What is wrong with my shell script ?

[Mmanjul]

When I try to run my script(check.sh ) I get the following message:

./check.sh[3]: test: argument expected

What does the above message mean ? I have used the arguments while trying to run this.Following is the contents of the script:

1 #! /usr/bin/ksh
2
3 while [ "$1" != ""] ;
4 do
5 echo "Enter the name of the directory :"
6 read dirname
7 ls $dirname
8
9 echo "Press a key ..."
10 read
11 exit 0
12 done ;
13
14

[Motoma]

I don't have ksh installed on my machine, but when I ran this with bash, it worked fine. Try changing the shell to /bin/bash and see if it works for you too.

[horace1]

there appear to be a space missing before the ] in

     3  while [ "$1" != ""] ;

[Varun Gupta]

ya there is a space expected just before ]

and what you are trying to do with "exit 0" within the while loop, without some condition. Does it work as you desire. ?