AppDomain.Load MixedMode (MC++) Dll Problem

[John]

Hi,

I tried to load a mixedmode dll (MC++) with AppDomain.Load( Byte[] ) in a C#
Client.
During the Load Process I got the following Exception:

System.IO.FileL oadException: Ausnahme von HRESULT: 0x80131019.
at System.Reflecti on.Assembly.nLo adImage(Byte[] rawAssembly, Byte[]
rawSymbolStore, Evidence evidence, StackCrawlMark& stackMark)
at System.AppDomai n.Load(Byte[] rawAssembly) ...

I also tried this with a pure managed MC++ dll and got the same error.

If I load a normal C# dll everythink is fine.

Here's the code loading the Assembly:


Any Suggestions?

////////////////////////Code Snippet for Loading the Assembly

public void LoadAssemblyOnl y(string Path)
{
FileStream f1 = new FileStream(Path ,FileMode.Open) ;
Byte[] rawAssemblyByte s1 = new Byte[f1.Length];
f1.Read(rawAsse mblyBytes1,0,(i nt)f1.Length);
f1.Close();

AppDomain.Curre ntDomain.Assemb lyResolve +=new
ResolveEventHan dler(CurrentDom ain_AssemblyRes olve0);
Assembly ass = AppDomain.Curre ntDomain.Load(r awAssemblyBytes 1);
MessageBox.Show (ass.FullName," Loaded AssemblyName");
string AssList="";
foreach (Assembly a in AppDomain.Curre ntDomain.GetAss emblies() )
{
AssList += a.FullName +"\r\n";
}
MessageBox.Show (AssList,"Assem blyList");
string typelist="";
foreach(Type t in ass.GetTypes() )
{
typelist += t.FullName +"\r\n";
}
MessageBox.Show (typelist,"Type LIst");
}

private Assembly CurrentDomain_A ssemblyResolve0 (object sender,
ResolveEventArg s args)
{
MessageBox.Show ("Name:"+args.N ame,"ResolveEve nt") ;
Assembly ass = Assembly.LoadFr om(args.Name);
if(ass!=null)
{
MessageBox.Show ("Assembly loaded:"+ass.Fu llName);
}
else
{
MessageBox.Show ("Assembly not loaded");
}
return ass;
}
////////////////////////

Best regards in advance
John

[Junfeng Zhang[MSFT]]

Re: AppDomain.Load MixedMode (MC++) Dll Problem

It is not possible to load MC++ assembly through Assembly.Load(b yte[]). MC++
assembly requires fixup which cannot be performed in byte array.

--
Junfeng Zhang

http://blogs.msdn.com/junfeng

This posting is provided "AS IS" with no warranties, and confers no rights.

"John" <paradisaea@gmx .de> wrote in message
news:uGOnkKqHFH A.1176@TK2MSFTN GP12.phx.gbl...[color=blue]
> Hi,
>
> I tried to load a mixedmode dll (MC++) with AppDomain.Load( Byte[] ) in a
> C#
> Client.
> During the Load Process I got the following Exception:
>
> System.IO.FileL oadException: Ausnahme von HRESULT: 0x80131019.
> at System.Reflecti on.Assembly.nLo adImage(Byte[] rawAssembly, Byte[]
> rawSymbolStore, Evidence evidence, StackCrawlMark& stackMark)
> at System.AppDomai n.Load(Byte[] rawAssembly) ...
>
> I also tried this with a pure managed MC++ dll and got the same error.
>
> If I load a normal C# dll everythink is fine.
>
> Here's the code loading the Assembly:
>
>
> Any Suggestions?
>
> ////////////////////////Code Snippet for Loading the Assembly
>
> public void LoadAssemblyOnl y(string Path)
> {
> FileStream f1 = new FileStream(Path ,FileMode.Open) ;
> Byte[] rawAssemblyByte s1 = new Byte[f1.Length];
> f1.Read(rawAsse mblyBytes1,0,(i nt)f1.Length);
> f1.Close();
>
> AppDomain.Curre ntDomain.Assemb lyResolve +=new
> ResolveEventHan dler(CurrentDom ain_AssemblyRes olve0);
> Assembly ass = AppDomain.Curre ntDomain.Load(r awAssemblyBytes 1);
> MessageBox.Show (ass.FullName," Loaded AssemblyName");
> string AssList="";
> foreach (Assembly a in AppDomain.Curre ntDomain.GetAss emblies() )
> {
> AssList += a.FullName +"\r\n";
> }
> MessageBox.Show (AssList,"Assem blyList");
> string typelist="";
> foreach(Type t in ass.GetTypes() )
> {
> typelist += t.FullName +"\r\n";
> }
> MessageBox.Show (typelist,"Type LIst");
> }
>
> private Assembly CurrentDomain_A ssemblyResolve0 (object sender,
> ResolveEventArg s args)
> {
> MessageBox.Show ("Name:"+args.N ame,"ResolveEve nt") ;
> Assembly ass = Assembly.LoadFr om(args.Name);
> if(ass!=null)
> {
> MessageBox.Show ("Assembly loaded:"+ass.Fu llName);
> }
> else
> {
> MessageBox.Show ("Assembly not loaded");
> }
> return ass;
> }
> ////////////////////////
>
> Best regards in advance
> John
>
>[/color]