using an array's extended properties in jQuery

[svendok]

What does one have to do in the code below to allow jQuery to make use of the find() function that I added to the array object (see line #26)?

Is there a namespace clash?

The code is here http://jsbin.com/oluyu6/5/edit

Thanks.

  Array.prototype.find = function(searchStr) {  
     // http://www.hunlock.com/blogs/Mastering_Javascript_Arrays#quickIDX39
     var returnArray = false;  
     for (i=0; i<this.length; i++) {
             if (typeof(searchStr) == 'function') {
                 if (searchStr.test(this[i])) {
                     if (!returnArray) {     returnArray = [];  }
                     returnArray.push(i);      
                 }    
             } else {
               if (this[i]===searchStr) {
                   if (!returnArray) { returnArray = []; }
                 returnArray.push(i);      
             }    
         }  
     }  
     return returnArray;
 };

function toggleArrowBySelectedVal(option_array, list_id, arrow)
{
  var list=$("#"+list_id);
  
  var numselected=$("#"+list_id+" option:selected").length;
  if ( (numselected==1)   &&
     (option_array.find(Number(list.value))))  arrow.disabled=false;
  else                      arrow.disabled=true;
  
}

[Dormilich]

list.value is undefined, because list is a jQuery instance and not a <select>.

besides that you have a logic error (line #6), if searchStr is a function, searchStr.test( ) will throw an error (undefined method call). functions only have the methods apply(), bind(), call() & toString().