VS7.1: No member function pointer call possible?

[Axel Dahmen]

Hi,

I can't get to compile the following:


struct A
{
A(void);
bool fn(void);
bool (A::*pfnc)(void );
};


A::A(void) : pfnc(fn) {}


bool A::fn(void) {return true;}


int _tmain(int argc, _TCHAR* argv[])
{
A a;
(a.*pfnc)(); // *** error: 'pfnc': undeclared identifier ***
return 0;
}

Is it me?? This ought to be correct C++ syntax. What am I doing wrong?

TIA,
Axel Dahmen

[Igor Tandetnik]

Re: VS7.1: No member function pointer call possible?

"Axel Dahmen" <NoSpam@NoOneKn ows.de> wrote in message
news:OTdDZ4o5DH A.2404@TK2MSFTN GP11.phx.gbl...[color=blue]
> I can't get to compile the following:
>
>
> struct A
> {
> A(void);
> bool fn(void);
> bool (A::*pfnc)(void );
> };
>
>
> A::A(void) : pfnc(fn) {}[/color]

Should be

A::A(void) : pfnc(&A::fn) {}
[color=blue]
> int _tmain(int argc, _TCHAR* argv[])
> {
> A a;
> (a.*pfnc)(); // *** error: 'pfnc': undeclared identifier[/color]
***

Should be

(a.*(a.pfnc))() ;
[color=blue]
> return 0;
> }[/color]

--
With best wishes,
Igor Tandetnik

"For every complex problem, there is a solution that is simple, neat,
and wrong." H.L. Mencken

[Doug Harrison [MVP]]

Re: VS7.1: No member function pointer call possible?

Axel Dahmen wrote:
[color=blue]
>Hi,
>
>I can't get to compile the following:
>
>
> struct A
> {
> A(void);
> bool fn(void);
> bool (A::*pfnc)(void );
> };
>
>
> A::A(void) : pfnc(fn) {}
>
>
> bool A::fn(void) {return true;}
>
>
> int _tmain(int argc, _TCHAR* argv[])
> {
> A a;
> (a.*pfnc)(); // *** error: 'pfnc': undeclared identifier ***
> return 0;
> }
>
>Is it me?? This ought to be correct C++ syntax. What am I doing wrong?[/color]

Try:

(a.*a.pfnc)();

P.S. For functions which have no parameters, it's conventional in C++ to
omit the "void", because in C++, an empty parameter list means "void".

--
Doug Harrison
Microsoft MVP - Visual C++