http_request failing between sites

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  • empiresolutions
    New Member
    • Apr 2006
    • 162

    http_request failing between sites

    im trying to call a page on "Server B" from "Server A" using http_request method. the problem is the request fails at http_request.op en(). Below is the very basic code im using that can be found everywhere online.

    Code Calling from a page on Server (site) A. Requesting URL is on Server (site) B
    Code:
    makeRequest('http://www.sitename.com/ajax_insert.php?field_name=test&field_value=',this.value);
    This is the code in the makeRequest() function which is on Server (site) A.
    Code:
    function makeRequest(url, parameters) {
    
    	http_request = false;
    	if (window.ActiveXObject) { // IE
    		try {
    			http_request = new ActiveXObject("Msxml2.XMLHTTP");
    		} catch (e) {
    			try {
    				http_request = new ActiveXObject("Microsoft.XMLHTTP");
    			} catch (e) {}
    		}
    	} else if (window.XMLHttpRequest) {// Mozilla, Safari,...xmlHttpReq.overrideMimeType
    		http_request = new XMLHttpRequest();
    		if (http_request.overrideMimeType) {
    			// set type accordingly to anticipated content type
    			http_request.overrideMimeType('text/xml');
    		}else{ alert('Did not create *http_request.overrideMimeType*'); return false; }
    	} 
    
    	if (!http_request) {
    
    		alert('Cannot create XMLHTTP instance');
    		return false;
    
    	}
    
    	http_request.onreadystatechange = alertContents;
    
    	// FOR GET VARS
    	http_request.open('GET', url + parameters, true);
    	http_request.send(null);
    	
    }
    So what am i missing? How can i get the http_request to process a page on another server (site). FYI, outside this application, my code as written works fine.

    Thank you much for all the help.
  • rnd me
    Recognized Expert Contributor
    • Jun 2007
    • 427

    #2
    you can't. it's not allowed.

    Comment

    • gits
      Recognized Expert Moderator Expert
      • May 2007
      • 5390

      #3
      that's right ... you may have a look here too ...

      kind regards

      Comment

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