Behaviour of string.split()

[Steve]

I understand that string.split() should produce an array from a
string. However when I use the following script the type of the result
is indeed an object but the array elements are undefined. Why?

var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);

Thanks in advance.

[Henry]

Re: Behaviour of string.split()

On Aug 13, 11:59 am, Steve wrote:

I understand that string.split() should produce an
array from a string. However when I use the
following script the type of the result is indeed
an object but the array elements are undefined. Why?
>
var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);

If you do not provide the first ("Separator" ) argument to -
String.prototyp e.split - it will return a one element array with first
(zero index) element containing a string that is equivalent to the
original string. Thus - arryTest[2] - would be expected to result in
the undefined value as the - length - of - arrayTest - will be one and
its only existing 'array index' property is '0'.

[virtuPIC]

Re: Behaviour of string.split()

var strTest = '1,2,3,4';

var aryTest = strTest.split() ;
alert(typeof aryTest + "  " + aryTest[2]);

Hey, you didn't tell your JavaScript VM where to split! Try this:

var strTest = '1,2,3,4';
var aryTest = strTest.split(' ,');
alert(typeof aryTest + " " + aryTest[2]);

Looks better?

virtuPIC

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[Steve]

Re: Behaviour of string.split()

On Aug 13, 1:26 pm, virtuPIC <WebMas...@airs pace-v.comwrote:

var strTest = '1,2,3,4';
var aryTest = strTest.split() ;
alert(typeof aryTest + " " + aryTest[2]);

>
Hey, you didn't tell your JavaScript VM where to split! Try this:
>
var strTest = '1,2,3,4';
var aryTest = strTest.split(' ,');
alert(typeof aryTest + " " + aryTest[2]);
>
Looks better?
>

Yes it does.

However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.

Many Thanks,

Steve.

[Gregor Kofler]

Re: Behaviour of string.split()

Steve meinte:

On Aug 13, 1:26 pm, virtuPIC <WebMas...@airs pace-v.comwrote:

>>var strTest = '1,2,3,4';
>>var aryTest = strTest.split() ;
>>alert(typeo f aryTest + " " + aryTest[2]);

>Hey, you didn't tell your JavaScript VM where to split! Try this:
>>
>var strTest = '1,2,3,4';
>var aryTest = strTest.split(' ,');
>alert(typeof aryTest + " " + aryTest[2]);
>>
>Looks better?
>>

Yes it does.
>
However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.

Read again. Mozilla doesn't state a "default separator". Instead
"If separator is omitted, the array returned contains one element
consisting of the entire string." [1]
I suppose other ECMAScript derivates behave equally.

Gregor


[1]
<http://developer.mozil la.org/en/docs/Core_JavaScript _1.5_Reference: Objects:String: split>

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[Peter Billam]

Re: Behaviour of string.split()

On 2008-08-13, Gregor Kofler <usenet@gregork ofler.atwrote:

Steve meinte:

However according to the material I have read, including the Rhino,
the comma is the default. But I should have thought of that anyway.

>
Read again. Mozilla doesn't state a "default separator". Instead
"If separator is omitted, the array returned contains one element
consisting of the entire string." [1]
I suppose other ECMAScript derivates behave equally.

Probably the OP is thinking of the inverse operation, Array.join()
where Flanagan's O'Reilly book says "if the argument is omitted,
a comma is used."

Regards, Peter Billam

--
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