Adding Program links to Application Menu

[nathj]

Hi,

I've just got a new mini computer running Linux Ubuntu 8.04, and I'm very happy with it.

I've been merrily installing the few bits I want on it and one of those is a SQL editor. I've purchased RazorSQL as it seems to do exactly what I want.

My trouble is that I don't want to have to go into the terminal everytime I load it.

So I've managed to add it to the Applications>>P rogramming menu but when I click on the item I get a blank terminal window - really noting in it and the following message:

There was an error creating the child process for this terminal

So what have I done? Well, knowing that to launch the program in the terminal I typed:

cd programs/razorsql
sh razaorsql.sh

I have created a file that contains the following code:

#! /bin/bash
cd programs/razorsql
sh razaorsql.sh

Then under the menu item properties I have set the following:

Type Application in Terminal
Name RazorSQL
Command /home/ndavies/programs/launchers/razorslq

(that's the file I mentioned above)

With all that in place I click the item on the menu and get the error I mentioned above.

Does anyone know what I've done wrong or what I should do instead of all this? I really do what to have this item accessible from the menu.

Many thanks
Nathan

[ashitpro]

Could you please try with this command...?

"sh razaorsql.sh &" instead of "sh razaorsql.sh".

However, I'm not sure about this...

[Nepomuk]

cd programs/razorsql
sh razaorsql.sh

When you open a terminal, you are automatically in your home directory. So try changing that bash script to

#! /bin/bash
cd /home/nathj/programs/razorsql
sh razaorsql.sh

(if "nathj" is your username)

Also, you can try if the command

/home/nathj/programs/razorsql/razorsql.sh

works from terminal.

Greetings,
Nepomuk

[nathj]

Hi there,

@ asitpro:
I tried that and it made no difference

@Nepomuk:

I have changed the bash script and I still get the same issue. I also tried the script in the terminal - typing it in myself and that worked fine.

If I type in:

sh /home/ndavies/programs/razorsql/razorsql.sh

I get the following message shown in the terminal:

/home/ndavies/programs/razorsql/razorsql.sh: 2: ./jre/bin/java: not found

Any further thoughts?

Cheers
nathj

[Nepomuk]

And how about the command

/home/nathj/programs/razorsql/razorsql.sh

Did you try that? If it works in the terminal, does it work for the bash script?

Greetings,
Nepomuk

[nathj]

And how about the command

/home/nathj/programs/razorsql/razorsql.sh

Did you try that? If it works in the terminal, does it work for the bash script?

Greetings,
Nepomuk

Wow, that was a quick reply.

Here's what works in the terminal:

cd /home/ndavies/programs/razorsql
sh razorsql.sh

That is exactly what I have in the bash script after the initial line and I still get the odd message about creating the child process.

This all really new to me and I really appreciate the help.

nathj

[nathj]

One other thing I should point out, it may be helpful, I don't know.

If I navigate to the razorsql.sh file and click on it I get a message asking me if I want to run it or display it's contents with the options of Run in terminal, display, cancel and run.

thanks again
nathj

[Nepomuk]

One thing that just struck me: You say, you call it with

sh razorsql.sh

Now, as you have

#/bin/bash

in your script, you shouldn't have to do that. Just make that script executable (if you haven't already) with

 chmod +x /home/ndavies/programs/launchers/razorslq.sh

and try to change the script to

#! /bin/bash
cd /home/ndavies/programs/razorsql
./razaorsql.sh

Also, have you tried running your script from terminal?

Greetings,
Nepomuk

[nathj]

Nepomuk,

You are a genius! thank you for helping me out.

Changing the script I wrote to be executable and then amending it as you sad works a treat.

Thank you for helping me out, not only have I got my problem solved I've learnt something along the way,

Cheers
nathj

[Nepomuk]

Glad I could help! :-)

Greetings,
Nepomuk