Recursion of tags in one tag

[Cedric Vonck]

Hello everybody,

I have a question about xml / xsl(t).

I need to transform a following kind of xml to editable file (format
does not matter).

The xml file look like this:

<...> Root
<tag>
<subtag1>.... .</subtag1>
<subtag2>.... .</subtag2>
....
....
<subtag1>.... .</subtag1>
<subtag2>.... .</subtag2>
</tag>
</...> End Root

Subtag1 & Subtag2 can repeat themselves n-times.
I know that this is xml is wellformed but not wellstructured.

The ideal solution should be:

<...> Root
<tag>
<detail>
<subtag1>.... .</subtag1>
<subtag2>.... .</subtag2>
</detail>
<detail>
<subtag1>.... .</subtag1>
<subtag2>.... .</subtag2>
</detail>
</tag>
</...> End Root

If the xml should like this (in the ideal case) I could get the
conversion to work in no time.

Any suggestions how I could write a correct xsl(t) for the first
example???

Thank you

[Joris Gillis]

Re: Recursion of tags in one tag

Tempore 15:25:40, die Thursday 10 February 2005 AD, hinc in foro {comp.text.xml} scripsit Cedric Vonck <vanderhoeven@p ing.be>:

[color=blue]
> Subtag1 & Subtag2 can repeat themselves n-times.
> I know that this is xml is wellformed but not wellstructured.
>
> The ideal solution should be:
>
> <...> Root
> <tag>
> <detail>
> <subtag1>.... .</subtag1>
> <subtag2>.... .</subtag2>
> </detail>
> <detail>
> <subtag1>.... .</subtag1>
> <subtag2>.... .</subtag2>
> </detail>
> </tag>
> </...> End Root
>
> If the xml should like this (in the ideal case) I could get the
> conversion to work in no time.
>
> Any suggestions how I could write a correct xsl(t) for the first
> example???[/color]
Hi,

I'm not really sure if this is really what you asked for, but here's an xslt that converts the first document into the second:

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*"/>
</xsl:copy>
</xsl:template>

<xsl:template match="*[subtag1]">
<xsl:copy>
<xsl:apply-templates select="node()[not(self::subta g2)] | @*"/>
</xsl:copy>
</xsl:template>

<xsl:template match="subtag1" >
<details>
<xsl:copy-of select=". | following-sibling::subtag 2[1]"/>
</details>
</xsl:template>

</xsl:stylesheet>


regards,
--
Joris Gillis (http://www.ticalc.org/cgi-bin/acct-v...i?userid=38041)
Vincit omnia simplicitas
Keep it simple

[Cedric Vonck]

Re: Recursion of tags in one tag

> <xsl:styleshe et version="1.0"[color=blue]
> xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
> <xsl:output method="xml" indent="yes"/>
>
> <xsl:template match="node() | @*">
> <xsl:copy>
> <xsl:apply-templates select="node() | @*"/>
> </xsl:copy>
> </xsl:template>
>
> <xsl:template match="*[subtag1]">
> <xsl:copy>
> <xsl:apply-templates select="node()[not(self::subta g2)] | @*"/>
> </xsl:copy>
> </xsl:template>
>
> <xsl:template match="subtag1" >
> <details>
> <xsl:copy-of select=". | following-sibling::subtag 2[1]"/>
> </details>
> </xsl:template>
>
> </xsl:stylesheet>
>
>
> regards,[/color]

Thank you for your answer, but I should have made my post more
clearer.
The second example with the (<detail>) tag is no problem for me.
It is the first one that poses problems.

So if possible, could anyone explain to me how I have to write a
decent xsl(t) for it??

Thx