>
<Group name="G3">
<Field fieldName="f7"> Value7</Field>
<Field fieldName="f8"> Value8</Field>
<Field fieldName="f9"> Value9</Field>
</Group>
</AllFields>

required.xml:

<RequiredFields >
<FieldName>f1 </FieldName>
<FieldName>f3 </FieldName>
<FieldName>f6 </FieldName>
</RequiredFields>


The requirement.xml defines which field will go to the output XML.

The xsl file and output XML are like the following:

xsl file:

<xsl:template match="node()|@ *">
<xsl:if test="(not(self ::Field )or
@FieldName=docu ment('required .xml')/*/FieldName">
<xsl:copy>
<xsl:apply-templates select="node()| @*"/>
</xsl:copy>
</xsl:if>
</xsl:template>

output.xml

<AllFields>
<Group name="G1">
<Field fieldName="f1"> Value1</Field>

<Field fieldName="f3"> Value3</Field>
</Group>
<Group name="G2">


<Field fieldName="f6"> Value6</Field>
</Group>
<Group name="G3">



</Group>
</AllFields>


How could I use XSLT to get the following desired output(without all
the empty lines and the last Group element:


<AllFields>
<Group name="G1">
<Field fieldName="f1"> Value1</Field>
<Field fieldName="f3"> Value3</Field>
</Group>
<Group name="G2">
<Field fieldName="f6"> Value6</Field>
</Group>
</AllFields>


Thanks your help in advance!

[Joris Gillis]

Re: How to display all the ancestors and their attributes of a selected element?

Tempore 23:06:17, die Thursday 10 February 2005 AD, hinc in foro {comp.text.xml} scripsit <ai2003lian@yah oo.com>:
[color=blue]
> <xsl:template match="node()|@ *">
> <xsl:if test="(not(self ::Field )or
> @FieldName=docu ment('requÂire d.xml')/*/FieldName">
> <xsl:copy>
> <xsl:apply-templates select="node()| @*"/>
> </xsl:copy>
> </xsl:if>
> </xsl:template>
>
> How could I use XSLT to get the following desired output(without all
> the empty lines and the last Group element:[/color]

try something like:

<xsl:template match="node()|@ *">
<xsl:if test="not(self: :Field or self::Group)
or (.|*)/@fieldName=docu ment('requÂire d.xml')/*/FieldName">
<xsl:copy>
<xsl:apply-templates select="node()| @*"/>
</xsl:copy>
</xsl:if>
</xsl:template>

(do beware of lower/uppercase, when you're testing this)

As for the whitespaces in your output, I don't see them occurring when I try your template.


regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)
Veni, vidi, wiki (http://www.wikipedia.org)

[ai2003lian@yahoo.com]

Re: How to display all the ancestors and their attributes of a selected element?

Thank. But it didn't work. The result xml is as the following:

<?xml version="1.0"?>
<AllFields>



</AllFields>

Any ideas?


Joris Gillis wrote:[color=blue]
> Tempore 23:06:17, die Thursday 10 February 2005 AD, hinc in foro[/color]
{comp.text.xml} scripsit <ai2003lian@yah oo.com>:[color=blue]
>[color=green]
> > <xsl:template match="node()|@ *">
> > <xsl:if test="(not(self ::Field )or
> > @FieldName=docu ment('required .xml')/*/FieldName">
> > <xsl:copy>
> > <xsl:apply-templates select="node()| @*"/>
> > </xsl:copy>
> > </xsl:if>
> > </xsl:template>
> >
> > How could I use XSLT to get the following desired output(without[/color][/color]
all[color=blue][color=green]
> > the empty lines and the last Group element:[/color]
>
> try something like:
>
> <xsl:template match="node()|@ *">
> <xsl:if test="not(self: :Field or self::Group)
> or (.|*)/@fieldName=docu ment('required .xml')/*/FieldName">
> <xsl:copy>
> <xsl:apply-templates select="node()| @*"/>
> </xsl:copy>
> </xsl:if>
> </xsl:template>
>
> (do beware of lower/uppercase, when you're testing this)
>
> As for the whitespaces in your output, I don't see them occurring[/color]
when I try your template.[color=blue]
>
>
> regards,
> --
> Joris Gillis[/color]
(http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)[color=blue]
> Veni, vidi, wiki (http://www.wikipedia.org)[/color]

[Joris Gillis]

Re: How to display all the ancestors and their attributes of a selected element?

On 11 Feb 2005 07:19:08 -0800, <ai2003lian@yah oo.com> wrote:
[color=blue]
> Thank. But it didn't work. The result xml is as the following:
>
> <?xml version="1.0"?>
> <AllFields>
>
>
>
> </AllFields>
>
> Any ideas?
>[/color]

Very strange...

Tested with Saxon and AltovaXSLT

input:
<AllFields>
<Group name="G1">
<Field fieldName="f1"> Value1</Field>
<Field fieldName="f2"> Value2</Field>
<Field fieldName="f3"> Value3</Field>
</Group>
<Group name="G2">
<Field fieldName="f4"> Value4</Field>
<Field fieldName="f5"> Value5</Field>
<Field fieldName="f6"> Value6</Field>
</Group>
<Group name="G3">
<Field fieldName="f7"> Value7</Field>
<Field fieldName="f8"> Value8</Field>
<Field fieldName="f9"> Value9</Field>
</Group>
</AllFields>

required.xml:
<RequiredFields >
<FieldName>f1 </FieldName>
<FieldName>f3 </FieldName>
<FieldName>f6 </FieldName>
</RequiredFields>

XSL:
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">

<xsl:strip-space elements="*"/>
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node()|@ *">
<xsl:if test="not(self: :Field or self::Group)
or (.|*)/@fieldName=docu ment('required. xml')/*/FieldName">
<xsl:copy>
<xsl:apply-templates select="node()| @*"/>
</xsl:copy>
</xsl:if>
</xsl:template>

</xsl:stylesheet>

(notice the 'strip-space' element I added; it solves the issue with the
linebreaks.

output:

<AllFields>
<Group name="G1">
<Field fieldName="f1"> Value1</Field>
<Field fieldName="f3"> Value3</Field>
</Group>
<Group name="G2">
<Field fieldName="f6"> Value6</Field>
</Group>
</AllFields>


The stylesheet probably needed adaption to your real XML. It's probably
some wrong names in the test expression that cause the trouble with your
real XML.

--
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/

[ai2003lian@yahoo.com]

Re: How to display all the ancestors and their attributes of a selected element?

Thanks. It still didn't work for me since I'm using XML C parser
libxml2 and libxslt. But I came up with the following solution:

<xsl:output method = "xml" indent = "yes" />

<xsl:template match="node()">
<xsl:if
test="descendan t-or-self::*/@fieldName=docu ment('required. xml')/*/FieldName
or @FieldName=docu ment('required .xml')/*/FieldName">
<xsl:text>
</xsl:text>
<xsl:element name = "{name(self::*) }" >
<xsl:for-each select = "@*" >
<xsl:attribut e name="{name(cur rent())}" >
<xsl:value-of select = "current()" />
</xsl:attribute>
</xsl:for-each>
<xsl:apply-templates select="node()"/>
<xsl:value-of select = "node()" />
</xsl:element>
</xsl:if>
</xsl:template>
</xsl:stylesheet>

It works fine although I'm still looking for a better way to do it.


Joris Gillis wrote:[color=blue]
> On 11 Feb 2005 07:19:08 -0800, <ai2003lian@yah oo.com> wrote:
>[color=green]
> > Thank. But it didn't work. The result xml is as the following:
> >
> > <?xml version="1.0"?>
> > <AllFields>
> >
> >
> >
> > </AllFields>
> >
> > Any ideas?
> >[/color]
>
> Very strange...
>
> Tested with Saxon and AltovaXSLT
>
> input:
> <AllFields>
> <Group name="G1">
> <Field fieldName="f1"> Value1</Field>
> <Field fieldName="f2"> Value2</Field>
> <Field fieldName="f3"> Value3</Field>
> </Group>
> <Group name="G2">
> <Field fieldName="f4"> Value4</Field>
> <Field fieldName="f5"> Value5</Field>
> <Field fieldName="f6"> Value6</Field>
> </Group>
> <Group name="G3">
> <Field fieldName="f7"> Value7</Field>
> <Field fieldName="f8"> Value8</Field>
> <Field fieldName="f9"> Value9</Field>
> </Group>
> </AllFields>
>
> required.xml:
> <RequiredFields >
> <FieldName>f1 </FieldName>
> <FieldName>f3 </FieldName>
> <FieldName>f6 </FieldName>
> </RequiredFields>
>
> XSL:
> <xsl:styleshe et version="1.0"
> xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
>
> <xsl:strip-space elements="*"/>
> <xsl:output method="xml" indent="yes"/>
>
> <xsl:template match="node()|@ *">
> <xsl:if test="not(self: :Field or self::Group)
> or (.|*)/@fieldName=docu ment('required. xml')/*/FieldName">
> <xsl:copy>
> <xsl:apply-templates select="node()| @*"/>
> </xsl:copy>
> </xsl:if>
> </xsl:template>
>
> </xsl:stylesheet>
>
> (notice the 'strip-space' element I added; it solves the issue with[/color]
the[color=blue]
> linebreaks.
>
> output:
>
> <AllFields>
> <Group name="G1">
> <Field fieldName="f1"> Value1</Field>
> <Field fieldName="f3"> Value3</Field>
> </Group>
> <Group name="G2">
> <Field fieldName="f6"> Value6</Field>
> </Group>
> </AllFields>
>
>
> The stylesheet probably needed adaption to your real XML. It's[/color]
probably[color=blue]
> some wrong names in the test expression that cause the trouble with[/color]
your[color=blue]
> real XML.
>
> --
> Using Opera's revolutionary e-mail client: http://www.opera.com/m2/[/color]

[Joris Gillis]

Re: How to display all the ancestors and their attributes of a selected element?

On 11 Feb 2005 09:49:02 -0800, <ai2003lian@yah oo.com> wrote:
[color=blue]
> Thanks. It still didn't work for me since I'm using XML C parser
> libxml2 and libxslt. But I came up with the following solution:
>
> <xsl:output method = "xml" indent = "yes" />
>
> <xsl:template match="node()">
> <xsl:if
> test="descendan t-or-self::*/@fieldName=docu ment('required. xml')/*/FieldName
> or @FieldName=docu ment('required .xml')/*/FieldName">
> <xsl:text>
> </xsl:text>
> <xsl:element name = "{name(self::*) }" >
> <xsl:for-each select = "@*" >
> <xsl:attribut e name="{name(cur rent())}" >
> <xsl:value-of select = "current()" />
> </xsl:attribute>
> </xsl:for-each>
> <xsl:apply-templates select="node()"/>
> <xsl:value-of select = "node()" />
> </xsl:element>
> </xsl:if>
> </xsl:template>
> </xsl:stylesheet>
>
> It works fine although I'm still looking for a better way to do it.[/color]

how about this template?

<xsl:template match="node()">
<xsl:if
test="descendan t-or-self::*/@fieldName=docu ment('required. xml')/*/FieldName">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="node()"/>
<xsl:value-of select="text()" />
</xsl:copy>
</xsl:if>
</xsl:template>

(correct result in Saxon), just curious to know if your processor can
handle this...

--
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/

[ai2003lian@yahoo.com]

Re: How to display all the ancestors and their attributes of a selected element?

It did the trick! Thanks!