Dynamically change an image based on document.URL

[ccountey]

Hello,


The objective of this script is to show visitors who found my site by clicking on one of our Google Adwords a specific telephone number (in graphic form) for the sake of tracking.


Here is the code I have been working on. My issue lies within the document.URL area of the script. I tried this code without declaring the source variable, but the script would redirect me to the document.URL declaration.


After running this code on a test page, it now displays the first image in the series, but should be showing the second image as the page I am viewing it on does not have the URL tied to it.






<script language = “javascript” type=”text/javascript”>
[code=javascript]


function adWords()



{



source=document .URL <!-- If I eliminate this declaration and just use document.URL in the IF statement, the page gets redirected to that URL



if(source="http ://www.appletreean swers.com/index.html") {



document.write( "<IMG SRC='/normalimage.jpg '>")



}else{



document.write( "<IMG SRC='/adwordimage.jpg '>")



}



}



[/CODE]-->

</script>





<script language="javas cript" type="text/javascript">



adWords();



</script>


Thanks!

[poe]

The reason the page gets redirected is because your if statement is making an assignment instead of a comparison.

What you have: blah = blah2

What you need: blah == blah2

With what you have, as soon as you assign document.URL to something, the page location changes.

[ccountey]

The reason the page gets redirected is because your if statement is making an assignment instead of a comparison.

What you have: blah = blah2

What you need: blah == blah2

With what you have, as soon as you assign document.URL to something, the page location changes.

Thanks, I am very new at JS, so I appreciate you taking the time to answer a simple question.

Chris

[acoder]

Just a note: document.URL is read-only or, at least, should be. IE lets you set it.

For cross-browser functionality, if you ever need to change the URL, use location.href.