using shell script

[madhu3437]

help ,please

using shell script
i want know the all process are running or not in a particular path.
the result will shown in web page (html).

process name = running ( server is running)
process name1 = not running( here server is not running)
process name 2 = running ( server is running)

above 3 lines shown in web page.

please help very urgent to me.

[prn]

using shell script
i want know the all process are running or not in a particular path.
the result will shown in web page (html).

process name = running ( server is running)
process name1 = not running( here server is not running)
process name 2 = running ( server is running)

The usual way of determining if a particular process is running is to us ps piped to grep for the process. For example, if you want to determine whether Apache is running, you can do something like:

ps | grep httpd

and get back some number of lines showing all the processes with httpd in them.

Perhaps unfortunately, one process line you are likely to get back will be "grep httpd". :)

So you may want to filter that out with something like

ps -ef | grep -v grep | grep httpd

And this will return only the lines showing actual instances of Apache. Now you are in a position to adapt this to your shell script (presumably being run by the web server---see below) where you just want to return a line saying that apache is or is not running. (You may notice something odd about the particular example I have chosen. :) )

Here, you don't really care about the exact content of the lines, in fact you probably don't want to actually display them. You just want a "count" of the number of lines returned so you know whether there were some or none:

if [ `ps -ef | grep -v grep | grep -c httpd` -gt 0 ] ; then
        echo "<P>apache is running</P>"
        exit
else
        echo "<P>apache is not running</P>"
        exit
fi

Now comes the warning: You need root privileges to look at processes being run by other users and your web server should NOT be running with root privileges. It will usually run either as "www" or as "nobody". So you need to grant LIMITED privs to the user that runs the web server. (I'll assume "www" for this example.) By far the best way to do this is to use sudo. Here is another thread with some discussion of how to go about that.

In this case, (let's assume desdemona is the name of your server) the easiest thing might be to put the actual script (let's call it foo.cgi) for this specific function directly into cgi-bin (which may be /usr/local/apache/share/cgi-bin, for example) and set the privs for it as:

chmod 0744 foo.cgi

so that only root can execute it and then include the lines:

# User privilege specification
root    ALL=(ALL) ALL
www     desdemona=NOPASSWD:/usr/local/apache/share/cgi-bin/foo.cgi

in your /etc/sudoers file.

I know that this is probably more information and less "how-to" than you may have been hoping for, but in fact, it's not quite as simple as dropping in a pre-made script.

HTH,
Paul

[madhu3437]

Thaks very much Paul
one more thing. Below shell script i create all servers are running or not
but i wrote like
i create a file, name of the file is =input_file(in that file put the all servers name)
and run the scripts
getting out put like

SERVER NAME

NETXfnic_uas02_ 31008 = 1
NETXacs2_uas02_ 31011 = 0 (this name AMERICAN CENTURY2)
NETXnetxpress_u as02_31013 = 1 (this name NETXPRESS)
NETXjohnston_ua s02_31035 = 1
NETXemerald_uas 02_31039 = 1
NETXjapan_uas02 _31044 = 1
NETXncbank_uas0 2_31073 = 1
NETXcunamutual_ uas02_31069 = 1
NETXhibernia_ua s02_31081 = 1

but i want OUTPUT like

AMERICAN CENTURY2 NOT RUNNING
NETXPRESS RUNNING

(NETXacs2_uas02 _31011) this is the server name but output like AMERICAN CENTURY2 i want show in the web page


so many servers we have ,so we show the in the web page like
server name = running
server name1 = not running

AMERICAN CENTURY2 NOT RUNNING
NETXPRESS RUNNING

var=`cat input_file`

if [ -f ./out.htm ]
then
rm ./out.htm
fi

for list_of_proc in $var
do
echo $list_of_proc
ps -eaf | grep $list_of_proc >> ./out.htm >&1
done

for list_of_proc in $var
do
flag=`grep "NETXcppSer ver -name $list_of_proc" out.htm|wc -l`

startTag="<html ><head></head><body><h1> "
endTag="</h1></body></html>"
echo "$startTag" "$list_of_p roc" "=" "$flag" "$endTag" >> /u/mkulluru/dev/html/abc.htm
done

please reply me it help and carrier will good for me also

Regards,
Madhu

The usual way of determining if a particular process is running is to us ps piped to grep for the process. For example, if you want to determine whether Apache is running, you can do something like:

ps | grep httpd

and get back some number of lines showing all the processes with httpd in them.

Perhaps unfortunately, one process line you are likely to get back will be "grep httpd". :)

So you may want to filter that out with something like

ps -ef | grep -v grep | grep httpd

And this will return only the lines showing actual instances of Apache. Now you are in a position to adapt this to your shell script (presumably being run by the web server---see below) where you just want to return a line saying that apache is or is not running. (You may notice something odd about the particular example I have chosen. :) )

Here, you don't really care about the exact content of the lines, in fact you probably don't want to actually display them. You just want a "count" of the number of lines returned so you know whether there were some or none:

if [ `ps -ef | grep -v grep | grep -c httpd` -gt 0 ] ; then
        echo "<P>apache is running</P>"
        exit
else
        echo "<P>apache is not running</P>"
        exit
fi

Now comes the warning: You need root privileges to look at processes being run by other users and your web server should NOT be running with root privileges. It will usually run either as "www" or as "nobody". So you need to grant LIMITED privs to the user that runs the web server. (I'll assume "www" for this example.) By far the best way to do this is to use sudo. Here is another thread with some discussion of how to go about that.

In this case, (let's assume desdemona is the name of your server) the easiest thing might be to put the actual script (let's call it foo.cgi) for this specific function directly into cgi-bin (which may be /usr/local/apache/share/cgi-bin, for example) and set the privs for it as:

chmod 0744 foo.cgi

so that only root can execute it and then include the lines:

# User privilege specification
root    ALL=(ALL) ALL
www     desdemona=NOPASSWD:/usr/local/apache/share/cgi-bin/foo.cgi

in your /etc/sudoers file.

I know that this is probably more information and less "how-to" than you may have been hoping for, but in fact, it's not quite as simple as dropping in a pre-made script.

HTH,
Paul

[ghostdog74]

Perhaps unfortunately, one process line you are likely to get back will be "grep httpd". :)

So you may want to filter that out with something like

ps -ef | grep -v grep | grep httpd

And this will return only the lines showing actual instances of Apache.l

don't have to use that many greps, when awk does the job :)

ps -ef| awk '/httpd/'

[prn]

don't have to use that many greps, when awk does the job :)

ps -ef| awk '/httpd/'

Eh?

[root@deimos ~]# ps -ef | grep 'bash'
prn       2915  2912  0  2007 pts/1    00:00:00 bash
root      2949  2944  0  2007 pts/1    00:00:00 -bash
prn      22993 22984  0 Mar07 pts/2    00:00:00 bash
prn      26492 26491  0 12:54 pts/3    00:00:00 -bash
root     26526 26525  0 12:54 pts/3    00:00:00 -bash
root     26581 26526  0 12:57 pts/3    00:00:00 grep bash
[root@deimos ~]# ps -ef | grep -v grep | grep -c bash
5
[root@deimos ~]# ps -ef | awk 'bash'
[root@deimos ~]#

If, in those circumstances, I grep just for "bash", I get back 5 instances plus the grep itself. If I use -v to exclude the "grep" line, I get back the proper count. If I use the awk expression you gave, I am getting back nothing.

I could always use something like:

[root@deimos ~]# ps -ef | awk /bash/
prn       2915  2912  0  2007 pts/1    00:00:00 bash
root      2949  2944  0  2007 pts/1    00:00:00 -bash
prn      22993 22984  0 Mar07 pts/2    00:00:00 bash
prn      26492 26491  0 12:54 pts/3    00:00:00 -bash
root     26526 26525  0 12:54 pts/3    00:00:00 -bash
root     26614 26526  0 13:06 pts/3    00:00:00 awk /bash/

but that is simply equivalent to the case of "ps -ef | grep bash" so I'm not clear on what you mean there.

Paul

[prn]

Thaks very much Paul
one more thing. Below shell script i create all servers are running or not
but i wrote like
i create a file, name of the file is =input_file(in that file put the all servers name)
and run the scripts
getting out put like

Sorry, Madhu. I am having trouble figuring out what you mean. Can you rephrase your question? And please use "code" tags around your code. I'm not clear on what you're getting, what you want and why. Let's try to get one point at a time. It looks like you're trying to ask several questions together and I'm not understanding which is what.

Paul

[ghostdog74]

but that is simply equivalent to the case of "ps -ef | grep bash" so I'm not clear on what you mean there.
Paul

sorry, i did not finish the code...
here's what i meant

# ps -ef | awk '/bash/ && !/awk/'

you don't have to call another grep process just to remove the extra "grep". however, it doesn't matter really..some people have gotten used to grep -v grep. :)

[prn]

Ah! I see now. Yes, that is a bit more elegant. :)

Paul

[madhu3437]

Ah! I see now. Yes, that is a bit more elegant. :)

Paul

we have 40 sites each site haveing webserver setup and application servers.
and also we need to find out the each site webserver and application servers is running or not in a particular machine.

if 40 sites are running or not running show in the html page.

These input_file have the 40 sites name


var=`cat input_file`

if [ -f ./out.htm ]
then
rm ./out.htm
fi

for list_of_proc in $var
do
echo $list_of_proc
ps -eaf | grep $list_of_proc >> ./out.htm >&1
done
for list_of_proc in $var
do
flag=`grep "NETXcppSer ver -name $list_of_proc" out.htm|wc -l`
startTag="<html ><head></head><body><h1> "
endTag="</h1></body></html>"
echo "$startTag" "$list_of_p roc" "=" "$flag" "$endTag" >> /u/mkulluru/dev/html/abc.htm
done



i am getting out

Republic = 1
TRP = 0
(here 1 mean is running)
(here 0 mean is not running)


but i want put like

Republic = running
TRP = Not running

how can write the in the script , please on this it is very use full to me.

Thanks & Regards
Madhusudhana gupta kulluru

[madhu3437]

i giving full details,

we have machines a,b,c,d
in each machine application servers are running
but each machine have 40 application server are running
result of 40 application servers are running or not shown in the web page.


but i am in z machine
when run the script (http://172.30.98.91:/cgi/health.ksh) in web page
Result will show in the web page .

Resultant in web page


Server a machine b machine c machine d machine
--------------------------------------------------------------------------------------------
trowe running running running running
republic running not running running running
universal not running
. ,
.
. ,
.
.
acs running running running running


it very help full greate becaues i am trouble .please help

Thanks & Regards,
Madhusudhana gutpa kulluru

we have 40 sites each site haveing webserver setup and application servers.
and also we need to find out the each site webserver and application servers is running or not in a particular machine.

if 40 sites are running or not running show in the html page.

These input_file have the 40 sites name


var=`cat input_file`

if [ -f ./out.htm ]
then
rm ./out.htm
fi

for list_of_proc in $var
do
echo $list_of_proc
ps -eaf | grep $list_of_proc >> ./out.htm >&1
done
for list_of_proc in $var
do
flag=`grep "NETXcppSer ver -name $list_of_proc" out.htm|wc -l`
startTag="<html ><head></head><body><h1> "
endTag="</h1></body></html>"
echo "$startTag" "$list_of_p roc" "=" "$flag" "$endTag" >> /u/mkulluru/dev/html/abc.htm
done



i am getting out

Republic = 1
TRP = 0
(here 1 mean is running)
(here 0 mean is not running)


but i want put like

Republic = running
TRP = Not running

how can write the in the script , please on this it is very use full to me.

Thanks & Regards
Madhusudhana gupta kulluru