How to convert a Byte array to a char array?

[Kueishiong Tu]

How do I convert a Byte array (unsigned char managed) to a
char array(unmanaged ) with wide character taken into
account?

[Nishant S]

Re: How to convert a Byte array to a char array?

Byte barray[] = new Byte[512];
__wchar_t* arr = new __wchar_t[barray->Length];
for(int i=0; i < barray->Length; i++)
arr[i] = barray[i];
delete arr;

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:2da101c374 a4$b85591a0$a10 1280a@phx.gbl.. .[color=blue]
> How do I convert a Byte array (unsigned char managed) to a
> char array(unmanaged ) with wide character taken into
> account?[/color]

[Kueishiong Tu]

Re: How to convert a Byte array to a char array?

[color=blue]
>-----Original Message-----
>Byte barray[] = new Byte[512];
>__wchar_t* arr = new __wchar_t[barray->Length];
>for(int i=0; i < barray->Length; i++)
>arr[i] = barray[i];
>delete arr;[/color]

How do I further convert to a array declared as char
carray[]? The access of a char array through its pointer
has taken the wide character into account. i.e., if

char *cpp;
int n;
cpp = carray;

(cpp+n) will always point to a valid wide charater (n any
int).

[Nishant S]

Re: How to convert a Byte array to a char array?

Byte barray[] = new Byte[512];

//char here is 16 bits
char smallarray[512];
for(int i=0; i<barray->Length; i++)
smallarray[i] = barray[i];

//Char here is 32 bits
Char carray[] = Encoding::ASCII->GetChars(barra y);


--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:2f9801c374 e6$35387b60$a10 1280a@phx.gbl.. .[color=blue]
>[color=green]
> >-----Original Message-----
> >Byte barray[] = new Byte[512];
> >__wchar_t* arr = new __wchar_t[barray->Length];
> >for(int i=0; i < barray->Length; i++)
> >arr[i] = barray[i];
> >delete arr;[/color]
>
> How do I further convert to a array declared as char
> carray[]? The access of a char array through its pointer
> has taken the wide character into account. i.e., if
>
> char *cpp;
> int n;
> cpp = carray;
>
> (cpp+n) will always point to a valid wide charater (n any
> int).
>[/color]

[Kueishiong Tu]

Re: How to convert a Byte array to a char array?

[color=blue]
>-----Original Message-----
>Byte barray[] = new Byte[512];
>
>//char here is 16 bits
>char smallarray[512];
>for(int i=0; i<barray->Length; i++)
> smallarray[i] = barray[i];
>
>//Char here is 32 bits
>Char carray[] = Encoding::ASCII->GetChars(barra y);
>[/color]

The byte array contains a mixture of
raw data of Ascii (8-bit) and Chinese characters (16-bit).
What I need is to convert the byte array into a char array
so that if I assigned a char pointer to the beginning of
the char array and I increment the char pointer, it will
point to a valid wide character which may be 8-bit or 16-
bit.

Byte barray[512];
char carray[512];
char *cpp;
//convert barray to caaray
cpp = carray;
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);
printf("%c\n", *cpp); // valid 8-bit or 16-bit character
*(cpp++);

and so on ....

[Jochen Kalmbach]

Re: How to convert a Byte array to a char array?

Kueishiong Tu wrote:
[color=blue]
> How do I convert a Byte array (unsigned char managed) to a
> char array(unmanaged ) with wide character taken into
> account?[/color]

See: StringToHGlobal Ansi (System::Runtim e::InteropServi ces::Marshal)

http://msdn.microsoft.com/library/en-

us/cpref/html/frlrfsystemrunt imeinteropservi cesmarshalclass stringtohglobal a
nsitopic.asp

But conversion to ANSI is bad... because String is UNICODE... so if it
contains some unicode characters this might be lost.

Better convert to unicde: StringToHGlobal Uni
or use PtrToStringChar s (which is faster; if you do not need to modify the
string)

See also:
HOW TO: Convert from System::String* to Char* in Visual C++ .NET

http://support.microsoft.com/?kbid=311259

--
Greetings
Jochen

Do you need a memory-leak finder ?

http://www.codeproject.com/tools/leakfinder.asp

[Nishant S]

Re: How to convert a Byte array to a char array?

There was en error in my prev post.

char is 8 bits (a byte) and Char is 16 bits (2 bytes)

--
Regards,
Nish [VC++ MVP]



"Nishant S" <nish@nospam.as ianetindia.com> wrote in message
news:upOT4hOdDH A.3248@tk2msftn gp13.phx.gbl...[color=blue]
> Byte barray[] = new Byte[512];
>
> //char here is 16 bits
> char smallarray[512];
> for(int i=0; i<barray->Length; i++)
> smallarray[i] = barray[i];
>
> //Char here is 32 bits
> Char carray[] = Encoding::ASCII->GetChars(barra y);
>
>
> --
> Regards,
> Nish [VC++ MVP]
>
>
>
> "Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
> news:2f9801c374 e6$35387b60$a10 1280a@phx.gbl.. .[color=green]
> >[color=darkred]
> > >-----Original Message-----
> > >Byte barray[] = new Byte[512];
> > >__wchar_t* arr = new __wchar_t[barray->Length];
> > >for(int i=0; i < barray->Length; i++)
> > >arr[i] = barray[i];
> > >delete arr;[/color]
> >
> > How do I further convert to a array declared as char
> > carray[]? The access of a char array through its pointer
> > has taken the wide character into account. i.e., if
> >
> > char *cpp;
> > int n;
> > cpp = carray;
> >
> > (cpp+n) will always point to a valid wide charater (n any
> > int).
> >[/color]
>
>
>[/color]

[Nishant S]

Re: How to convert a Byte array to a char array?

If you have Chinese characters then you cannot use a char array because a
char is only 8 bits. You need to use a Char (System::Char) or a __whcar_t
then.

BTW considering that a Byte is 8 bits I wonder how you can store chinese
characters in a Byte array unless you have a random kinda layout where
depending on whether the character you want to store is unicode or not, you
allot either one byte or two bytes for storing a character. Not a very
organized approach in my opinion.

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:3ba501c374 ff$eb879680$a60 1280a@phx.gbl.. .[color=blue]
>[color=green]
> >-----Original Message-----
> >Byte barray[] = new Byte[512];
> >
> >//char here is 16 bits
> >char smallarray[512];
> >for(int i=0; i<barray->Length; i++)
> > smallarray[i] = barray[i];
> >
> >//Char here is 32 bits
> >Char carray[] = Encoding::ASCII->GetChars(barra y);
> >[/color]
>
> The byte array contains a mixture of
> raw data of Ascii (8-bit) and Chinese characters (16-bit).
> What I need is to convert the byte array into a char array
> so that if I assigned a char pointer to the beginning of
> the char array and I increment the char pointer, it will
> point to a valid wide character which may be 8-bit or 16-
> bit.
>
> Byte barray[512];
> char carray[512];
> char *cpp;
> //convert barray to caaray
> cpp = carray;
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
> printf("%c\n", *cpp); // valid 8-bit or 16-bit character
> *(cpp++);
>
> and so on ....
>
>
>
>[/color]

[Kueishiong Tu]

Re: How to convert a Byte array to a char array?

[color=blue]
>-----Original Message-----
>If you have Chinese characters then you cannot use a[/color]
char array because a[color=blue]
>char is only 8 bits. You need to use a Char[/color]
(System::Char) or a __whcar_t[color=blue]
>then.
>
>BTW considering that a Byte is 8 bits I wonder how you[/color]
can store chinese[color=blue]
>characters in a Byte array unless you have a random[/color]
kinda layout where[color=blue]
>depending on whether the character you want to store is[/color]
unicode or not, you[color=blue]
>allot either one byte or two bytes for storing a[/color]
character. Not a very[color=blue]
>organized approach in my opinion.
>
>--
>Regards,
>Nish [VC++ MVP]
>[/color]

The Byte array I got is from a Webclient::Uplo adData call
which put the data returned in a Byte array (which may
contain both one byte Ascii and two-byte Chinese Big-5
code). VC++ can handle char array which may store both
one-byte ascii and two=byte Big-5 characters. I have
several functions which work fine with this situation.
The problem is how to convert the Byte array to a char
array so I have use a char porinter to decode the message
one character at a time.

[Nishant S]

Re: How to convert a Byte array to a char array?

Hmmm

Okay I think one of the following is what you want :-

//this is to obtain a single byte char array
//might lose chinese characters

char smallarray[512];
for(int i=0; i<barray->Length; i++)
smallarray[i] = barray[i];

//this gets a wide char array
String* tmp = new String(Encoding ::ASCII->GetChars(barra y));
__wchar_t* array = (__wchar_t*)Mar shal::StringToH GlobalUni(
tmp).ToPointer( );
//...
// You can now use array (wide char array)
//...
Marshal::FreeCo TaskMem(array);

I think the second one is what you want. Please try it out and see if it
works for you.

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:30ce01c375 10$c0da14b0$a10 1280a@phx.gbl.. .[color=blue]
>[color=green]
> >-----Original Message-----
> >If you have Chinese characters then you cannot use a[/color]
> char array because a[color=green]
> >char is only 8 bits. You need to use a Char[/color]
> (System::Char) or a __whcar_t[color=green]
> >then.
> >
> >BTW considering that a Byte is 8 bits I wonder how you[/color]
> can store chinese[color=green]
> >characters in a Byte array unless you have a random[/color]
> kinda layout where[color=green]
> >depending on whether the character you want to store is[/color]
> unicode or not, you[color=green]
> >allot either one byte or two bytes for storing a[/color]
> character. Not a very[color=green]
> >organized approach in my opinion.
> >
> >--
> >Regards,
> >Nish [VC++ MVP]
> >[/color]
>
> The Byte array I got is from a Webclient::Uplo adData call
> which put the data returned in a Byte array (which may
> contain both one byte Ascii and two-byte Chinese Big-5
> code). VC++ can handle char array which may store both
> one-byte ascii and two=byte Big-5 characters. I have
> several functions which work fine with this situation.
> The problem is how to convert the Byte array to a char
> array so I have use a char porinter to decode the message
> one character at a time.[/color]

[Nishant S]

Re: How to convert a Byte array to a char array?

System::Char can store both unicode as well as single byte characters.

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:3c5001c375 18$abc316a0$a60 1280a@phx.gbl.. .[color=blue]
>[color=green]
> >-----Original Message-----
> >There was en error in my prev post.
> >
> >char is 8 bits (a byte) and Char is 16 bits (2 bytes)
> >[/color]
>
> Does the 2-byte Char have a fixed length or it can adjust
> to the data depending on what are stored (may be one-byte
> or two-byte)?
> By the way, do you know a convert routine that can
> convert a Byte array to a Big-5 char array (a mixture of
> one-byte and two-byte characers)?
>
> regards,
> Kueishiong Tu[/color]

[Kueishiong Tu]

Re: How to convert a Byte array to a char array?

[color=blue]
>-----Original Message-----
>Hmmm
>
>Okay I think one of the following is what you want :-
>
>//this is to obtain a single byte char array
>//might lose chinese characters
>
>char smallarray[512];
>for(int i=0; i<barray->Length; i++)
> smallarray[i] = barray[i];
>
>//this gets a wide char array
>String* tmp = new String(Encoding ::ASCII->GetChars[/color]
(barray));[color=blue]
>__wchar_t* array = (__wchar_t*)[/color]
Marshal::String ToHGlobalUni([color=blue]
> tmp).ToPointer( );
>//...
>// You can now use array (wide char array)
>//...
>Marshal::FreeC oTaskMem(array) ;
>
>I think the second one is what you want. Please try it[/color]
out and see if it[color=blue]
>works for you.
>
>--
>Regards,
>Nish [VC++ MVP]
>[/color]

The problem I have is that the decoding routine (already
available) expects the input to be a char array instead
of a wide char array. How do I get around this?
Does VC++ .net has the concept of locality so that you
have to set up the locality properly before it will
recognize the local language (something like sun solaris)?
I think this is done implicitly in Microsoft products.

Kueishiong Tu

[Kueishiong Tu]

Re: How to convert a Byte array to a char array?

I have found the solution to my problem. And the solution
is surprising easy. It is

Byte a[100];
char b[100];

for(int i=0; i<a->Length; i++)
{
b[i] = (char) a[i];
}

The resulting char array then works fine for both 1-byte
character and 2-byte character.

[Nishant S]

Re: How to convert a Byte array to a char array?

Considering that a Byte array *cannot* contain 2-byte characters, the last
sentence about how it's fine for both 1-byte and 2-byte characters is a moot
point

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:18a401c382 86$134603d0$a30 1280a@phx.gbl.. .[color=blue]
> I have found the solution to my problem. And the solution
> is surprising easy. It is
>
> Byte a[100];
> char b[100];
>
> for(int i=0; i<a->Length; i++)
> {
> b[i] = (char) a[i];
> }
>
> The resulting char array then works fine for both 1-byte
> character and 2-byte character.[/color]

[Nishant S]

Re: How to convert a Byte array to a char array?

Considering that a Byte array *cannot* contain 2-byte characters, the last
sentence about how it's fine for both 1-byte and 2-byte characters is a moot
point

--
Regards,
Nish [VC++ MVP]



"Kueishiong Tu" <kst001@seed.ne t.tw> wrote in message
news:18a401c382 86$134603d0$a30 1280a@phx.gbl.. .[color=blue]
> I have found the solution to my problem. And the solution
> is surprising easy. It is
>
> Byte a[100];
> char b[100];
>
> for(int i=0; i<a->Length; i++)
> {
> b[i] = (char) a[i];
> }
>
> The resulting char array then works fine for both 1-byte
> character and 2-byte character.[/color]