insert value of a previous table to a new table and update the new table

[learner001]

I have recently started to write server scripts. Although the question may seem to be very basic but i am not able to get a solution.

I have two tables one is PRODUCTS and the other is DEALS.

PRODUCTS TABLE:

Id  product_name  product_desc   category    brand
1   product1      desc1          cat1        brand1                                                     
2   product2      desc2          cat2        brand2

DEALS TABLE

Id     deal_name      productid    
1      todayoffer        2

I wish to put the value of id (from PRODUCTS table) into productid and carry this value to DEALS table and then add deal_name along with it as shown above. The recent code that i am using is

<?
    require_once('config.php'); //connection
    
    $dealname=$_REQUEST['dealname'];
    $productid=$_REQUEST['productid'];
    $productid=$_REQUEST['productid'];
    $id=$_REQUEST['id'];
$inserts = mysql_query("insert into deals (dealname,productid) values ('".$dealname."','".$productid."') SELECT productid FROM products WHERE productid = '".$id."'");
	
$posts[0]['message'] = 'deal Added';
$idd = mysql_insert_id();
$selectt = mysql_query("select * from deals where id = '".$idd."'");
$results =  mysql_fetch_assoc($selectt);
$posts[0]['detail'] = $results;
header('Content-type: application/json');
echo json_encode($posts);
?>

When running the code it is returning false value. would really appreciate some help

[Luuk]

First you should read the warning here
"This extension is deprecated as of PHP 5.5.0, and will be removed in the future. "

Also you should read about SQL Injection, and how to prevent it. Read:
http://stackoverflow.com/questions/6...jection-in-php and Google it....

Secondly, your lines 5 and 6 are the same......?

Now to your question.
You cannot have two SQL statement in one mysql_query

Change line 8 to something like:

$getproductid = mysqlquery("SELECT productid FROM products WHERE productid = '".$id."'");
$productid = mysql_result($getproductid, 0);
$inserts = mysql_query("insert into deals (dealname,productid) values ('".$dealname."','".$productid."');