Pass variable into PHP via JAax

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  • nareh
    New Member
    • Nov 2014
    • 1

    Pass variable into PHP via JAax

    Code:
    <?php
    include('header.php'); 
    		require_once('/homepages/9/d322999378/htdocs/spaincoastrealty/wordpress_en/wp-admin/includes/image.php');
            require_once("/homepages/9/d322999378/htdocs/spaincoastrealty/wordpress_en/wp-load.php");
    		global $wpdb;
            global $posts;
    ?> <form id = "test" method = "post"> <div> <div class="control-group"> <label class="control-label" for="selectError">Site</label> <div class="controls"> <select name="sitechooser" id="sitechooser"> <option value="Site1" selected>Site1</option> <option value="Site2">Site2</option> </select> </div> </div> </div> <input type = "text" id = "site_value" value = "some text"> </form> <script>
    		$(document).ready(function (e) {
    			
                    $('#sitechooser').change(function () {
                        var selected = $("#sitechooser option:selected").text();
                        if (selected == "Site1") {
    	
    						var id = $('#site_value').val();
    						$.ajax({
    								url: 'try.php',
    								dataType: 'JSON',
    								data: {id: id},
    								success: function(data){
    									alert(data);
    									id = data.id;
    									$('#id').text(id);
    							}
    						});
                        } 
    				
    				});
    		});		
    		</script> <?php
    	
    		echo "id = ".$id;
    		
    		?>
    I want to get id value in php $id variable.

    Is something wrong in my code? THanks
    Last edited by Dormilich; Nov 22 '14, 09:18 PM. Reason: please use code tags
  • Dormilich
    Recognized Expert Expert
    • Aug 2008
    • 8694

    #2
    $_GET["id"] .

    Comment

    Working...