array creation (elementary question)

[gmb]

(.NET 2.0)

code:
array<TextBox^^ dialog_txb = {gcnew TextBox(),gcnew TextBox(),gcnew
TextBox(),gcnew TextBox(),gcnew TextBox()};

question:
Is there a shorter way to declare and initialize an array of 5 objects
without repetition of "gcnew TextBox()" ?
(What if I need to create an array with much bigger number of elements?)

Thanks in advance,
gmb

[=?Utf-8?B?RGF2aWQgQW50b24=?=]

RE: array creation (elementary question)

You only should use that syntax if you have the specific instances ready to
insert.
Instead use:
array<TextBox^^ dialog_txb = gcnew array<TextBox^> (5);

and then when you have the instance of TextBox that you want in the array,
add them using standard array syntax (e.g., dialog_txb[0] =
some_specific_t extbox, or dialog_txb[0] = gcnew TextBox() - obviously in a
loop if you have many that you're adding this way).
--
David Anton

https://www.tangiblesoftwaresolutions.com

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"gmb" wrote:

(.NET 2.0)
>
code:
array<TextBox^^ dialog_txb = {gcnew TextBox(),gcnew TextBox(),gcnew
TextBox(),gcnew TextBox(),gcnew TextBox()};
>
question:
Is there a shorter way to declare and initialize an array of 5 objects
without repetition of "gcnew TextBox()" ?
(What if I need to create an array with much bigger number of elements?)
>
Thanks in advance,
gmb
>
>

[Ben Voigt [C++ MVP]]

Re: array creation (elementary question)


"gmb" <diehard_gmb@wp .plwrote in message
news:u$zH3AcpHH A.3880@TK2MSFTN GP04.phx.gbl...

(.NET 2.0)
>
code:
array<TextBox^^ dialog_txb = {gcnew TextBox(),gcnew TextBox(),gcnew
TextBox(),gcnew TextBox(),gcnew TextBox()};
>
question:
Is there a shorter way to declare and initialize an array of 5 objects
without repetition of "gcnew TextBox()" ?

Please realize that .NET has no concept of initialized array. If you look
at the IL, you will see that it first creates the array, and then _assigns_
(not initializes) each element in sequence. So you will get the exact same
behavior using a loop.

(What if I need to create an array with much bigger number of elements?)
>
Thanks in advance,
gmb