replace "&" by its URL symbol "%26"

[vigi98]

Hello all,

Can someone confirme that this:
var strURLpiece = "UK & Ireland";
strURLpiece.rep lace("&", "%26");
replaces all occurrence of the character & by %26 in strURLpiece, ie
that strURLpiece becomes "UK %26 Ireland" ?

Thanks a lot.

[Richard Cornford]

Re: replace "&&quo t; by its URL symbol "%26&qu ot;

"vigi98" <vigi98@free.fr > wrote in message
news:c1df2002.0 402191107.dfbbd 70@posting.goog le.com...[color=blue]
> Can someone confirme that this:
> var strURLpiece = "UK & Ireland";
> strURLpiece.rep lace("&", "%26");
>replaces all occurrence of the character & by %26 in
>strURLpiece, ie that strURLpiece becomes "UK %26 Ireland" ?[/color]

If anyone does then don't trust them because it won't.

Richard.

[vigi98]

Re: replace &quot;&amp;&quo t; by its URL symbol &quot;%26&qu ot;

> If anyone does then don't trust them because it won't.[color=blue]
>
> Richard.[/color]

Thanks for this very helpfull solution. Nevertheless, what is the
solution ? I also tried this:
strURLpiece.rep lace(/&/,"%26");
but it does not work better.

[optimistx]

Re: replace &quot;&amp;&quo t; by its URL symbol &quot;%26&qu ot;

vigi98 wrote:[color=blue][color=green]
>>If anyone does then don't trust them because it won't.
>>
>>Richard.[/color]
>
>
> Thanks for this very helpfull solution. Nevertheless, what is the
> solution ? I also tried this:
> strURLpiece.rep lace(/&/,"%26");
> but it does not work better.[/color]
This worked in ie 6.0 and mozilla 1.6:

alert("UK & Ireland".replac e(/[&]/g,"%26"));

RegExp is for me so tricky to use that I made a small testbed to have
exercises in using it:

function evaluoi(r,s){
var re=new RegExp(r);
var myArray=new Array();
if (re){
myArray=re.exec (s);
if (myArray){alert (myArray.length +'\n'+myArray+' \n'+re.source); }
return re.test(s) ;
}
return false;
}




<form name="fname" action="#" method="get">
RegExp=
<input name="r" type="text" value="(\d{5})([a-z]*)(\s)+(\*$)">< br>
string=
<input name="s" type="text" value="12345abc *"><br>
RegExp.test(str ing)=
<input name="a" type="text" value="?"><br>
<input type="button" value="evaluoi"
onclick="docume nt.forms['fname'].a.value=evaluo i(document.form s['fname'].r.value,docume nt.forms['fname'].s.value);">
</form>

You can ignore the initial example values in the form fields.

Note that typing expressions to a form is different from using the
expressions in the progrmam code.

[Evertjan.]

Re: replace &quot;&amp;&quo t; by its URL symbol &quot;%26&qu ot;

optimistx wrote on 20 feb 2004 in comp.lang.javas cript:
[color=blue]
> alert("UK & Ireland".replac e(/[&]/g,"%26"));
>[/color]

Without the [] works as well:

alert("UK & Ireland &cetera".replac e(/&/g,"%26"));

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

[Lasse Reichstein Nielsen]

Re: replace &quot;&amp;&quo t; by its URL symbol &quot;%26&qu ot;

vigi98@free.fr (vigi98) writes:
[color=blue]
> Thanks for this very helpfull solution. Nevertheless, what is the
> solution ? I also tried this:
> strURLpiece.rep lace(/&/,"%26");
> but it does not work better.[/color]

You wanted the value of strURLpiece to change. For that you need an
assignment. The replace method does not change the string. So, at least;

strURLpiece = strURLpiece.rep lace(/&/,"%26");

The next problem is the "&". If the script is embedded in HTML, the
ampersand has a special meaning, and should be (HTML-)escaped:

strURLpiece = strURLpiece.rep lace(/&amp;/,"%26");

If the script is not embedded in Javascript, then you should not escape
the ampersand. If you want to avoid thinking about it, you can use a
Javascript escape:

strURLpiece = strURLpiece.rep lace(/\x26/,"%26");

Good luck.
/L
--
Lasse Reichstein Nielsen - lrn@hotpop.com
DHTML Death Colors: <URL:http://www.infimum.dk/HTML/rasterTriangleD OM.html>
'Faith without judgement merely degrades the spirit divine.'

[Dr John Stockton]

Re: replace &quot;&amp;&quo t; by its URL symbol &quot;%26&qu ot;

JRS: In article <c1df2002.04021 91107.dfbbd70@p osting.google.c om>, seen
in news:comp.lang. javascript, vigi98 <vigi98@free.fr > posted at Thu, 19
Feb 2004 11:07:16 :-
[color=blue]
>Can someone confirme that this:
> var strURLpiece = "UK & Ireland";
> strURLpiece.rep lace("&", "%26");
>replaces all occurrence of the character & by %26 in strURLpiece, ie
>that strURLpiece becomes "UK %26 Ireland" ?[/color]

It appears to replace all ampersands in "UK & Ireland".
It only replaces the first ampersand in "&&" & " & & "

--
© John Stockton, Surrey, UK. ?@merlyn.demon. co.uk Turnpike v4.00 IE 4 ©
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